FW: [PHP-DB] Variable Variables in PHP

2001-06-29 Thread Jonathan Hilgeman
Below is my reply to Morgan the other day. -Original Message- From: Jonathan Hilgeman Sent: Wednesday, June 27, 2001 8:36 AM To: 'Morgan Tocker' Cc: '[EMAIL PROTECTED]' Subject: RE: [PHP-DB] Variable Variables in PHP Try changing your inputs to: PRINT ""

RE: [PHP-DB] Variable Variables in PHP

2001-06-27 Thread Jonathan Hilgeman
me is $name and my e-mail is " . $email_array[$id] . ""; } - Jonathan -Original Message- From: Morgan Tocker [mailto:[EMAIL PROTECTED]] Sent: Tuesday, June 26, 2001 7:04 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] Variable Variables in PHP I am having trouble with vari

Re: [PHP-DB] Variable Variables in PHP

2001-06-27 Thread Jason Stechschulte
On Wed, Jun 27, 2001 at 12:03:42PM +1000, Morgan Tocker wrote: > ## THIS SHOULD SUBMIT SOMETHING LIKE THIS > > test.php?name1=avalue&email1=avalueagain&name2=secondname&email2=secondemail > > THE PROBLEM: > From PHP with variable variables, how do I change $name1 and $email1 into - > > ##

RE: [PHP-DB] Variable Variables in PHP

2001-06-27 Thread Taylor, Stewart
;,email = '%s' ". "WHERE ". "id = '%s'", $v, $email[$k], $k); // run query etc.. } -Original Message----- From: Morgan Tocker [mailto:[EMAIL PROTECTED]] Sent: 27 June 2001 03:04 To: [EMAIL PROTECTED] Subject: [PHP-

[PHP-DB] Variable Variables in PHP

2001-06-27 Thread Morgan Tocker
I am having trouble with variable variables; I want to create a form as follows :- "; WHILE ($i < $num) { $name = mysql_result($result,$i,name); $email = mysql_result($result,$i,email); $id = mysql_result($result,$i,id); PRINT ""; PRINT "";