For those that are curious, here's the working query:
SELECT options. * , count( option_items.optionID ) AS n
FROM options
LEFT JOIN option_links
USING ( optionID )
LEFT JOIN option_items ON options.optionID = option_items.optionID
WHERE option_links.productID = '$productID'
GROUP BY options.optio
Sorry, I'm wrong..
WHERE cannot refer to aggregate columns.. you must use the HAVING clause.
-Micah
On Wednesday 14 July 2004 12:07, Micah Stevens wrote:
> It is a column.. ;)
>
> And the docs say you can refer to an aliased aggregate column in the where
> clause:
>
> http://dev.mysql.com/do
It is a column.. ;)
And the docs say you can refer to an aliased aggregate column in the where
clause:
http://dev.mysql.com/doc/mysql/en/SELECT.html
I'll take this to the mysql list.. Thanks for your help..
-Micah
On Wednesday 14 July 2004 12:01, Torsten Roehr wrote:
> "Micah Stevens" <[EMAI
"Micah Stevens" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Thank you Torsten ,
>
> They're backticks, and I get the same error after removing them.
>
> Any other ideas?
Then I guess you can't use num in your WHERE clause - MySQL thinks it's a
column.
Torsten
>
>
> -Micah
>
>
>
Thank you Torsten ,
They're backticks, and I get the same error after removing them.
Any other ideas?
-Micah
On Wednesday 14 July 2004 11:48, Torsten Roehr wrote:
> "Micah Stevens" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
>
> > Hi,
> >
> > I'm getting an unknown colum `
"Micah Stevens" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
>
> I'm getting an unknown colum `num` in where clause error with this query:
>
> $options = mysql_query("select options.*,
> count(option_items.optionID) as `num`
> from options
> left join option_links using (
