[PHP-DB] parameters not working under PDO
It's quite possible that I'm missing something obvious here. The
following code fragment does not return any rows, but if I take out the
parameters and replace them with hardcoded strings (enclosed in single
quotes), I get the right results.
I've scattered print statements throughout, and the query seems to get
past execute() OK, it's just not returning anything from the call to fetch()
Am I missing something obvious?
$stmt = $conn-prepare(select t.z from towns t
join counties c on t.county_z = c.z
where t.me = ?
and c.state_z = ?);
if ($stmt-execute($parts)) {
while ($row = $stmt-fetch()) {
$town_z = $row['z'];
}
} else {
print $stmt-errorCode();
print_r($stmt-errorInfo());
}
Thanks in advance!
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Re: [PHP-DB] parameters not working under PDO
O/H Chris Curvey ??:
It's quite possible that I'm missing something obvious here. The
following code fragment does not return any rows, but if I take out
the parameters and replace them with hardcoded strings (enclosed in
single quotes), I get the right results.
I've scattered print statements throughout, and the query seems to
get past execute() OK, it's just not returning anything from the call
to fetch()
Am I missing something obvious?
$stmt = $conn-prepare(select t.z from towns t
join counties c on t.county_z = c.z
where t.me = ?
and c.state_z = ?);
if ($stmt-execute($parts)) {
while ($row = $stmt-fetch()) {
$town_z = $row['z'];
}
What is $parts doing ?? You just need execute() and I suppose although
not posted that you did construct the object like:
$conn| = new PDO('mysql:host=localhost;dbname=test', $user, $pass);
|A good choice is to tell fetch a way to retrieve your data like this:
$town_z = $stmt-fetch(PDO::FETCH_ASSOC);
although I think that it will get both result sets in case you don't define.
} else {
print $stmt-errorCode();
print_r($stmt-errorInfo());
}
Thanks in advance!
A better way debug that I know is using exceptions like:
try {
$sth = $conn-query($query);
$rs = $sth-fetch();
} catch (Exception $e) {
print failed :.$e-getMessage();
}
You can use try {} with almost everything so give it a try :-) .
Send us some feed back or post full source if you keep having trouble.
--
Thodoris
Re: [PHP-DB] parameters not working under PDO
Check $parts.. print_r($parts) and make sure its 1) an array 2)
contains 2 values
On 10/31/07, Chris Curvey [EMAIL PROTECTED] wrote:
It's quite possible that I'm missing something obvious here. The
following code fragment does not return any rows, but if I take out the
parameters and replace them with hardcoded strings (enclosed in single
quotes), I get the right results.
I've scattered print statements throughout, and the query seems to get
past execute() OK, it's just not returning anything from the call to fetch()
Am I missing something obvious?
$stmt = $conn-prepare(select t.z from towns t
join counties c on t.county_z = c.z
where t.me = ?
and c.state_z = ?);
if ($stmt-execute($parts)) {
while ($row = $stmt-fetch()) {
$town_z = $row['z'];
}
} else {
print $stmt-errorCode();
print_r($stmt-errorInfo());
}
Thanks in advance!
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[PHP-DB] Trouble with Text Area
When I put his line outside of the php tags I get the correct size: textarea name='name' value='$String' rows='10' cols='10'/textareap When I put this line inside the php tags the size comes out about 2 rows by 10 columns regardless of the value of rows and cols. Any ideas on how to format this would be greatly appreciated. The mySQL db column TYPE I am calling is Blob not null. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] parameters not working under PDO
good thing to check...it seems to be OK.
Array ( [0] = montclair [1] = nj )
Michael Preslar wrote:
Check $parts.. print_r($parts) and make sure its 1) an array 2)
contains 2 values
On 10/31/07, Chris Curvey [EMAIL PROTECTED] wrote:
It's quite possible that I'm missing something obvious here. The
following code fragment does not return any rows, but if I take out the
parameters and replace them with hardcoded strings (enclosed in single
quotes), I get the right results.
I've scattered print statements throughout, and the query seems to get
past execute() OK, it's just not returning anything from the call to fetch()
Am I missing something obvious?
$stmt = $conn-prepare(select t.z from towns t
join counties c on t.county_z = c.z
where t.me = ?
and c.state_z = ?);
if ($stmt-execute($parts)) {
while ($row = $stmt-fetch()) {
$town_z = $row['z'];
}
} else {
print $stmt-errorCode();
print_r($stmt-errorInfo());
}
Thanks in advance!
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Re: [PHP-DB] Re: backup of database record before update
Stephen Sunderlin wrote: Neil, Have you had success with triggers. I couldn't get one to work and then saw discussion on the board here that MYSQL triggers were not so reliable and still somewhat problematic so I archive through the application. Just curious. i have used a couple simple triggers on a 5.0.20nt box. one thing i read recently is triggers and stored procedures do use more system resources though... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Trouble with Text Area
Stephen Sunderlin wrote: When I put his line outside of the php tags I get the correct size: textarea name='name' value='$String' rows='10' cols='10'/textareap That's not how you specify the value of a textarea. It should be between the tags like so... textarea name=name rows=10 cols=10$String/textarea And I'm assuming that $String has already had htmlentities run on it. When I put this line inside the php tags the size comes out about 2 rows by 10 columns regardless of the value of rows and cols. Check the source of the page being created. I'm guessing $String contains a single quote and then a sequence of characters that is causing this behaviour. Any ideas on how to format this would be greatly appreciated. The mySQL db column TYPE I am calling is Blob not null. -Stut -- http://stut.net/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
