[snip]
That does not work either... I can not make the statement fail!!!
I have tried
$password = "123456";
and
$password = "abcdef";
I have change the if statement to what is below and past in all letters
and
it still works?
if (preg_match ('/\d/', $password)) {
die ("You must have a numb
you only want to check to see if there is at least one digit?
If that is true, this should work:
if(preg_match('/\d/',$password)) {
echo 'password ok';
}
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hat there is at least 1 number in the password ?
// Larry
-Original Message-
From: Matthias Steinböck [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 24, 2004 1:41 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] regular expression help
hi!
is this correct: you want to check if there are
ok... this still does not do what you want, because it does not consider
that only digits should be between the letters... here is the correct
solution:
// dies
$password = 'alfgoesswimming';
// dies too
$password = 'a2lf4g2o4e7s9s3w9i0m5m7i0n3g';
// survives
$password = 'a2$5l5f4g2o4e7s9s3w9i0
hi!
is this correct: you want to check if there are two letters in the
password wich do not surround a digit? if so this is what you need:
// dies
$password = 'alfgoesswimming';
// dies too
$password = 'a2lf4g2o4e7s9s3w9i0m5m7i0n3g';
// survives
$password = 'a2l5f4g2o4e7s9s3w9i0m5m7i0n3g';
$foun
die ("You must have a number between 2 letters in your password ...
0-9");
// Larry
-Original Message-
From: Matt Matijevich [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 24, 2004 12:11 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] regular expression hel
try this
$password = 'abcdef';
if (preg_match ('/\w\d\w/', $password)) {
die ("You must have a number between 2 letters in your password ...
0-9");
}
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The *if* statement should fail with the password abcdef being qualified but
it never fails ?
If I understand the expression right, it should have at 1 number in it
between 2 letters ?
$password = abcdef;
if (preg_match ("/[A-z]+[0-9]+[A-z]+/", $password)) {
die ("You must have a n
