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On 01 November 2004 05:01, Doug Thompson wrote:
> The variables are not being expanded. As a minimum, you need to
> escape the single quotes. $query = "SELECT * from user where
>
The variables are not being expanded. As a minimum, you need to escape the single quotes.
$query = "SELECT * from user where name=\'$userid\' and
pass=password(\'$password\')"
Alternatively, you can concatenate the expanded variables.
$query = "SELECT * from user where name='".$userid."' and
p
IL PROTECTED]>
Reply-To: "Arne Essa Madsen" <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Problems with mysql_num-rows()
Date: Sun, 31 Oct 2004 19:32:09 +0100
I have the following problem:
This one does not work:
$query = "SELECT * from user where name='
On Sunday 31 October 2004 18:32, Arne Essa Madsen wrote:
> I have the following problem:
>
> This one does not work:
> $query = "SELECT * from user where name='$userid' and
> pass=password('$password')";
print $query;
> $result = mysql_query($query, $link);
Use mysql_error().
--
Jason Wong
I have the following problem:
This one does not work:
$query = "SELECT * from user where name='$userid' and
pass=password('$password')";
$result = mysql_query($query, $link);
$num_rows = mysql_num_rows($result);
I get this error message:
Warning: mysql_num_rows(): supplied argument is not a
