Well, you're initializing $food to ""; then testing to see if it has a value, which it never will.
If you're getting the $food variable from a POST or a GET op, you'll need to grab it from the appropriate array, $food = $_POST['food']; echo $food; to see what is being passed. Gary Every Sr. UNIX Administrator Ingram Entertainment (615) 287-4876 "Pay It Forward" mailto:[EMAIL PROTECTED] http://accessingram.com > -----Original Message----- > From: gatimu [mailto:[EMAIL PROTECTED] > Sent: Tuesday, July 22, 2003 7:34 AM > To: [EMAIL PROTECTED] > Subject: [PHP-DB] Condition for Adding data > > > Hi > I need help!, I am quite new to php and I am trying to create > a condition > that will load a specific page after a form has been > submitted to enter > data in my database, I have tried using this code (I created > it) but it > wont work, all I get is a messege on the browser that says "the page > address incorrect" > > Here is how i have scripted the code > <?php > $food=""; > if($food=="milk") > { > $pgload="milk.php"; > } > if ($food=="eggs") > { > $pgload="egg.php; > } > if ($food=="ham") > { > $pgload="ham.php"; > } > echo "<form name=appForm method=post action=.$pgload.>" > ?> > > any ideas on how i can go around this problem? > > Gatimu > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >
