subject:"\[PHP\-DB\] Eval statement"

Re: [PHP-DB] Eval statement

2001-04-09 Thread John

Hello, Eval must be a statement, not an expression. eval("\$result=$number1+$number2;"); print $result; John ""Bartek Pawlik"" <[EMAIL PROTECTED]> wrote in message 003101c0c0d6$48546a40$539f4dd5@administrator">news:003101c0c0d6$48546a40$539f4dd5@administrator... Hi, Sorry, but it's no

[PHP-DB] Eval statement

2001-04-09 Thread Bartek Pawlik

Hi, Sorry, but it's no connected with PHP+DB, but I can't find answer enywhere Supouse I have $number=123; what i want is eval ("$kg"+$number) and print it. PS. $number takes different values; Thanks in advance Bartek Pawlik Poland --