[PHP-DB] undefined function: mysql_pconnect()
I'm new to this stuff, so you have to excuse me if I seem dense. I can't get MySQL base operation from PHP 4.22 under RedHat Linux 8.0. I get the following error when trying to use mysql_connect(). Call to undefined function: mysql_pconnect() I don't have any other PHP running on the box, other non-db related scripting works. I'm using Apache 2.0, all the newest stuff. The PHP documentation says this should be built in, and when I utilize phpinfo(), the output section dbx says MySQL is installed. Can someone help me out? Thanks... Signed, someone who spent his time in ASP but wants out. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] undefined function: mysql_pconnect()
Could you post your entire script to see what's wrong ? -Message d'origine- De : Cameron [mailto:[EMAIL PROTECTED] Envoyé : samedi 1 mars 2003 6:17 À : [EMAIL PROTECTED] Objet : [PHP-DB] undefined function: mysql_pconnect() I'm new to this stuff, so you have to excuse me if I seem dense. I can't get MySQL base operation from PHP 4.22 under RedHat Linux 8.0. I get the following error when trying to use mysql_connect(). Call to undefined function: mysql_pconnect() I don't have any other PHP running on the box, other non-db related scripting works. I'm using Apache 2.0, all the newest stuff. The PHP documentation says this should be built in, and when I utilize phpinfo(), the output section dbx says MySQL is installed. Can someone help me out? Thanks... Signed, someone who spent his time in ASP but wants out. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Creating MySQL Entry Forms
It has to be HTML based, it can't install on the server. - Original Message - From: Leif K-Brooks [EMAIL PROTECTED] To: Jeremy N.E. Proffitt [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Friday, February 28, 2003 9:37 PM Subject: Re: [PHP-DB] Creating MySQL Entry Forms What's wrong with PhpMyAdmin? Jeremy N.E. Proffitt wrote: I need to create some simple web forms for entering, changing, deleteing information from a fairly simple MySQL database. This is to be for internal use, so doesn't have to be really fancy or have alot of error checking. I could make a form for each table myself, but I would think their is an easier way... Cheers Jeremy -- The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] redirect
How can I redirect a user to a specific page if they are already
authenticated?
if ($SESSION_Authenticated) { //code here to redirect; }
thanks
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RE: [PHP-DB] redirect
Nevermind, I found the answer, and why it wasn't working. Now I was
wondering how I can format a number to be a currency? Like if
$totalprice = 14.343 have it print 14.34.
thanks
-Original Message-
From: Jeremi Bergman [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 01, 2003 2:13 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] redirect
How can I redirect a user to a specific page if they are already
authenticated?
if ($SESSION_Authenticated) { //code here to redirect; }
thanks
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RE: [PHP-DB] redirect
Nevermind, I found the answer, and why it wasn't working. Now I was wondering how I can format a number to be a currency? Like if $totalprice = 14.343 have it print 14.34. Number_format() or printf() ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] redirect
At 04:33 PM 3/1/2003 -0500, Jeremi Bergman wrote:
www.php.net/round
find the answer there, you will :-)
~kurth
Nevermind, I found the answer, and why it wasn't working. Now I was
wondering how I can format a number to be a currency? Like if
$totalprice = 14.343 have it print 14.34.
thanks
-Original Message-
From: Jeremi Bergman [mailto:[EMAIL PROTECTED]
Sent: Saturday, March 01, 2003 2:13 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] redirect
How can I redirect a user to a specific page if they are already
authenticated?
if ($SESSION_Authenticated) { //code here to redirect; }
thanks
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RE: [PHP-DB] Code to send user info to database
I have a website that is hosted by Yahoo! Web Hosting which supports PHP with MySQL.
The db is already created, so there's no problem there. The problem I am having is
knowing what code to write for my form entries so that the info entered by a user can
be sent to my db named users and then later when a zip code search is conducted, the
matching info can be retrieved and displayed on a results page. Someone else created
the db for me so I don't really know much about that side of it. I've been reading up
on how to write PHP, but I am still lost as to where to start for my forms. Is there
any other info you need to know?
Hutchins, Richard [EMAIL PROTECTED] wrote: Michelle,
You said you've tried tutorial after tutorial. What specific problems are
you having? What kind of database are you using? Have you architected the db
yet? We can't help much if we don't know what specific problems you're
having (e.g. db connection problems, PHP parse errors, unexpected results,
etc., etc.).
Rich
-Original Message-
From: Michelle Whelan [mailto:[EMAIL PROTECTED]
Sent: Friday, February 28, 2003 2:09 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Code to send user info to database
Hi all,
I'm just starting out with writing PHP and would like to get
help with writing the code for my forms to have the data sent
to a database. Here is one of my forms:
if ($submit == Submit){
echo Your listing has been submitted;
echo Go back Home ;
echo www.dirtjobs.com/havedirt.phpAdd
another listing;
}
else{
echo '
size=2 color=#FFWHAT TYPE OF DIRT?
CLEAN DIRT FOR FINISH GRADINGDIRT WITH 6 MINUS ROCKSDIRT WITH ROCKS
size=2 color=#FFAPPROXIMATE QUANTITY OF DIRT IN YARDS:
[input] name=noyardsYards
size=2 color=red*MANDATORY*
size=2 color=#FFCONTACT NAME:
[input]
size=2 color=#FFCONTACT PHONE NUMBER:
[input]
[input]
size=2 color=#FF - [input] maxlength=4 name=suffix
size=2 color=#FFZIP CODE:
[input]
(Jobs are sorted by zip code to find other jobs in the
area)
size=2 color=#FFJOB EXPIRATION DATE:
[input]
(If no date is listed, jobs will be removed in 60
days.)
size=2 color=blue(*Optional)/font
size=2 color=#FFEMAIL ADDRESS:
[input]
size=2 color=#FFCITY OF JOB LOCATION:
[input]
size=2 color=#FFJOB CROSS STREETS:
[input]
size=2 color=#FFJOB EXPIRATION DATE:
[input]
(If no date is listed, jobs will be removed in 60
days.)
[input] value=Submit
[input]
I imagine the code is probably somewhat simple, but I have
read tutorial after tutorial etc. and am getting nowhere for
the past two weeks.
This is also the first time I have ever posted to a mailing
list so I apologize if my request is incorrect in format.
Thanks so much,
Michelle
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RE: [PHP-DB] Code to send user info to database
I have a website that is hosted by Yahoo! Web Hosting which supports PHP with MySQL.
The db is already created, so there's no problem there. The problem I am having is
knowing what code to write for my form entries so that the info entered by a user can
be sent to my db named users and then later when a zip code search is conducted, the
matching info can be retrieved and displayed on a results page. Someone else created
the db for me so I don't really know much about that side of it. I've been reading up
on how to write PHP, but I am still lost as to where to start for my forms. Is there
any other info you need to know?
Hutchins, Richard [EMAIL PROTECTED] wrote: Michelle,
You said you've tried tutorial after tutorial. What specific problems are
you having? What kind of database are you using? Have you architected the db
yet? We can't help much if we don't know what specific problems you're
having (e.g. db connection problems, PHP parse errors, unexpected results,
etc., etc.).
Rich
-Original Message-
From: Michelle Whelan [mailto:[EMAIL PROTECTED]
Sent: Friday, February 28, 2003 2:09 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Code to send user info to database
Hi all,
I'm just starting out with writing PHP and would like to get
help with writing the code for my forms to have the data sent
to a database. Here is one of my forms:
if ($submit == Submit){
echo Your listing has been submitted;
echo Go back Home ;
echo www.dirtjobs.com/havedirt.phpAdd
another listing;
}
else{
echo '
size=2 color=#FFWHAT TYPE OF DIRT?
CLEAN DIRT FOR FINISH GRADINGDIRT WITH 6 MINUS ROCKSDIRT WITH ROCKS
size=2 color=#FFAPPROXIMATE QUANTITY OF DIRT IN YARDS:
[input] name=noyardsYards
size=2 color=red*MANDATORY*
size=2 color=#FFCONTACT NAME:
[input]
size=2 color=#FFCONTACT PHONE NUMBER:
[input]
[input]
size=2 color=#FF - [input] maxlength=4 name=suffix
size=2 color=#FFZIP CODE:
[input]
(Jobs are sorted by zip code to find other jobs in the
area)
size=2 color=#FFJOB EXPIRATION DATE:
[input]
(If no date is listed, jobs will be removed in 60
days.)
size=2 color=blue(*Optional)/font
size=2 color=#FFEMAIL ADDRESS:
[input]
size=2 color=#FFCITY OF JOB LOCATION:
[input]
size=2 color=#FFJOB CROSS STREETS:
[input]
size=2 color=#FFJOB EXPIRATION DATE:
[input]
(If no date is listed, jobs will be removed in 60
days.)
[input] value=Submit
[input]
I imagine the code is probably somewhat simple, but I have
read tutorial after tutorial etc. and am getting nowhere for
the past two weeks.
This is also the first time I have ever posted to a mailing
list so I apologize if my request is incorrect in format.
Thanks so much,
Michelle
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PHP Database Mailing List (http://www.php.net/)
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Re: [PHP-DB] Creating MySQL Entry Forms
on 3/1/03 2:00 PM, Jeremy N.E. Proffitt at [EMAIL PROTECTED] appended
the following bits to my mbox:
What's wrong with PhpMyAdmin?
It has to be HTML based, it can't install on the server.
Well, you can't administer MySQL with HTML pages. You need PHP pages that
generate HTML pages. PHPMyAdmin is just a collection of PHP pages that talk
to MySQL. It doesn't require any special installation.
See: http://phpmyadmin.sf.net for more information.
Sincerely,
Paul Burney
http://paulburney.com/
?php
while ($self != asleep) {
$sheep_count++;
}
?
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Re: [PHP-DB] undefined function: mysql_pconnect()
on 3/1/03 12:16 AM, Cameron at [EMAIL PROTECTED] appended the following bits to my mbox: I'm new to this stuff, so you have to excuse me if I seem dense. I can't get MySQL base operation from PHP 4.22 under RedHat Linux 8.0. I get the following error when trying to use mysql_connect(). Call to undefined function: mysql_pconnect() You need to install the php-MySQL RPM file from the Red Hat CD. The default install doesn't give you MySQL support. HTH. Sincerely, Paul Burney -- I'm inhaling Caesar's last gasp... http://paul.burney.ws/thoughts/caesars_breath.html -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Auto inserting a database with dates
Hi there everyone, Is there a quick and easy (HAH :-) way of doing the following: I have a DB and a table with id, date etc . now what I need is to create 3 years of entries for the date in advance of the system going live (Rather than while they use it - hard to explain why but necessary). Is there an easy way to write a short PHP script that will populate the field $stock with 3 years dates in advance from the current date, using the format 02-03-200x ? it's either this way or I go through and insert new onces argghhh (That's not a pleasant thought :-) Thanks :-) Chris
Re: [PHP-DB] Random not working?
This recent thread from the mysql list explains a lot about the problem. http://lists.mysql.com/cgi-ez/ezmlm-cgi?1:mss:15034 hth, Doug On Sat, 1 Mar 2003 12:24:57 +0100, Frank Keessen wrote: Hi All, I'm trying to get a random record each time this script runs; Only it's giving me everytime the first record back.. No random at all.. // generate and execute query $query = SELECT stedenid, naamstad, stadomschrijvk FROM steden ORDER BY RAND() LIMIT 1; $result = mysql_query($query) or die (Error in query: $query. . mysql_error()); $row = mysql_fetch_object($result); echo $row-naamstad; Version info; PHP 4.3.1 Mysql 3.23.54 When i'm trying to excute the SELECT statement in phpmyadmin; i'm only getting the first record back and when i'm taking off the LIMIT 1 it will display all the records in ascending order so also not in random.. Regards, Frank -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Random not working?
Hi All, I'm trying to get a random record each time this script runs; Only it's giving me everytime the first record back.. No random at all.. // generate and execute query $query = SELECT stedenid, naamstad, stadomschrijvk FROM steden ORDER BY RAND() LIMIT 1; $result = mysql_query($query) or die (Error in query: $query. . mysql_error()); $row = mysql_fetch_object($result); echo $row-naamstad; Version info; PHP 4.3.1 Mysql 3.23.54 When i'm trying to excute the SELECT statement in phpmyadmin; i'm only getting the first record back and when i'm taking off the LIMIT 1 it will display all the records in ascending order so also not in random.. Regards, Frank
[PHP-DB] RE: [PHP] Random not working?
Hi All, I'm trying to get a random record each time this script runs; Only it's giving me everytime the first record back.. No random at all.. // generate and execute query $query = SELECT stedenid, naamstad, stadomschrijvk FROM steden ORDER BY RAND() LIMIT 1; $result = mysql_query($query) or die (Error in query: $query. . mysql_error()); $row = mysql_fetch_object($result); echo $row-naamstad; Version info; PHP 4.3.1 Mysql 3.23.54 When i'm trying to excute the SELECT statement in phpmyadmin; i'm only getting the first record back and when i'm taking off the LIMIT 1 it will display all the records in ascending order so also not in random.. Regards, Frank Frank This really belongs on the MySQL list but there was a known issue with RAND() on 3.23.54 - can you upgrade? If your table has an auto_increment ID column then a workaround would be to use rand() in PHP to generate a random ID then use that with a 'where id = '.$id in your query... HTH Rich -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] RE: [PHP] Random not working?
Thanks guys for the info; I will speak to my ISP! Have a nice weekend! Regards, Frank - Original Message - From: Rich Gray [EMAIL PROTECTED] To: Frank Keessen [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Sunday, March 02, 2003 2:36 AM Subject: [PHP-DB] RE: [PHP] Random not working? Hi All, I'm trying to get a random record each time this script runs; Only it's giving me everytime the first record back.. No random at all.. // generate and execute query $query = SELECT stedenid, naamstad, stadomschrijvk FROM steden ORDER BY RAND() LIMIT 1; $result = mysql_query($query) or die (Error in query: $query. . mysql_error()); $row = mysql_fetch_object($result); echo $row-naamstad; Version info; PHP 4.3.1 Mysql 3.23.54 When i'm trying to excute the SELECT statement in phpmyadmin; i'm only getting the first record back and when i'm taking off the LIMIT 1 it will display all the records in ascending order so also not in random.. Regards, Frank Frank This really belongs on the MySQL list but there was a known issue with RAND() on 3.23.54 - can you upgrade? If your table has an auto_increment ID column then a workaround would be to use rand() in PHP to generate a random ID then use that with a 'where id = '.$id in your query... HTH Rich -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] RE: [PHP] Random not working?
You might try getting the random number before the query. -Original Message- From: Rich Gray [mailto:[EMAIL PROTECTED] Sent: Saturday, March 01, 2003 8:37 PM To: Frank Keessen; [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: [PHP-DB] RE: [PHP] Random not working? Hi All, I'm trying to get a random record each time this script runs; Only it's giving me everytime the first record back.. No random at all.. // generate and execute query $query = SELECT stedenid, naamstad, stadomschrijvk FROM steden ORDER BY RAND() LIMIT 1; $result = mysql_query($query) or die (Error in query: $query. . mysql_error()); $row = mysql_fetch_object($result); echo $row-naamstad; Version info; PHP 4.3.1 Mysql 3.23.54 When i'm trying to excute the SELECT statement in phpmyadmin; i'm only getting the first record back and when i'm taking off the LIMIT 1 it will display all the records in ascending order so also not in random.. Regards, Frank Frank This really belongs on the MySQL list but there was a known issue with RAND() on 3.23.54 - can you upgrade? If your table has an auto_increment ID column then a workaround would be to use rand() in PHP to generate a random ID then use that with a 'where id = '.$id in your query... HTH Rich -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Making Join
Mark wrote: --- Daniel Harik [EMAIL PROTECTED] wrote: Hello, I have 2 tables users table, that stores user info, and photos table, i want to select all users with one photo form photos table, but i don't want it to be photos * users = result. Is there way to do it? Assuming you mean, you have a table called user_info and another called photos and each of them has a common element AND there must be a photo for the user then you could use this sort of select... select user_info.name, photo.image from user_info, photo where user_info.id = photo.user_id The above will not display anything if there are no matching id to user_id so if one of your users didn't have a photo they would not get displayed. Also, if a user had more than one photo they would all be displayed. If your users are expected to have one and only one photo then you may want get rid of the photo table and just put the photo in the user table. HTH Thank You for your reply, but the problem is that users may have many photos, and i need to get only one, i use folllowing sql: SELECT users.username, photos.file FROM users left join photos on users.id=photos.userid And i get: username file dan 9a2de085e456e78ed66f079572638ff3.jpg dan 852d28e6fa730f6d29d69aacd1059ae7.jpg dan 672df2f16e89e3dc92ff74e3a0fa4b4f.jpg dan 8bae6f20ed6e12ba1c86d04b8ebc9e1f.jpg dan 7de9d2db2b2096cfc3f072f8c15a9e50.jpg 404 f474a8ee5965f0a792e5b626fb30c2cd.jpg 404 3acd391cf7abafa032c5e3b21eb7b322.jpg 404 4e5df8cfa4bce5dd30c1166b8a86fa23.jpg Bedman NULL but i want only 3 users from this join, not 3x3=9 If you only want the users, and not the photos, then the previous post should do what you want. But if you also want the photo, and there's more than one photoo for a user, how will the code know which photo you want? Do you want a random photo from each user? The last photo from each user? The first? Mark Random is fine -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Making Join
Paul Burney wrote: on 2/28/03 3:15 PM, Daniel Harik at [EMAIL PROTECTED] appended the following bits to my mbox: Thank You for your reply, but the problem is that users may have many photos, and i need to get only one, i use folllowing sql: SELECT users.username, photos.file FROM users left join photos on users.id=photos.userid And i get: username file dan 9a2de085e456e78ed66f079572638ff3.jpg dan 852d28e6fa730f6d29d69aacd1059ae7.jpg dan 672df2f16e89e3dc92ff74e3a0fa4b4f.jpg dan 8bae6f20ed6e12ba1c86d04b8ebc9e1f.jpg dan 7de9d2db2b2096cfc3f072f8c15a9e50.jpg 404 f474a8ee5965f0a792e5b626fb30c2cd.jpg 404 3acd391cf7abafa032c5e3b21eb7b322.jpg 404 4e5df8cfa4bce5dd30c1166b8a86fa23.jpg Bedman NULL but i want only 3 users from this join, not 3x3=9 So you just want the users who have pictures, but not all the pictures for each? Something like: SELECT count(*) AS num_photos, username FROM photos LEFT JOIN users ON photos.userid=users.id GROUP BY userid You could add the file field in there as well, but it would only be returning one of the files (the first or last one for that user, but I don't know of a way for you to be specific). Hope that helps. Sincerely, Thank You, group by users.id did the trick, but now i have another problem, i want to select users with no photo as well, all with same sql statment, so far i have SELECT users.id, users.gender, users.year, users.month, users.day, users.username, users.city, users.country, users.feet, users.inches, users.cm, users.openingLine, profiles.bodyType, profiles.ethnic, profiles.smoke, profiles.drink, profiles.children, profiles.religion, profiles.moment, photos.file FROM users,profiles, photos WHERE users.id=profiles.userid GROUP BY users.id It works fine selecting random photo for user, but doesn't select users with no photos. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
