select PERIOD_DIFF(DATE_FORMAT("2002-04-01","%Y%m"),
DATE_FORMAT("2001-0801","%Y%m") ) as dd;
+------+
| dd |
+------+
| 8 |
+------+
1 row in set (0.00 sec)
-----Original Message-----
From: John Hughes [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, April 02, 2002 2:28 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] figuring out number of months between two dates
I'm trying to get PERIOD_DIFF to work in my quest to count months between
dates. I've run into a stumbling block:
LEFT(CURRENT_DATE,7) produces 2002-04, as you would expect.
LEFT(week_date,7) WHERE week_no = '1' produces 2001-08, again as expected
(see table below)
But PERIOD_DIFF(LEFT(CURRENT_DATE,7) ,LEFT(week_date,7) ) WHERE week_no =
'1' produces 1.
The trouble appears to be the '-' in the dates produced by LEFT.
When I just put PERIOD_DIFF(200204,200108) the result is 8, which is the
correct answer.
So, how do I produce the year and month digits without the intervening
hyphen so I can feed the data to PERIOD_DIFF?
----- Original Message -----
From: "John Hughes" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, April 01, 2002 11:56 PM
Subject: [PHP-DB] figuring out number of months between two dates
> I have a table that contains a list of dates. For instance:
>
> 2001-08-23
> 2001-08-27
> 2001-09-04
> (and running through)
> 2002-06-03
>
> I want to calculate how many months between 2001-08-23 and CURRENT_DATE
> (which for discussion purposes we'll put at 2002-04-01) and how many
months
> between the first week and the last.
>
> I can count the weeks and divide by 4.333 to approximate months, but I was
> wondering if there was a way to use a PHP function or MySQL's MONTH() to
do
> the job.
>
>
>
>
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>
>
>
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