I thought about this some more, and my last reply wouldn't work if you
wanted data besides the IP and date. A better answer is to use a
self-join like this:
select t1.* from tracker t1
left join tracker t2 on t2.date > t1.date
and t2.ip = t1.ip
where t2.date is null
That should get you what you want.
-Micah
On 03/13/2007 11:41 PM, septic wrote:
Thanks for the responce..
I have tried everything except of the one that forms the date in one field
and use the DISTINCT for ip and date.
The problem with the distinct is that even if I use 'order by' the entries I
get for all IPs are not the latest ones that exist in the database.
.
""septic"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
Hello all,
I have created a simple webtracer for my website and I save some info on
mysql database.
table = tracker
FIELDS
ip
day
month
year
session_id
browser of visitor
page that was visited
What I would like to do next, is simple to create an output of that
database with the last time that every different IP has visited my
website.
the best output I have at the moment is:
$query = "SELECT ip,day,month,year FROM tracker WHERE page = 'index'
ORDER BY `tracker`.`year` DESC , `tracker`.`month` DESC , `tracker`.`day`
DESC LIMIT 0,20 ";
The problem is that I want to Keep for each different IP the fisrt entry
that is found on this output I get.
therefore I would say that the output would represent the last visit of
each different user on my website.
do you know of a php or sql trick to avoid entries that containt the same
IP entries ?
Thanks in advance for the help.
Nikos.
