Have a look here...I have some sample code on calling images from a db. It
used the two pages like you do here and passes the ID back and forth to the
image production page...maybe it will help
http://www.weberdev.com/get_example-4062.html
bastien
From: Craig Hoffman [EMAIL PROTECTED]
To:
I believe the problem is somewhere in the GD script. Because when I
view the source it shows an empty variable. I should at least see the
name of variable in the source. Any ideas?
img src='include/function_gd.php?route_photo='..'' height='x'
width='x' align='center' id='image'
On Apr 6,
Hi,
If I understand correctly, you're using
include/function_gd.php?route_photo=$thumb as image source which is the
script you pasted. If you use a script as image source, the script should
output the image data - not just store the image.
I'm not sure what you're trying to do but if you have an
Hi Jos,
I understand what your saying. The problem is all the image names are
listed in the DB (image.jpg, image1.jpg and so on) and all images have
titles attached. For example,
Title: Large Green Sea Turtle
Image: LargeGreenSeaTurtle.jpg
As you can see, the GD script randomly pulls photo
-Original Message-
From: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sent: 06 April 2005 18:12
To: php-db@lists.php.net
Cc: Juffermans, Jos
Subject: Re: [PHP-DB] One more GD ? -- filename
Hi Jos,
I understand what your saying. The problem is all the image names are
listed in the DB
] One more GD ? -- filename
Hi Jos,
I understand what your saying. The problem is all the image names are
listed in the DB (image.jpg, image1.jpg and so on) and all images have
titles attached. For example,
Title: Large Green Sea Turtle
Image: LargeGreenSeaTurtle.jpg
As you can see, the GD script
