Hi,
I have a code that goes like this. Scroll down to the --
sign. How come I need another $result = mysql_query($sql) at that location?
If I don't have it, the results coming out will only start printing from the
2nd Row.. Omitting the 1st.
Results as wanted
row 1
Because you have already fetched one row before outputting the record
count. Therefore the row pointer is at the second record before you 'print
out'.
Try putting
mysql_data_seek($result,0);
in place of your second
$result = mysql_query($sql);
This should return the pointer to the first
/M Engineering
Western Digital M'sia
DID : 03-7870 5168
-Original Message-
From: Terry Riley [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 22, 2003 7:33 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] WHY need to query 2x to get results
Because you have already fetched one row before
