Hello Juan
If I declare &Telefono=4141414 in one line and in the next line I declare
&Telefono=31453531, then I have overwritten the first variable.
What you need to change is the name of the variable. You need to append your
ID number to the variable name.
So &Telefono01=4141414 and &Telefono0
Thanks for the response,
Now its fixed, and this is the output for the code:
&Id=28&Apellido=sadfsadf&Nombre=asdfsdf&Dni=sadfsdf&Telefono=sadfsadf&Dia=1&Mes=12&Ano=2004&Hora=9&Minutos=50&Abogado=Dra.
Claudia I.
Gorno&Nombre=asdfsdf&Asunto=asdfsd&Donde=Guia Barrial
Palermo&Id=26&Apellido=Sarasa&No
Ok, i´ve removed the "@" form them, and now im trying
this, but its not working:
// Request all data
$result1 = mysql_query("select * from
clientesnuevos");
$nrows = mysql_num_rows($qr);
for ($i=0; $i < $nrows; $i++) {
$row = mysql_fetch_array($qr);
echo "&Id={$row['id']}";
echo "&Apellido={$row
remove the @ symbol from in front of the connect functions
@mysql_connect
@mysql_select_db
Its supressing any errors that you may have...when you finish the debugging,
then you can add them back in.
bastien
From: Juan Stiller <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Fixing this
