Try putting the hidden element statement down inside the while loop in he
second page, but change it to "" and add
$id=$row['id'];
before it.
I will show below where it should go.
HTH
MB
jas <[EMAIL PROTECTED]> said:
> I have made the changes you suggested which if you ask me have been
I have made the changes you suggested which if you ask me have been the most
informative answers I have recieved thus far. I did run into a slight snag
on line 21 which is this on my confirmation page "" and the parse error is as follows...
Parse error: parse error, expecting `STRING' or `NUM_STR
Ok, you have almost got it. I have made little remarks further down in your
code which should just about do it for you.
jas <[EMAIL PROTECTED]> said:
> I don't know what it is but I am having a hell of a time trying to get some
> results of a query setup into an array or variable (too much of
Well ok now that I know it isn't an array I am having problems with, how
exactly am I supposed to create a variable (that can be passed to another
page) from a selected set of records?
Thanks again for the politeness,
Jas
"Spyproductions Support Team" <[EMAIL PROTECTED]> wrote in message
[EMAIL PR
That's not Array Hell, this is Array Hell:
$Hell = array("satan","fire","brimstone");
-Mike
> -Original Message-
> From: jas [mailto:[EMAIL PROTECTED]]
> Sent: Friday, February 22, 2002 4:37 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] Array HELL
>
>
> I don't know what it is bu
