It seems to me that this code will not provide useful information:
if ($result)
echo mysql_affected_rows()." affected.";
If the insert was successful, it will always say "1 affected." Since
you are only inserting one row at a time.
On Sat, 07 Jun 2003 08:49:15 -0400, Becoming Digital wrot
Try this. I made some minor syntax changes and added some error reporting.
While it may not fix things, it might help you figure out what's wrong.
Edward Dudlik
Becoming Digital
www.becomingdigital.com
- Original Message -
From: "Ahmed Abdelaliem" <[EMAIL PROTECTED]>
To: <[EMAIL PROTE
