[PHP-DB] Re: Help with array

2003-02-16 Thread John Thorne
$cpt=0; $rownu =1; while($row = mysql_fetch_row($result)) { $data[$cpt][0] = $rownu; $data[$cpt][1] = $row[0]; $data[$cpt][2] = $row[1]; $data[$cpt][3] = $row[2]; $rownu++; $cpt++; This worked perfectly Fredrik.. thank you jrt "Fredrik De Vibe" <[EMA

[PHP-DB] Re: Help with array

2003-02-16 Thread Fredrik de Vibe
[EMAIL PROTECTED] (John Thorne) writes: [ snip ] > $data[$cpt]= > $rownu.","."\"".$row[0]."\"".",\"".$row[1]."\","."\"".$row[2]."\""; This is a string, not an array. > Could you go a step farther in the $foo[$i][$j] please $data[$cpt][0] = $rownu; $data[$cpt][1] = $row[0]; $data[$cpt][2] = $

[PHP-DB] Re: Help with array

2003-02-16 Thread John Thorne
Thanks for the reply I do not under stand how to apply your example $foo[$i][$j] = "bar"; Graph example array trying to create thru sql: $data = array( array(0,"Concept","2002-9-1","2002-9-15",blue), array(1,"Creative","2002-9-15","2002-9-30",red), array(2,"Produce","2002-9-31","2002-10-10",green

[PHP-DB] Re: Help with array

2003-02-16 Thread Fredrik de Vibe
[EMAIL PROTECTED] (John Thorne) writes: > $data[$cpt]= $row[0].",".$row[1].",".$row[2].",".$row[3].",".$row[4]; What you need is a two dimensional array. The code above concatenates the $row elements into a string and puts this string into a one dimensional array. the 2D array $foo[3][5] can be s