[PHP-DB] Page cannot be displayed problems
My bosses computer gets a Page cannot be displayed message when she uses some of my pages. I have tried to find a pattern as to why this happens on only her computer. I think the problem only occurs when she links to a page that links to a page. Say I have 3 pages: page1.php, page2.php, and page3.php On page1.php form action=page2.php method=PUT input type=submit value=GO /form And on page2.php meta http-equiv=refresh content=0;URL=page3.php If I click go on page1.php I SOMETIMES get the cannot be displayed message. SOMETIMES it works even on her computer! Anyone know why? - Matthew Perry -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Page cannot be displayed problems
form action=page2.php method=PUT ??? is that a new standard? - Original Message - From: matthew perry [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, April 29, 2004 8:11 AM Subject: [PHP-DB] Page cannot be displayed problems My bosses computer gets a Page cannot be displayed message when she uses some of my pages. I have tried to find a pattern as to why this happens on only her computer. I think the problem only occurs when she links to a page that links to a page. Say I have 3 pages: page1.php, page2.php, and page3.php On page1.php form action=page2.php method=PUT input type=submit value=GO /form And on page2.php meta http-equiv=refresh content=0;URL=page3.php If I click go on page1.php I SOMETIMES get the cannot be displayed message. SOMETIMES it works even on her computer! Anyone know why? - Matthew Perry -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Page cannot be displayed problems
Nope. An obsolete standard. Try use GET or POST instead of PUT. Cheers - Original Message - From: Uzi To: matthew perry ; [EMAIL PROTECTED] Sent: Thursday, April 29, 2004 10:13 Subject: Re: [PHP-DB] Page cannot be displayed problems form action=page2.php method=PUT ??? is that a new standard? - Original Message - From: matthew perry [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, April 29, 2004 8:11 AM Subject: [PHP-DB] Page cannot be displayed problems My bosses computer gets a Page cannot be displayed message when she uses some of my pages. I have tried to find a pattern as to why this happens on only her computer. I think the problem only occurs when she links to a page that links to a page. Say I have 3 pages: page1.php, page2.php, and page3.php On page1.php form action=page2.php method=PUT input type=submit value=GO /form And on page2.php meta http-equiv=refresh content=0;URL=page3.php If I click go on page1.php I SOMETIMES get the cannot be displayed message. SOMETIMES it works even on her computer! Anyone know why? - Matthew Perry -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Page cannot be displayed problems
As Uzi and Viorel already pointed out, use GET or POST instead of PUT. Also, to be certain of the redirect, use: ?php header(Location: page3.php); exit; ? instead of the meta redirect. First of all, I'm sure there are browsers that don't support META redirects, secondly, using the PHP header function, you will get no waiting time what so ever when moving to page 3. The META redirect tells the browser to move, while the header command tells the browser directly to go to page3. instead of loading page2 first. Does the composition of above sentences give you a hint that I'm extremely tired right now? ;) Mike On Apr 29, 2004, at 07:11, matthew perry wrote: My bosses computer gets a Page cannot be displayed message when she uses some of my pages. I have tried to find a pattern as to why this happens on only her computer. I think the problem only occurs when she links to a page that links to a page. Say I have 3 pages: page1.php, page2.php, and page3.php On page1.php form action=page2.php method=PUT input type=submit value=GO /form And on page2.php meta http-equiv=refresh content=0;URL=page3.php If I click go on page1.php I SOMETIMES get the cannot be displayed message. SOMETIMES it works even on her computer! Anyone know why? - Matthew Perry -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] assigning variables after one-to-many query
- Original Message -
From: Rachel Rodriguez [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, April 23, 2004 3:55 AM
Subject: [PHP-DB] assigning variables after one-to-many query
Hi!
I have a one-to-many relationship between two tables
(table1 and table3) with a linking table between
them (table2):
table1: table2
+---++ +---++
|id | f_name | |id | emailID|
+---++ +---++
| 1 | bill | | 1 | 1|
| 2 | john | | 1 | 4|
| 3 | diana | | 1 | 3|
| 4 | victor | | 2 | 2|
| 5 | renata | | 4 | 5|
+---++ +---++
table3
++-+
|emailID | email |
++-+
| 1| [EMAIL PROTECTED]|
| 2| [EMAIL PROTECTED] |
| 3| [EMAIL PROTECTED] |
| 4| [EMAIL PROTECTED] |
| 5| [EMAIL PROTECTED] |
++-+
I would like to write a query that matches table1.id
with records
from table3.emailID via the linking table (table2) and
then
assign each match to a variable.
Here is what I have:
$query = SELECT t3.email
FROM table3 AS t3
LEFT JOIN table2 AS t2
ON (t3.emailID = t2.emailID)
LEFT JOIN table1 AS t1
ON (t2.id = t1.id)
WHERE t1.id = 1;
$result = @myql_query($query, $db_connection);
$num = mysql_num_rows($result);
$email1 = ;
$email2 = ;
$email3 = ;
if ($num 0)
{
while ($row = mysql_fetch_array($result))
{
// do something here to assign
// $email1 = $row[email] and
// $email2 = $row[email], etc.
}
}
Of course, the problem I am having is as I am going
through the while loop, I am assigning $email1,
$email2, and so on the
same e-mail address.
I would like to get: $email1 = [EMAIL PROTECTED],
$email2 = [EMAIL PROTECTED], and $email3 =
[EMAIL PROTECTED]
what i would do is add it into an array:
$emails = Array();
while ($row = mysql_fetch_array($result,MYSQL_NUM))
{
$emails[] = $row[0];
}
then u have an array with :
$emails[0] = [EMAIL PROTECTED]
$emails[1] = [EMAIL PROTECTED]
etc...
I would prefer to do that rather than what I have seen
in most examples which is similar to the following:
// snippet of code
while ($row = mysql_fetch_array($result))
{
echoBill's email is $row[email].;
}
// end of snippet
Any assistance is greatly appreciated.
Thanks,
Rachel
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Re: [PHP-DB] converting scripts for register_globals=Off
Since I have a thing for using one file for all things in i.e. an admin
script, I use POST and GET variables at the same time. Getting them
mixed up is extremely hazardous.. I do stuff like:
a href=admin.php?action=deleteid=2Delete post/a
which leads to the section of the admin script;
?php
if ($_GET['action'] == delete $_GET['id']) {
// lots of PHP doing lots of stuff
} else {
// the link
}
?
Now, if there's a POST variable named ID containing an INT matching the
database, and I use $_REQUEST instead of $_GET, I'm in trouble!
Mike
On Apr 29, 2004, at 11:00, Ignatius Reilly wrote:
even better:
$_REQUEST['variable_name']
so that you don't have to bother checking both depending on whether
your
form was GETted or POSTed.
_
- Original Message -
From: Mikael Grön [EMAIL PROTECTED]
To: Kim Jacobs (Crooks) - Mweb [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 11:54 AM
Subject: Re: [PHP-DB] converting scripts for register_globals=Off
What register_globals does (Please correct me if I'm wrong) is convert
i.e. $_POST['variable_name'], $_GET['variable_name'] and so on to
$variable_name. which isn't very good from my point of view.
I suggest you make sure you use $_GET['your_variable'] when ever you're
fetching a GET variable, $_POST['var'] for all post variables and so
on, instead of what you're doing now.
This works just fine with register_globals = On as well, so I always
use it... to be safe..
Mike
On Apr 29, 2004, at 10:40, Kim Jacobs (Crooks) - Mweb wrote:
if any of you could help me out, I would greatly appreciate it... I am
an absolute beginner to php (2 weeks now) and dont know what I dont
know...
I have written some scripts to access my online SQL db and I've tested
the scripts on my machine with PHP 4.3.6 and register_globals = On
Now where I host my site, uses PHP 4.3.5 and has register_globals =
Off which means of course, that my scripts arent working, but I dont
know why
My question is, how do I convert my scripts so that they will work
please? I know that $id and $submit are two of the 'inputs' that it
doesnt like, but I dont know the rest
Tx
K
MWEB: S.A.'s most trusted and reliable Internet Service Provider. Just
Like That.
To join, go to: http://join.mweb.co.za or call 0860032000.
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Re: [PHP-DB] converting scripts for register_globals=Off
If your form is well designed, there should NOT be another POST variable
named ID or id used for a different purpose.
Your form data validation routine will examine the 2-uple ( action, id), not
id alone. therefore no problem.
In many cases I find it convenient to design a page so that it can be called
indifferently by POST or GET.
Just my 2 Belgian francs.
Ignatius
_
- Original Message -
From: Mikael Grön [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 12:42 PM
Subject: Re: [PHP-DB] converting scripts for register_globals=Off
Since I have a thing for using one file for all things in i.e. an admin
script, I use POST and GET variables at the same time. Getting them
mixed up is extremely hazardous.. I do stuff like:
a href=admin.php?action=deleteid=2Delete post/a
which leads to the section of the admin script;
?php
if ($_GET['action'] == delete $_GET['id']) {
// lots of PHP doing lots of stuff
} else {
// the link
}
?
Now, if there's a POST variable named ID containing an INT matching the
database, and I use $_REQUEST instead of $_GET, I'm in trouble!
Mike
On Apr 29, 2004, at 11:00, Ignatius Reilly wrote:
even better:
$_REQUEST['variable_name']
so that you don't have to bother checking both depending on whether
your
form was GETted or POSTed.
_
- Original Message -
From: Mikael Grön [EMAIL PROTECTED]
To: Kim Jacobs (Crooks) - Mweb [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 11:54 AM
Subject: Re: [PHP-DB] converting scripts for register_globals=Off
What register_globals does (Please correct me if I'm wrong) is convert
i.e. $_POST['variable_name'], $_GET['variable_name'] and so on to
$variable_name. which isn't very good from my point of view.
I suggest you make sure you use $_GET['your_variable'] when ever you're
fetching a GET variable, $_POST['var'] for all post variables and so
on, instead of what you're doing now.
This works just fine with register_globals = On as well, so I always
use it... to be safe..
Mike
On Apr 29, 2004, at 10:40, Kim Jacobs (Crooks) - Mweb wrote:
if any of you could help me out, I would greatly appreciate it... I am
an absolute beginner to php (2 weeks now) and dont know what I dont
know...
I have written some scripts to access my online SQL db and I've tested
the scripts on my machine with PHP 4.3.6 and register_globals = On
Now where I host my site, uses PHP 4.3.5 and has register_globals =
Off which means of course, that my scripts arent working, but I dont
know why
My question is, how do I convert my scripts so that they will work
please? I know that $id and $submit are two of the 'inputs' that it
doesnt like, but I dont know the rest
Tx
K
MWEB: S.A.'s most trusted and reliable Internet Service Provider. Just
Like That.
To join, go to: http://join.mweb.co.za or call 0860032000.
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Re: [PHP-DB] converting scripts for register_globals=Off
From: Kim Jacobs (Crooks) - Mweb [EMAIL PROTECTED] I have written some scripts to access my online SQL db and I've tested the scripts on my machine with PHP 4.3.6 and register_globals = On Now where I host my site, uses PHP 4.3.5 and has register_globals = Off which means of course, that my scripts arent working, but I dont know why My question is, how do I convert my scripts so that they will work please? I know that $id and $submit are two of the 'inputs' that it doesnt like, but I dont know the rest If your program is well written, you can get away with just switching $id for $_REQUEST['id']. This is assuming you already properly validate and sanitize all of the data coming from the user. Using $_REQUEST['id'] doesn't make anything more or less secure, it's a matter of what you're doing with the data coming from the user. ---John Holmes... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Pear - autoExecute()
Am trying the following bit of code usind the PEAR DB.php class
$table = 'reports';
$fields = array('report_name' = $_POST['report_name'],
'report_desc' = $_POST['report_desc']
);
$res = $db-autoExecute($table,$fields,DB_AUTOQUERY_INSERT);
if (DB::isError($res)) {
die($res-getMessage());
}
However I get the error
Fatal error: Call to undefined function: autoexecute() in
/home/jp/public_html/v1/reports.php on line 19
I'm using the $db-query() methods and getALL etc so I know the class is
loaded and working.
Is there a library I'm missing
tia
Pete
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RE: [PHP-DB] Pear - autoExecute()
http://pear.php.net/manual/en/package.database.php
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:03
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Pear - autoExecute()
Am trying the following bit of code usind the PEAR DB.php class
$table = 'reports';
$fields = array('report_name' = $_POST['report_name'],
'report_desc' = $_POST['report_desc']
);
$res = $db-autoExecute($table,$fields,DB_AUTOQUERY_INSERT);
if (DB::isError($res)) {
die($res-getMessage());
}
However I get the error
Fatal error: Call to undefined function: autoexecute() in
/home/jp/public_html/v1/reports.php on line 19
I'm using the $db-query() methods and getALL etc so I know the class is
loaded and working.
Is there a library I'm missing
tia
Pete
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Re: [PHP-DB] Pear - autoExecute()
That's where I copied the code below that does not work ;-(
Uzi Klein wrote:
http://pear.php.net/manual/en/package.database.php
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:03
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Pear - autoExecute()
Am trying the following bit of code usind the PEAR DB.php class
$table = 'reports';
$fields = array('report_name' = $_POST['report_name'],
'report_desc' = $_POST['report_desc']
);
$res = $db-autoExecute($table,$fields,DB_AUTOQUERY_INSERT);
if (DB::isError($res)) {
die($res-getMessage());
}
However I get the error
Fatal error: Call to undefined function: autoexecute() in
/home/jp/public_html/v1/reports.php on line 19
I'm using the $db-query() methods and getALL etc so I know the class is
loaded and working.
Is there a library I'm missing
tia
Pete
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RE: [PHP-DB] Pear - autoExecute()
Did you use $db = new DB; ?
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:31
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Pear - autoExecute()
That's where I copied the code below that does not work ;-(
Uzi Klein wrote:
http://pear.php.net/manual/en/package.database.php
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:03
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Pear - autoExecute()
Am trying the following bit of code usind the PEAR DB.php class
$table = 'reports';
$fields = array('report_name' = $_POST['report_name'],
'report_desc' = $_POST['report_desc']
);
$res = $db-autoExecute($table,$fields,DB_AUTOQUERY_INSERT);
if (DB::isError($res)) {
die($res-getMessage());
}
However I get the error
Fatal error: Call to undefined function: autoexecute() in
/home/jp/public_html/v1/reports.php on line 19
I'm using the $db-query() methods and getALL etc so I know the class is
loaded and working.
Is there a library I'm missing
tia
Pete
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RE: [PHP-DB] Pear - autoExecute()
http://pear.php.net/manual/en/package.database.db.db-common.autoexecute.php
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:31
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Pear - autoExecute()
That's where I copied the code below that does not work ;-(
Uzi Klein wrote:
http://pear.php.net/manual/en/package.database.php
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:03
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Pear - autoExecute()
Am trying the following bit of code usind the PEAR DB.php class
$table = 'reports';
$fields = array('report_name' = $_POST['report_name'],
'report_desc' = $_POST['report_desc']
);
$res = $db-autoExecute($table,$fields,DB_AUTOQUERY_INSERT);
if (DB::isError($res)) {
die($res-getMessage());
}
However I get the error
Fatal error: Call to undefined function: autoexecute() in
/home/jp/public_html/v1/reports.php on line 19
I'm using the $db-query() methods and getALL etc so I know the class is
loaded and working.
Is there a library I'm missing
tia
Pete
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Re: [PHP-DB] Pear - autoExecute()
yep
This is from config.inc.php
$dsn = mysql://$username_DB:[EMAIL PROTECTED]/$database_DB;
//echo $dsn;
require_once('../includes/DB/DB.php');
$db = DB::connect($dsn,true);
if (DB::isError($db)) {
die ($db-getMessage());}
$db-setFetchMode(DB_FETCHMODE_ASSOC);
I'm using the getAll(), query(), getOne(), etc ok - it just doesnt see
autoExecute() ??
Or I'm missing the obvious !
pete ;-)
Uzi Klein wrote:
Did you use $db = new DB; ?
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:31
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Pear - autoExecute()
That's where I copied the code below that does not work ;-(
Uzi Klein wrote:
http://pear.php.net/manual/en/package.database.php
-Original Message-
From: pete M [mailto:[EMAIL PROTECTED]
Sent: Thursday, April 29, 2004 14:03
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Pear - autoExecute()
Am trying the following bit of code usind the PEAR DB.php class
$table = 'reports';
$fields = array('report_name' = $_POST['report_name'],
'report_desc' = $_POST['report_desc']
);
$res = $db-autoExecute($table,$fields,DB_AUTOQUERY_INSERT);
if (DB::isError($res)) {
die($res-getMessage());
}
However I get the error
Fatal error: Call to undefined function: autoexecute() in
/home/jp/public_html/v1/reports.php on line 19
I'm using the $db-query() methods and getALL etc so I know the class is
loaded and working.
Is there a library I'm missing
tia
Pete
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[PHP-DB] Re: Page cannot be displayed problems
Date: Thu, 29 Apr 2004 01:11:35 -0500 From: matthew perry [EMAIL PROTECTED] To: [EMAIL PROTECTED] Subject: Page cannot be displayed problems My bosses computer gets a Page cannot be displayed message when she uses some of my pages. I have tried to find a pattern as to why this happens on only her computer. I think the problem only occurs when she links to a page that links to a page. Say I have 3 pages: page1.php, page2.php, and page3.php On page1.php form action=page2.php method=PUT input type=submit value=GO /form And on page2.php meta http-equiv=refresh content=0;URL=page3.php If I click go on page1.php I SOMETIMES get the cannot be displayed message. SOMETIMES it works even on her computer! Anyone know why? - Matthew Perry Hi, I have just encountered the same problem. The site was working fine a few days ago but now it shows up as a 404 error however the files exist in the directory in question on the web server. Has there been a new release of php/apache/mysql or something that has caused some forms to not work? I can't find a problem at all nor has the files that produce 404's have been edited at all in a long time. So they should not be different and therefore work. Another things I thought of was cookies, clearing cookies etc. And as I speak I just cleared mine and they bloody (excuse me) worked. I can login and use forms... Well, that is weird. I suggest you clear your cookies! I just did and it worked wonders, I've NEVER HAD to do that EVER in the passed. Maybe they got altered/corrupted or something?? J Find local movie times and trailers on Yahoo! Movies. http://au.movies.yahoo.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Dynamic Graphing Software
Hi every one! I am looking for recommendations for using software to produce dynamic graphs with a APM solution. Any suggestions? - Rafi Sheikh This e-mail, including attachments, may include confidential and/or proprietary information, and may be used only by the person or entity to which it is addressed. If the reader of this e-mail is not the intended recipient or his or her authorized agent, the reader is hereby notified that any dissemination, distribution or copying of this e-mail is prohibited. If you have received this e-mail in error, please notify the sender by replying to this message and delete this e-mail immediately. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Dynamic Graphing Software
jpgraph :) - Original Message - From: Rafi Sheikh To: '[EMAIL PROTECTED]' Sent: Thursday, April 29, 2004 16:18 Subject: [PHP-DB] Dynamic Graphing Software Hi every one! I am looking for recommendations for using software to produce dynamic graphs with a APM solution. Any suggestions? - Rafi Sheikh This e-mail, including attachments, may include confidential and/or proprietary information, and may be used only by the person or entity to which it is addressed. If the reader of this e-mail is not the intended recipient or his or her authorized agent, the reader is hereby notified that any dissemination, distribution or copying of this e-mail is prohibited. If you have received this e-mail in error, please notify the sender by replying to this message and delete this e-mail immediately. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] converting scripts for register_globals=Off
If you have already have a number of scripts and, especially, if you are doing things with the variables inside the script (in other words, the variables appear more than once), it can be more convenient to convert at the top of each page, eg: $id = $_REQUEST['id']; $this = $_REQUEST['this']; $that = $_SERVER['that']; etc... Jeffrey Baumgartner Date sent: Thu, 29 Apr 2004 11:40:14 +0200 From: Kim Jacobs (Crooks) - Mweb [EMAIL PROTECTED] To: [EMAIL PROTECTED] Subject:[PHP-DB] converting scripts for register_globals=Off if any of you could help me out, I would greatly appreciate it... I am an absolute beginner to php (2 weeks now) and dont know what I dont know... I have written some scripts to access my online SQL db and I've tested the scripts on my machine with PHP 4.3.6 and register_globals = On Now where I host my site, uses PHP 4.3.5 and has register_globals = Off which means of course, that my scripts arent working, but I dont know why My question is, how do I convert my scripts so that they will work please? I know that $id and $submit are two of the 'inputs' that it doesnt like, but I dont know the rest Tx K MWEB: S.A.'s most trusted and reliable Internet Service Provider. Just Like That. To join, go to: http://join.mweb.co.za or call 0860032000. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] From mysql to mssql...
I use PHP/MySQL daily.. love it, live it breath it... However, I've been given a one page project to do, that needs to add the contecnt of a form to an mssql database... I'm fine with doing all the page, apart from talking to mssql... how drasitally does this differ from the standard mysql functions tha tI use..? (Also, I nearly ahd to do it in asp... I'd never used it before, but after lookign at it, it made me damned happy that I use PHP.. way more user friendly!!) * The information contained in this e-mail message is intended only for the personal and confidential use of the recipient(s) named above. If the reader of this message is not the intended recipient or an agent responsible for delivering it to the intended recipient, you are hereby notified that you have received this document in error and that any review, dissemination, distribution, or copying of this message is strictly prohibited. If you have received this communication in error, please notify us immediately by e-mail, and delete the original message. *** -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] PHP Training
Any one know of a good training course for PHP (beg to intermediate-1-3 days) in the twin cities area? Best regards, RS This e-mail, including attachments, may include confidential and/or proprietary information, and may be used only by the person or entity to which it is addressed. If the reader of this e-mail is not the intended recipient or his or her authorized agent, the reader is hereby notified that any dissemination, distribution or copying of this e-mail is prohibited. If you have received this e-mail in error, please notify the sender by replying to this message and delete this e-mail immediately. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] search engines
Anyone out there know of a good tutorial on creating a php/mysql based search engine script? I would like to write one for a small in-house application that I am running. thanks, DF -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] search engines
Read up on MySQL full text search. http://dev.mysql.com/doc/mysql/en/Fulltext_Search.html -Jeff - Original Message - From: redhat [EMAIL PROTECTED] To: phplist [EMAIL PROTECTED] Sent: Thursday, April 29, 2004 10:12 AM Subject: [PHP-DB] search engines Anyone out there know of a good tutorial on creating a php/mysql based search engine script? I would like to write one for a small in-house application that I am running. thanks, DF -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] From mysql to mssql...
[EMAIL PROTECTED] wrote: I've been given a one page project to do, that needs to add the contecnt of a form to an mssql database... I'm fine with doing all the page, apart from talking to mssql... how drasitally does this differ from the standard mysql functions tha tI use..? There's not much of a difference (with regards to the php functions). I'd recommend you get into the habit of using ADOdb or PEAR::DB so that even if you do switch databases like this, you still have a familiar syntax. -- ---John Holmes... Amazon Wishlist: www.amazon.com/o/registry/3BEXC84AB3A5E/ php|architect: The Magazine for PHP Professionals www.phparch.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: From mysql to mssql...
Hi Tristan, Tristan Pretty wrote: However, I've been given a one page project to do, that needs to add the contecnt of a form to an mssql database... I'm fine with doing all the page, apart from talking to mssql... how drasitally does this differ from the standard mysql functions tha tI use..? The quick answer is that you're in luck: the MSSQL API looks a lot like MySQL's PHP API. For example, mysql_fetch_array() - mssql_fetch_array(). A practical word of advice, though: use a database abstraction layer. There are a number out there that will make your life easier: PEAR::DB, PEAR::MDB, ADOdb, Creole (PHP5). Most (all?) of these support MS SQL Server and they will all make thing much easier -- especially if you ever decide to try to run that SQL Server app on MySQL. I would recommend MDB (or MDB2) if you are using PHP4; ADOdb is fast, but if you care about source code quality and/or design you'll use PEAR. One difference you'll probably discover, if you extend your app at all, is that there is no LIMIT in MS SQL Server. To do paged queries is quite difficult -- and that's why using a db abstraction layer will help you out. Other differences in the SQL / results are quite numerous. Date/time formats look different (some abstraction layers will help with this). MySQL also allows for some pretty sloppy SQL, and MS SQL Server will complain when you try to do things like add aggegate functions to your SELECT() clause without having a GROUP BY clause. (Also, I nearly ahd to do it in asp... I'd never used it before, but after lookign at it, it made me damned happy that I use PHP.. way more user friendly!!) At the risk of being stoned, I will say that I've had the opportunity to work with ASP.NET/C# and I absolutely love that famework (and the C# language). It's a very well conceived answer to problem of OO n-tier web application development. I love PHP and have been using it for many years, but I also love OO app architecture and even PHP5 really doesn't play in the same league as solutions like ASP.NET. Classic ASP is a different story. Cheers, Hans -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Page cannot be displayed problems
PUT is still used with great success by systems such as WebDav. I'd stick to GET or POST though in a web environment, as the server needs to be specially configured to accept PUT requests and there are certain security implications from allowing people to upload files using PUT. Cheers - Neil. At 10:43 29/04/2004 +, you wrote: Message-ID: [EMAIL PROTECTED] From: Uzi [EMAIL PROTECTED] To: matthew perry [EMAIL PROTECTED], [EMAIL PROTECTED] Date: Thu, 29 Apr 2004 09:13:40 +0200 MIME-Version: 1.0 Content-Type: text/plain; charset=iso-8859-1 Content-Transfer-Encoding: 7bit Subject: Re: [PHP-DB] Page cannot be displayed problems form action=page2.php method=PUT ??? is that a new standard? CaptionKit http://www.captionkit.com : Production tools for accessible subtitled internet media, transcripts and searchable video. Supports Real Player, Quicktime and Windows Media Player. VideoChat with friends online, get Freshly Toasted every day at http://www.fresh-toast.net : NetMeeting solutions for a connected world. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Image / file uploader
I have a script where it uploads a image to directory. I have used
the script several times and it works when I send the form to another
page. The problem is I have changed the form to submit to itself and I
can't seem to get it to work.
echo ( form method='post' action='$_SERVER[PHP_SELF]'
encType='multipart/form-data');
The thing is all my other fields update except for the image. Further,
the image does not even show up if I echo the query out.
UPDATE users SET bio = 'Bio - Test', goals = 'Goals - Test', fav_race =
'Fav Races - test', fav_train = 'Traing -test', photo_name = '' WHERE
user_id = '1'
Here is the code of the image uploader and my query, perhaps someone
could take a look let me know what I'm missing.
Thanks - CH
input type='file' name='photo'
if($_POST[postback_bio])
{
include include/dbadmin.php;
//image uploader
$uploadpath = '/images/clients/';
$source = $HTTP_POST_FILES['photo']['tmp_name'];
$photo_name = $HTTP_POST_FILES['photo']['name'];
$dest = '';
if (($source != '') ($source != '')) {
$dest = $uploadpath.$photo_name;
if ($dest = '') {
if (move_uploaded_file($source, $dest)) {
echo (p id='message'Image and Bio has been successfully
stored./p );
} else {
echo (p id='message'Image could not be stored./p);
}
}
} else {
echo (p id='message'No new image supplied./p);
$photo_name = $oldimage;
}
//declare varibles
$user_id = $_POST[user_id];
$name = $_POST[name];
$bio = $_POST[bio];
$goals = $_POST[goals];
$fav_race = $_POST[fav_race];
$fav_train = $_POST[fav_train];
$photo = $_POST[photo_name];
$query = UPDATE users SET bio = '$bio', goals = '$goals', fav_race =
'$fav_race', fav_train = '$fav_train', photo_name = '$photo_name'
WHERE user_id = '$user_id';
echo $query;
$msg = span style='color:red' id='message'Could not update
record/span;
$result = mysql_query($query, $db);
}
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
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Re: [PHP-DB] Image / file uploader
I think you want single quotes around PHP_SELF.
$_SERVER['PHP_SELF']
I have a script where it uploads a image to directory. I have used
the script several times and it works when I send the form to another
page. The problem is I have changed the form to submit to itself and I
can't seem to get it to work.
echo ( form method='post' action='$_SERVER[PHP_SELF]'
encType='multipart/form-data');
The thing is all my other fields update except for the image. Further,
the image does not even show up if I echo the query out.
UPDATE users SET bio = 'Bio - Test', goals = 'Goals - Test', fav_race =
'Fav Races - test', fav_train = 'Traing -test', photo_name = '' WHERE
user_id = '1'
Here is the code of the image uploader and my query, perhaps someone
could take a look let me know what I'm missing.
Thanks - CH
input type='file' name='photo'
if($_POST[postback_bio])
{
include include/dbadmin.php;
//image uploader
$uploadpath = '/images/clients/';
$source = $HTTP_POST_FILES['photo']['tmp_name'];
$photo_name = $HTTP_POST_FILES['photo']['name'];
$dest = '';
if (($source != '') ($source != '')) {
$dest = $uploadpath.$photo_name;
if ($dest = '') {
if (move_uploaded_file($source, $dest)) {
echo (p id='message'Image and Bio has been
successfully
stored./p );
} else {
echo (p id='message'Image could not be
stored./p);
}
}
} else {
echo (p id='message'No new image supplied./p);
$photo_name = $oldimage;
}
//declare varibles
$user_id = $_POST[user_id];
$name = $_POST[name];
$bio = $_POST[bio];
$goals = $_POST[goals];
$fav_race = $_POST[fav_race];
$fav_train = $_POST[fav_train];
$photo = $_POST[photo_name];
$query = UPDATE users SET bio = '$bio', goals = '$goals', fav_race =
'$fav_race', fav_train = '$fav_train', photo_name = '$photo_name'
WHERE user_id = '$user_id';
echo $query;
$msg = span style='color:red' id='message'Could not update
record/span;
$result = mysql_query($query, $db);
}
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
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Re: [PHP-DB] Image / file uploader
When I put single quotes in the PHP_SELF and I get this error:
Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE,
expecting T_STRING or T_VARIABLE or T_NUM_STRING
and I can't use double quotes because its in an echo statement. What
am I missing?
echo (form method='post' action='$_SERVER['PHP_SELF']'
encType='multipart/form-data'
Any more thoughts?
CH
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
On Apr 29, 2004, at 6:49 PM, Daniel Clark wrote:
I think you want single quotes around PHP_SELF.
$_SERVER['PHP_SELF']
I have a script where it uploads a image to directory. I have used
the script several times and it works when I send the form to another
page. The problem is I have changed the form to submit to itself and
I
can't seem to get it to work.
echo ( form method='post' action='$_SERVER[PHP_SELF]'
encType='multipart/form-data');
The thing is all my other fields update except for the image.
Further,
the image does not even show up if I echo the query out.
UPDATE users SET bio = 'Bio - Test', goals = 'Goals - Test', fav_race
=
'Fav Races - test', fav_train = 'Traing -test', photo_name = '' WHERE
user_id = '1'
Here is the code of the image uploader and my query, perhaps someone
could take a look let me know what I'm missing.
Thanks - CH
input type='file' name='photo'
if($_POST[postback_bio])
{
include include/dbadmin.php;
//image uploader
$uploadpath = '/images/clients/';
$source = $HTTP_POST_FILES['photo']['tmp_name'];
$photo_name = $HTTP_POST_FILES['photo']['name'];
$dest = '';
if (($source != '') ($source != '')) {
$dest = $uploadpath.$photo_name;
if ($dest = '') {
if (move_uploaded_file($source, $dest)) {
echo (p id='message'Image and Bio has been
successfully
stored./p );
} else {
echo (p id='message'Image could not be
stored./p);
}
}
} else {
echo (p id='message'No new image supplied./p);
$photo_name = $oldimage;
}
//declare varibles
$user_id = $_POST[user_id];
$name = $_POST[name];
$bio = $_POST[bio];
$goals = $_POST[goals];
$fav_race = $_POST[fav_race];
$fav_train = $_POST[fav_train];
$photo = $_POST[photo_name];
$query = UPDATE users SET bio = '$bio', goals = '$goals', fav_race =
'$fav_race', fav_train = '$fav_train', photo_name = '$photo_name'
WHERE user_id = '$user_id';
echo $query;
$msg = span style='color:red' id='message'Could not update
record/span;
$result = mysql_query($query, $db);
}
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
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Re: [PHP-DB] Image / file uploader
Change to double quotes for the HTML portion.
action=\$_SERVER['PHP_SELF']\
When I put single quotes in the PHP_SELF and I get this error:
Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE,
expecting T_STRING or T_VARIABLE or T_NUM_STRING
and I can't use double quotes because its in an echo statement. What
am I missing?
echo (form method='post' action='$_SERVER['PHP_SELF']'
encType='multipart/form-data'
Any more thoughts?
CH
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
On Apr 29, 2004, at 6:49 PM, Daniel Clark wrote:
I think you want single quotes around PHP_SELF.
$_SERVER['PHP_SELF']
I have a script where it uploads a image to directory. I have used
the script several times and it works when I send the form to another
page. The problem is I have changed the form to submit to itself and
I
can't seem to get it to work.
echo ( form method='post' action='$_SERVER[PHP_SELF]'
encType='multipart/form-data');
The thing is all my other fields update except for the image.
Further,
the image does not even show up if I echo the query out.
UPDATE users SET bio = 'Bio - Test', goals = 'Goals - Test', fav_race
=
'Fav Races - test', fav_train = 'Traing -test', photo_name = '' WHERE
user_id = '1'
Here is the code of the image uploader and my query, perhaps someone
could take a look let me know what I'm missing.
Thanks - CH
input type='file' name='photo'
if($_POST[postback_bio])
{
include include/dbadmin.php;
//image uploader
$uploadpath = '/images/clients/';
$source = $HTTP_POST_FILES['photo']['tmp_name'];
$photo_name = $HTTP_POST_FILES['photo']['name'];
$dest = '';
if (($source != '') ($source != '')) {
$dest = $uploadpath.$photo_name;
if ($dest = '') {
if (move_uploaded_file($source, $dest)) {
echo (p id='message'Image and Bio has been
successfully
stored./p );
} else {
echo (p id='message'Image could not be
stored./p);
}
}
} else {
echo (p id='message'No new image supplied./p);
$photo_name = $oldimage;
}
//declare varibles
$user_id = $_POST[user_id];
$name = $_POST[name];
$bio = $_POST[bio];
$goals = $_POST[goals];
$fav_race = $_POST[fav_race];
$fav_train = $_POST[fav_train];
$photo = $_POST[photo_name];
$query = UPDATE users SET bio = '$bio', goals = '$goals', fav_race =
'$fav_race', fav_train = '$fav_train', photo_name = '$photo_name'
WHERE user_id = '$user_id';
echo $query;
$msg = span style='color:red' id='message'Could not update
record/span;
$result = mysql_query($query, $db);
}
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
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Re: [PHP-DB] Image / file uploader
Do this:
echo ( form method='post' action='.$_SERVER[PHP_SELF].'
encType='multipart/form-data');
PHP doesn't handle array's well in echo statements, so you have to stop the
echo, concat the array, and then continue the echo.
-Micah
On Thursday 29 April 2004 04:46 pm, Craig Hoffman wrote:
I have a script where it uploads a image to directory. I have used
the script several times and it works when I send the form to another
page. The problem is I have changed the form to submit to itself and I
can't seem to get it to work.
echo ( form method='post' action='$_SERVER[PHP_SELF]'
encType='multipart/form-data');
The thing is all my other fields update except for the image. Further,
the image does not even show up if I echo the query out.
UPDATE users SET bio = 'Bio - Test', goals = 'Goals - Test', fav_race =
'Fav Races - test', fav_train = 'Traing -test', photo_name = '' WHERE
user_id = '1'
Here is the code of the image uploader and my query, perhaps someone
could take a look let me know what I'm missing.
Thanks - CH
input type='file' name='photo'
if($_POST[postback_bio])
{
include include/dbadmin.php;
//image uploader
$uploadpath = '/images/clients/';
$source = $HTTP_POST_FILES['photo']['tmp_name'];
$photo_name = $HTTP_POST_FILES['photo']['name'];
$dest = '';
if (($source != '') ($source != '')) {
$dest = $uploadpath.$photo_name;
if ($dest = '') {
if (move_uploaded_file($source, $dest)) {
echo (p id='message'Image and Bio has been
successfully
stored./p );
} else {
echo (p id='message'Image could not be
stored./p);
}
}
} else {
echo (p id='message'No new image supplied./p);
$photo_name = $oldimage;
}
//declare varibles
$user_id = $_POST[user_id];
$name = $_POST[name];
$bio = $_POST[bio];
$goals = $_POST[goals];
$fav_race = $_POST[fav_race];
$fav_train = $_POST[fav_train];
$photo = $_POST[photo_name];
$query = UPDATE users SET bio = '$bio', goals = '$goals', fav_race =
'$fav_race', fav_train = '$fav_train', photo_name = '$photo_name'
WHERE user_id = '$user_id';
echo $query;
$msg = span style='color:red' id='message'Could not update
record/span;
$result = mysql_query($query, $db);
}
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
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Re: [PHP-DB] Image / file uploader
Sorry to be a pest but I tried that. It giving me the same error.
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
On Apr 29, 2004, at 7:10 PM, Daniel Clark wrote:
Change to double quotes for the HTML portion.
action=\$_SERVER['PHP_SELF']\
When I put single quotes in the PHP_SELF and I get this error:
Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE,
expecting T_STRING or T_VARIABLE or T_NUM_STRING
and I can't use double quotes because its in an echo statement. What
am I missing?
echo (form method='post' action='$_SERVER['PHP_SELF']'
encType='multipart/form-data'
Any more thoughts?
CH
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
On Apr 29, 2004, at 6:49 PM, Daniel Clark wrote:
I think you want single quotes around PHP_SELF.
$_SERVER['PHP_SELF']
I have a script where it uploads a image to directory. I have used
the script several times and it works when I send the form to
another
page. The problem is I have changed the form to submit to itself
and
I
can't seem to get it to work.
echo ( form method='post' action='$_SERVER[PHP_SELF]'
encType='multipart/form-data');
The thing is all my other fields update except for the image.
Further,
the image does not even show up if I echo the query out.
UPDATE users SET bio = 'Bio - Test', goals = 'Goals - Test',
fav_race
=
'Fav Races - test', fav_train = 'Traing -test', photo_name = ''
WHERE
user_id = '1'
Here is the code of the image uploader and my query, perhaps someone
could take a look let me know what I'm missing.
Thanks - CH
input type='file' name='photo'
if($_POST[postback_bio])
{
include include/dbadmin.php;
//image uploader
$uploadpath = '/images/clients/';
$source = $HTTP_POST_FILES['photo']['tmp_name'];
$photo_name = $HTTP_POST_FILES['photo']['name'];
$dest = '';
if (($source != '') ($source != '')) {
$dest = $uploadpath.$photo_name;
if ($dest = '') {
if (move_uploaded_file($source, $dest)) {
echo (p id='message'Image and Bio has been
successfully
stored./p );
} else {
echo (p id='message'Image could not be
stored./p);
}
}
} else {
echo (p id='message'No new image supplied./p);
$photo_name = $oldimage;
}
//declare varibles
$user_id = $_POST[user_id];
$name = $_POST[name];
$bio = $_POST[bio];
$goals = $_POST[goals];
$fav_race = $_POST[fav_race];
$fav_train = $_POST[fav_train];
$photo = $_POST[photo_name];
$query = UPDATE users SET bio = '$bio', goals = '$goals',
fav_race =
'$fav_race', fav_train = '$fav_train', photo_name = '$photo_name'
WHERE user_id = '$user_id';
echo $query;
$msg = span style='color:red' id='message'Could not update
record/span;
$result = mysql_query($query, $db);
}
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
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Re: [PHP-DB] Image / file uploader
Craig Hoffman wrote: Sorry to be a pest but I tried that. It giving me the same error. __ Change to double quotes for the HTML portion. action=\$_SERVER['PHP_SELF']\ You'll find that the ultimate correct form is echo etcetc action=\$_SERVER[PHP_SELF]\ etcetc; When you're using an associative array inside a string, you don't need to put quotes refer to its textual index. Bruno Ferreira --- [This E-mail scanned for viruses by Declude Virus] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Image / file uploader
Fellows, thanks for helping. But still no luck. The error is gone, but
the image / file is still not showing up in the query. What else I can
provide to help trouble shoot this?
echo (form method='post' action='.$_SERVER[PHP_SELF].'
encType='multipart/form-data');
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
On Apr 29, 2004, at 7:32 PM, Micah Stevens wrote:
Do this:
echo ( form method='post' action='.$_SERVER[PHP_SELF].'
encType='multipart/form-data');
PHP doesn't handle array's well in echo statements, so you have to
stop the
echo, concat the array, and then continue the echo.
-Micah
On Thursday 29 April 2004 04:46 pm, Craig Hoffman wrote:
I have a script where it uploads a image to directory. I have used
the script several times and it works when I send the form to another
page. The problem is I have changed the form to submit to itself and
I
can't seem to get it to work.
echo ( form method='post' action='$_SERVER[PHP_SELF]'
encType='multipart/form-data');
The thing is all my other fields update except for the image.
Further,
the image does not even show up if I echo the query out.
UPDATE users SET bio = 'Bio - Test', goals = 'Goals - Test', fav_race
=
'Fav Races - test', fav_train = 'Traing -test', photo_name = '' WHERE
user_id = '1'
Here is the code of the image uploader and my query, perhaps someone
could take a look let me know what I'm missing.
Thanks - CH
input type='file' name='photo'
if($_POST[postback_bio])
{
include include/dbadmin.php;
//image uploader
$uploadpath = '/images/clients/';
$source = $HTTP_POST_FILES['photo']['tmp_name'];
$photo_name = $HTTP_POST_FILES['photo']['name'];
$dest = '';
if (($source != '') ($source != '')) {
$dest = $uploadpath.$photo_name;
if ($dest = '') {
if (move_uploaded_file($source, $dest)) {
echo (p id='message'Image and Bio has been
successfully
stored./p );
} else {
echo (p id='message'Image could not be
stored./p);
}
}
} else {
echo (p id='message'No new image supplied./p);
$photo_name = $oldimage;
}
//declare varibles
$user_id = $_POST[user_id];
$name = $_POST[name];
$bio = $_POST[bio];
$goals = $_POST[goals];
$fav_race = $_POST[fav_race];
$fav_train = $_POST[fav_train];
$photo = $_POST[photo_name];
$query = UPDATE users SET bio = '$bio', goals = '$goals', fav_race =
'$fav_race', fav_train = '$fav_train', photo_name = '$photo_name'
WHERE user_id = '$user_id';
echo $query;
$msg = span style='color:red' id='message'Could not update
record/span;
$result = mysql_query($query, $db);
}
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimbmedia.com
_
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[PHP-DB] Page cannot be displayed continues
Everyone,
Thank you very much for your advice about not using PUT. I will use
GET or POST from now on.
I am, however, failing to understand how to use headers to change pages
instead of meta tags.
After checking if the user has logged in correctly I do this:
if ($loginGood){
echo 'meta http-equiv=refresh content=0;URL=welcome.php';
}
else {
echo 'meta http-equiv=refresh content=0;URL=loginerror.php';
}
How can I use a header like the following one to do change pages based
on variable input?
Thank you for your time and patience,
- Matt
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