>"Vincent Jordan" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
>Could someone instruct me or point me in the right direction. I would like
to have a <input type=password name=password> ><input type=password
name=password2> when submit it will check to se if password and password2
are = ( i do not want >password2 to end up in POST on submit.)
>
>also i am trying to rewrite data from a tinyint. the tinyint will return 1
or 0, I have tried but can not seem to get it >right. pretty much if it
returns 1 i want display active where if 0 display not active. I have tried
the following:
>
>$act = mysql_query("select isactive from acl where isactive '1'")
I think you missed the = on the above line. This should be the correct
syntax:
$act = mysql_query("select isactive from acl where isactive = 1");
>if ($act)
>{
>while ($isact = mysql_fetch_array($act))
>{
>echo "Active";
>}
>}
>else
>{
>echo "Not Active";
>}
>
>i have also tried:
>
>if $row[isactive] = '1'
The above should be:
if ($row['isactive'] == 1)
>{
>echo "active";
>}
>else
>{
>echo "Not Active";
>}
>
>im suue i have screwed up the syntax somewhere. I have looked on google and
picked thru several scripts i have found >online but have been unsuccessful.
aly help appriciated.
>
>Vinny
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