RE: [PHP-DB] % operator

2003-08-14 Thread Matthew Moldvan
to do with databases. :) Regards, Matt. -Original Message- From: Andrew D. Luebke [mailto:[EMAIL PROTECTED] Sent: Tuesday, August 12, 2003 3:04 PM To: 'Alain Barthélemy'; php-db Subject: RE: [PHP-DB] % operator Although now that I look at: http://us4.php.net/manual/en

RE: [PHP-DB] % operator

2003-08-14 Thread Matthew Moldvan
There's probably a better way to do this, but to retrieve only the 0.8 from 24/5 try this: ($a/$b)-floor($a/$b) Regards, Matt. -Original Message- From: Alain Barthélemy [mailto:[EMAIL PROTECTED] Sent: Tuesday, August 12, 2003 5:05 AM To: php-db Subject: [PHP-DB] % operator Hello

Re: [PHP-DB] % operator

2003-08-14 Thread Phil Driscoll
On Tuesday 12 August 2003 10:39 am, Phil Driscoll wrote: The modulus is the remainder after division hence 5 into 24 goes 3 times with a remainder of 4, oops - 4 times with a remainder of 4 :( -- Phil Driscoll -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit:

RE: [PHP-DB] % operator

2003-08-14 Thread Andrew D. Luebke
. -Original Message- From: Alain Barthélemy [mailto:[EMAIL PROTECTED] Sent: Tuesday, August 12, 2003 5:05 AM To: php-db Subject: [PHP-DB] % operator Hello, If you have $a = 24; $b = 5; and $c = $a/$b; === $c = 4.8 To retrieve the .8 (reste in french) I saw instruction: $a%$b Where can I find

Re: [PHP-DB] % operator

2003-08-14 Thread Doug Thompson
The % is called the Modulus operator. It is very briefly explained in the PHP manual in table 11-2. In your example, $mod = $a % $b == $mod = 0.8 It is a very easy operator to use. Doug On Tue, 12 Aug 2003 11:04:39 +0200, Alain Barthélemy wrote: Hello, If you have $a = 24; $b = 5; and

RE: [PHP-DB] % operator

2003-08-14 Thread Andrew D. Luebke
try this: ($a/$b)-floor($a/$b) Regards, Matt. -Original Message- From: Alain Barthélemy [mailto:[EMAIL PROTECTED] Sent: Tuesday, August 12, 2003 5:05 AM To: php-db Subject: [PHP-DB] % operator Hello, If you have $a = 24; $b = 5; and $c = $a/$b; === $c = 4.8 To retrieve the .8 (reste

Re: [PHP-DB] % operator

2003-08-14 Thread Phil Driscoll
On Tuesday 12 August 2003 10:27 am, Doug Thompson wrote: The % is called the Modulus operator. It is very briefly explained in the PHP manual in table 11-2. In your example, $mod = $a % $b == $mod = 0.8 The modulus is the remainder after division hence 5 into 24 goes 3 times with a

[PHP-DB] % operator

2003-08-14 Thread Alain Barthlemy
Hello, If you have $a = 24; $b = 5; and $c = $a/$b; === $c = 4.8 To retrieve the .8 (reste in french) I saw instruction: $a%$b Where can I find a manual for this '%' operator? Of course I already looked in all the Php manuals (operators, etc ...). Thanks, -- Alain Barthélemy [EMAIL

Re: [PHP-DB] % operator

2003-08-12 Thread Doug Thompson
One day I'll learn to wait until two cups of coffee before attempting to post replies. On top of which, I have no idea where 0.8 came from. 8-/ Sorry for the confusion factor. Doug On Tue, 12 Aug 2003 10:47:21 +0100, Phil Driscoll wrote: On Tuesday 12 August 2003 10:39 am, Phil Driscoll