Are you using a FORM Post or Get ?
Perhaps $_POST['Name'] or $_GET['Name']
>>Hi!!
>>
>>I have a very simple and smail script with just one input text box and a
>>submit button.
>>After that, I have an echo function in the same code page that just
>>displays the data entered in the text box.
>>
Thanks so much!!!
Miguel Guirao
Servicios Datacard
www.SIASA.com.mx
-Mensaje original-
De: Viorel Dragomir [mailto:[EMAIL PROTECTED]
Enviado el: Miércoles, 26 de Mayo de 2004 09:55 a.m.
Para: Miguel Guirao; PHP DB List
Asunto: Re: [PHP-DB] Undefined variable
echo $_REQUEST['
echo $_REQUEST['Name'];
- Original Message -
From: Miguel Guirao
To: PHP DB List
Sent: Wednesday, May 26, 2004 17:47
Subject: [PHP-DB] Undefined variable
Hi!!
I have a very simple and smail script with just one input text box and a
submit button.
After that, I hav
On Friday 16 August 2002 02:22, Bo wrote:
> basically this a code for uploading images and text info into a mysql
> database, however, when I execute this code, an error occured as:
> Undefined variable: action in \phpmySQL\add.php on line 2
> what will be the problem?
php.ini -> register_globals
This is CorpseEater's reply on your message send to him on 8/15/2002 :
Sorry - i made a mistake :
it's '&&' instead of '||'
-snatch--
Bo> if ((isset($action)&&($action == "upload")) {
snatch-
--
Greets
[EMAIL PROTECTED]
--
PHP Database Mailing List (http://www.php
This is CorpseEater's reply on your message send to him on 8/15/2002 :
Bo> basically this a code for uploading images and text info into a mysql
Bo> database, however, when I execute this code, an error occured as:
Bo> Undefined variable: action in \phpmySQL\add.php on line 2
Bo> what will be the
Is it possible to add, subtract, etc on values as I am demonstrating below.
I'm getting an error with this. I want to be able to add the values of
CMAPER and CMUPER when displayed.
printf("%s%s\n", $myrow["CMPLNDESC"],
$myrow["CMAPER"+"CMUPER"]);
Thanks,
John
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PHP Database Mailing List (htt
rge
[EMAIL PROTECTED]
- Original Message -
From: John Halladay <[EMAIL PROTECTED]>
To: 'Jorge Santos' <[EMAIL PROTECTED]>
Sent: Wednesday, February 14, 2001 1:11 PM
Subject: RE: [PHP-DB] Undefined Variable and argument not valid . . .
> Great! That fixed the first er
Hi John,
You're trying to use a variable that is not set. Try using the isset
function... Like this:
if (isset($COCOD))
$result = mysql_query("SELECT * FROM tblAA_MIKER_COMPDAT WHERE
COCOD=$COCOD",$db);
Hope this helps...
Later,
Jorge
[EMAIL PROTECTED]
- Original Message -
From
