Gnanavel wrote:
$output=exec(cp file1 file2);
echo pre$output/pre;
does not works. can any one help me out of this problem
When I was executing the cp command it doesn't return anything.
But it returned the name of the last file when i executed the ls
`cp file1 file2` doesn't return anything -
I need to copy some tables from one mysql database to another mysql database
on the same server.
I looked at the php manual and couldn't find it...I found stuff on
mysqlhotcopy, but it doesn't look like that will do what I need it to do, or
maybe I'm reading the manual wrong.
Can someone please
Have you tried something like this:
insert into database1.tablename select * from database2.tablename;
database1 and database2 are the names of the two databases. tablename is
the name of the table you want to copy from database1 to database2. In
your case I guess this would be:
insert
David Smith wrote:
insert into database1.tablename select * from database2.tablename;
database1 and database2 are the names of the two databases. tablename
is the name of the table you want to copy from database1 to database2.
Correction: from database2 to database1, not vice versa.
Jeremy wrote:
I need to copy some tables from one mysql database to another mysql database
on the same server.
I looked at the php manual and couldn't find it...I found stuff on
mysqlhotcopy, but it doesn't look like that will do what I need it to do, or
maybe I'm reading the manual wrong.
Can
Hi all,,,
I'm having hell with this !ยง$ PHP safe mode. It seems that SuSE complies PHP
with safe mode = on. THEREFORE the config file php.ini can not turn it off.
Can someone who is using PHP exec in SuSE 8.2 give me an idea how they are
doing it? OR how to work around this.
Here is my
Sorry I'm a bit late with this, I couldn't remember where I'd seen this:
http://www.zend.com/zend/spotlight/searchengine.php
has an article on getting around this. I've used it and it's pretty easy to do.
HTH,
-Lisi
At 11:18 AM 9/4/03 +0100, [EMAIL PROTECTED] wrote:
I've been building web
Please see the attached file for details.
Unknown command - PLEASE. Try HELP.
Summary of resource utilization
---
CPU time:0.000 sec
Overhead CPU:0.000 sec
CPU model: 4-CPU 700MHz Pentium III Xeon 1M (2048M)
Job origin: [EMAIL PROTECTED]
Hi there everyone,
I'm having a strange problem, I have a form with 2 fields, 1 is for points
(Weightwatcher points) and one is for recipe names. If you select points
(IE: 1-3, 3-6,6-9,9 and above) it works perfectly, displays the recipes and
allows you to select a new points range from the
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Content preview: Please see the attached file for details. Unknown
command - PLEASE.
Since you didn't include the form, I'm going to have to make a couple of
assumptions:
$nameb is the recipe field.
$pointsb is the points field.
You want to use SQL statement 1 if they select points, 2 if they select
recipies, but those aren't the only possibilities with the form. It sounds to
Hi
if you compiled apache with prefix /usr/local/apache (i use
apache_1.3.28.tar)
and you put your mysql binary into /usr/local/mysql (i use
mysql-standard-4.0.14-pc-linux-i686.tar)
then you configure php (i use php-4.3.2.tar )
./configure --prefix=/usr/local/php --with-config-file-path=/etc
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