; From: Patrik Fomin [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, July 22, 2003 4:41 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] silly problem
>
>
>
> $sql = "UPDATE dagensfraga SET nej = '$nej' WHERE id = '$iid' AND
> aktuellfraga = '1
you are missing the $ sign on your second mysql_query call
-Original Message-
From: Patrik Fomin [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 22, 2003 4:41 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] silly problem
$sql = "UPDATE dagensfraga SET nej = '$nej' WHERE
Typo in your second query call. Should be:
mysql_query($sql);
Rich
> -Original Message-
> From: Patrik Fomin [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, July 22, 2003 4:41 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] silly problem
>
>
>
> $sql = "UP
Because you forgot a $ before $sql in the second?
Regards,
Matthew Moldvan
System Administrator
Trilogy International, Inc.
-Original Message-
From: Patrik Fomin [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 22, 2003 4:41 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] silly problem
$sql = "UPDATE dagensfraga SET nej = '$nej' WHERE id = '$iid' AND
aktuellfraga = '1'";
mysql_query($sql);
$sql = "INSERT INTO dagensfragaip (aid, ip) VALUES('$iid',
'$REMOTE_ADDR')";
mysql_query(sql);
when i run this only the first line is recorded into the databse?,
when i run the second l
