Balazs Hegedus ha scritto:
?php
$date = '30/03/2983 12:00';
$pattern =
'[0-3][0-9]/[0|1][0-9]/[1|2][0-9]{3,3}\s[0-2][0-9]:[0-5][0-9]';
I found this:
^([0-1]?\d)|(2[0-8]))\/((0?\d)|(1[0-2])))|(29\/((0?[1,3-9])|(1[0-2])))|(30\/((0?[1,3-9])|(1[0-2])))|(31\/((0?[13578])|(1[0-2]\/((19\d{2})|([2-9]\d{3}))|(29\/0?2\/[2468][048])|([3579][26]))00)|(((19)|([2-9]\d))(([2468]0)|([02468][48])|([13579][26]))\s(([01]?\d)|(2[0-3]))(:[0-5]?\d){2}$
But it accepts second too...can you help me to modify it?
bye and thanks anyway,
damn thats ugly..
Personally I love regex, as some of you on this list may have found out
the hard way..
But in a situation like this where I'd also want to verify the integers
passed I'd simply use the regex to help me split the given datetime
string into a 5/6 element array which I can then perform tests with
Lets not forget:
bool checkdate ( int month, int day, int year )
http://php.mirrors.ilisys.com.au/manual/en/function.checkdate.php
Helps to ensure the date at least is a valid date and day for the given
month..
Therefore I would do something like:
$dtStr = preg_replace(/^(\d{2})\/(\d{2})\/(\d{2,4})
(\d{1,2}):(\d{2})$/, $1-$2-$3-$4-$5, $date);
$dtArr = split(-,$dtStr);
if(checkdate($dtArr[1], $dtArr[0], $dtArr[2]) AND $dtArr[3]=23 AND
$dtArr[3]=0 AND $dtArr[4]=59 AND $dtArr[4]=0) {
//date and time are valid. continue processing..
}
its fairly short, has room to grow [ie changing format acceptance in
regex] to allow for different seperators or even addition of seconds
later down the track easily without having to dive into a untidy regex
pattern.
Let me know how you go...
Best of luck!
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