Hi,
> $result2 = mysql_query("SELECT * FROM convicts WHERE ship =
> '$id' ORDER BY convict",$db);
> $row = mysql_fetch_array($result2) // ! you are missing a ";"
this is where you get the parse error from!
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Thanks for that. I've cleaned up things a bit for the time being.
I'm still getting an error though.
Parse error: parse error in c:\usr\local\www\pages/ships.php on line 30
Line 30 turns out to be $convict = $row["convict"]; so I'm assuming that
it's having trouble with the array. I've tried
Hi,
which part is not working? Put a "or die(mysql_error())" behind your
queries to see which one produces an error.
like this: $result = mysql_query("SELECT * FROM ships ORDER BY ship",$db)
or die(mysql_error());
>
> while ($row = mysql_fetch_array($result)) {
>
> If ($result) {
>
