Re: [PHP-DB] If( Query)
Niel Archer wrote:
Hi
I have the following function:
function
add_item($item_name,$item_desc,$item_price,$item_man_id,$item_cat_id,$item_pix)
{
connect();
if($item_pix == "")
{
$sql = "INSERT INTO items
(item_name,item_desc,item_price,item_man_id,item_cat_id) VALUES
('$item_name','$item_desc','$item_price','$item_man_id','$item_cat_id')";
}
else {
$sql = "INSERT INTO items
(item_name,item_desc,item_price,item_pix,item_man_id,item_cat_id) VALUES
('$item_name','$item_desc','$item_price','$item_pix','$item_man_id','$item_cat_id')";
}
mysql_query($sql);
return;
}
I am using the if statement because i want it so that if no picture is
uploaded the entry is blank and the mysql database has a default entry
of na.gif which is a "picture coming soon picture".
It works fine when i run in localy on MAMP, but if i run it on my web
server it doesnt add the row.
You should be checking the mysql_query call for success and output the
error if it fails. Something like:
mysql_query($sql) or die('Insert failed: ' . mysql_error());
You'll now why it's failing then. Make sure you have error reporting
enabled.
Is this a compatability error? or is there a better way to write this?
--
Niel Archer
I have fixed it now:
function
add_item($item_name,$item_desc,$item_price,$item_man_id,$item_cat_id,$item_pix)
{
connect();
if($item_pix == "")
{
$sql = "INSERT INTO items
(item_name,item_desc,item_price,item_man_id,item_cat_id) VALUES
('$item_name','$item_desc','$item_price','$item_man_id','$item_cat_id')";
}
else {
$sql = "INSERT INTO items
(item_name,item_desc,item_price,item_pix,item_man_id,item_cat_id) VALUES
('$item_name','$item_desc','$item_price','$item_pix','$item_man_id','$item_cat_id')";
}
mysql_query($sql);
return;
}
Thanks anyway.
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Re: [PHP-DB] If( Query)
Hi
> I have the following function:
>
> function
> add_item($item_name,$item_desc,$item_price,$item_man_id,$item_cat_id,$item_pix)
> {
> connect();
> if($item_pix == "")
> {
> $sql = "INSERT INTO items
> (item_name,item_desc,item_price,item_man_id,item_cat_id) VALUES
> ('$item_name','$item_desc','$item_price','$item_man_id','$item_cat_id')";
> }
> else {
> $sql = "INSERT INTO items
> (item_name,item_desc,item_price,item_pix,item_man_id,item_cat_id) VALUES
> ('$item_name','$item_desc','$item_price','$item_pix','$item_man_id','$item_cat_id')";
> }
> mysql_query($sql);
> return;
> }
>
> I am using the if statement because i want it so that if no picture is
> uploaded the entry is blank and the mysql database has a default entry
> of na.gif which is a "picture coming soon picture".
>
> It works fine when i run in localy on MAMP, but if i run it on my web
> server it doesnt add the row.
You should be checking the mysql_query call for success and output the
error if it fails. Something like:
mysql_query($sql) or die('Insert failed: ' . mysql_error());
You'll now why it's failing then. Make sure you have error reporting
enabled.
> Is this a compatability error? or is there a better way to write this?
>
--
Niel Archer
--
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Re: [PHP-DB] mysql auto_increment
Little change - the label was not used in the right way:
http://pastebin.com/m2d98e677
On Sun, Sep 7, 2008 at 11:46 PM, Evert Lammerts
<[EMAIL PROTECTED]> wrote:
> I guess this code was not copy pasted from your actual source? It
> would generate mysql errors.
>
> Anyway, I think I've an idea of what you want, so here's my two cents :
>
> function edit_cat_radio($item_cat_id) {
>connect();
>$query = mysql_query("SELECT * FROM cat");
>while ($row = mysql_fetch_assoc($query)) {
>echo " for=\"{$row['cat_name']}\">{$row['cat_name']} type=\"radio\" name=\"fcat\" value=\"{$row['cat_id']}\"
> id=\"{$row['cat_id']}\" " . ($item_cat_id == $row["cat_id"] ?
> "checked=\"checked\"" : "") . "/>\n";
>}
> }
>
>
>
> On Sun, Sep 7, 2008 at 11:16 PM, Chris Hale <[EMAIL PROTECTED]> wrote:
>> I am writing a catologe application and i have a problem when it comes to
>> the edit product part. I have a table with the catogories and a table with
>> manufacturers.
>> Each table has a id column and a name column. The id column is set up in the
>> MySQL to auto_increment, which works fine normally, but i am writing this
>> script:
>>
>> function edit_cat_radio($item_cat_id)
>> {
>> connect();
>> $sql = "SELECT * FROM cat DISTINGT ORDER BY cat_id";
>> $result = mysql_query($sql);
>> $k = 1;
>> while ($row = mysql_fetch_assoc($result))
>> {
>> extract($row);
>> echo '',$cat_name,'> name="fcat" value="',$cat_id,'" id="',$cat_id,'"';
>> if($k == $item_cat_id)
>> {
>> echo 'checked';
>> }
>> echo ' />';
>> $k++;
>> }
>> return; }
>>
>> This should (in theory) automatically check the radio button of the existing
>> catogory. It would work fine; but what seems to mess it up is the
>> auto_increment.
>>
>> If i delete a catogory/manufacturer from the id's remain the same. and end
>> up like this:
>> cat_id cat_name
>> 1 Bridlework
>> 2 Clippers
>> 3 Clothing
>> 4 Dressage Tests
>> 5 DVD/Video/Books
>> 9 Footwear
>>
>> but if the cat_id is 9 the /while /statement doesnt repeat 9 times so the
>> counter never reaches 9.
>>
>> I don't know if you got all that, its hard to explain.
>>
>> I would appreciate any help on how to sort this out.
>>
>> Thanks
>>
>> --
>> PHP Database Mailing List (http://www.php.net/)
>> To unsubscribe, visit: http://www.php.net/unsub.php
>>
>>
>
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Re: [PHP-DB] mysql auto_increment
Pastebin is so much nicer when posting code. Find the code i've sent here: http://pastebin.com/mc5d611a -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] mysql auto_increment
I guess this code was not copy pasted from your actual source? It
would generate mysql errors.
Anyway, I think I've an idea of what you want, so here's my two cents :
function edit_cat_radio($item_cat_id) {
connect();
$query = mysql_query("SELECT * FROM cat");
while ($row = mysql_fetch_assoc($query)) {
echo "{$row['cat_name']}\n";
}
}
On Sun, Sep 7, 2008 at 11:16 PM, Chris Hale <[EMAIL PROTECTED]> wrote:
> I am writing a catologe application and i have a problem when it comes to
> the edit product part. I have a table with the catogories and a table with
> manufacturers.
> Each table has a id column and a name column. The id column is set up in the
> MySQL to auto_increment, which works fine normally, but i am writing this
> script:
>
> function edit_cat_radio($item_cat_id)
> {
> connect();
> $sql = "SELECT * FROM cat DISTINGT ORDER BY cat_id";
> $result = mysql_query($sql);
> $k = 1;
> while ($row = mysql_fetch_assoc($result))
> {
> extract($row);
> echo '',$cat_name,' name="fcat" value="',$cat_id,'" id="',$cat_id,'"';
> if($k == $item_cat_id)
> {
> echo 'checked';
> }
> echo ' />';
> $k++;
> }
> return; }
>
> This should (in theory) automatically check the radio button of the existing
> catogory. It would work fine; but what seems to mess it up is the
> auto_increment.
>
> If i delete a catogory/manufacturer from the id's remain the same. and end
> up like this:
> cat_id cat_name
> 1 Bridlework
> 2 Clippers
> 3 Clothing
> 4 Dressage Tests
> 5 DVD/Video/Books
> 9 Footwear
>
> but if the cat_id is 9 the /while /statement doesnt repeat 9 times so the
> counter never reaches 9.
>
> I don't know if you got all that, its hard to explain.
>
> I would appreciate any help on how to sort this out.
>
> Thanks
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
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[PHP-DB] mysql auto_increment
I am writing a catologe application and i have a problem when it comes
to the edit product part. I have a table with the catogories and a table
with manufacturers.
Each table has a id column and a name column. The id column is set up in
the MySQL to auto_increment, which works fine normally, but i am writing
this script:
function edit_cat_radio($item_cat_id)
{
connect();
$sql = "SELECT * FROM cat DISTINGT ORDER BY cat_id";
$result = mysql_query($sql);
$k = 1;
while ($row = mysql_fetch_assoc($result))
{
extract($row);
echo '',$cat_name,'type="radio" name="fcat" value="',$cat_id,'" id="',$cat_id,'"';
if($k == $item_cat_id)
{
echo 'checked';
}
echo ' />';
$k++;
}
return;
}
This should (in theory) automatically check the radio button of the
existing catogory. It would work fine; but what seems to mess it up is
the auto_increment.
If i delete a catogory/manufacturer from the id's remain the same. and
end up like this:
cat_id cat_name
1 Bridlework
2 Clippers
3 Clothing
4 Dressage Tests
5 DVD/Video/Books
9 Footwear
but if the cat_id is 9 the /while /statement doesnt repeat 9 times so
the counter never reaches 9.
I don't know if you got all that, its hard to explain.
I would appreciate any help on how to sort this out.
Thanks
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] If( Query)
Is your table set up in the same way on your webserver? Maybe you
forgot to set the default value to na.gif in your item_pix column. If
not, can you send your table definition?
On Sat, Sep 6, 2008 at 9:02 PM, Chris Hale <[EMAIL PROTECTED]> wrote:
> I have the following function:
>
> function
> add_item($item_name,$item_desc,$item_price,$item_man_id,$item_cat_id,$item_pix)
> {
> connect();
> if($item_pix == "")
> {
> $sql = "INSERT INTO items
> (item_name,item_desc,item_price,item_man_id,item_cat_id) VALUES
> ('$item_name','$item_desc','$item_price','$item_man_id','$item_cat_id')";
> }
> else {
> $sql = "INSERT INTO items
> (item_name,item_desc,item_price,item_pix,item_man_id,item_cat_id) VALUES
> ('$item_name','$item_desc','$item_price','$item_pix','$item_man_id','$item_cat_id')";
> }
> mysql_query($sql);
> return;
> }
>
> I am using the if statement because i want it so that if no picture is
> uploaded the entry is blank and the mysql database has a default entry of
> na.gif which is a "picture coming soon picture".
>
> It works fine when i run in localy on MAMP, but if i run it on my web server
> it doesnt add the row.
>
> Is this a compatability error? or is there a better way to write this?
>
> Thanks
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
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