Hi,
Actually you have an undefined variable called $row which is in this
context ($row->Vorname) is an object...but $row has nor content
neither type.
I think you'd better use arrays...in this way:
(according to the PHP manual mysql_db_query() is decrepated)
Of course some error handling may c
You seem to be mixing OO and procedural coding styles...try
,);
$result=mysql_db_query("salzert","SELECT * FROM Benutzer WHERE ID=$id");
$row = mysql_fetch_array($result); //get the data into an array
echo '';
echo "";
echo " Vorname";
echo '';
echo "";
echo "";
echo " Name";
echo '';
echo "";
