[PHP-DB] Re: Screen size, browser on php
Is there a way of getting from php the screen size? Sorry but as php is only server-side, there is no way to get the screen size. You have to use javascript and send the result to the page again, as you suggested yourself. Regards, Bastian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: foreach problem
$sql2 = INSERT INTO cal_date_map (entry_id, date) VALUES (\$entry_id\, \$val\); Where does $entry_id come from? Maybe it's unique? Bastian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: vaiable from one page to another
Hi, you have to write it exactly like this: echo $_POST['fname']; HTH, Bastian echo $_post(fname) -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: select from multi tables
SELECT SUM(T1.F1) AS C1, SUM(T2.F1) AS C2 FROM T1, T2 Hi, T1,T2 is a join of the two tables which means that you combine each value of T1 with each value of T2. This is why you don't get the result you want. In your case I simply would do two querys as it won't make any problems: SELECT SUM T1.F1 FROM T1; SELECT SUM T2.F2 FROM T2; Regards, Bastian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Echo with extra characters
Maybe you want to use urlencode()?!
hth,
Bastian
Alex Francis schrieb:
I have the following code in my page as a header.
?
if ($mainarea==Language)
{
header(Location:add_5-14_material.php?mainarea=$mainarea);
}
else
{
}
?
When I echo $mainarea I get \'Language\'. I think it is something to do
with my quotation marks but need some help.
How do I get rid of the ' and \ so that I am left with my variable?.
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[PHP-DB] Re: Dumping MySQL rows into a 2D array
Hi,
first leave out the loop with for ($i...).
then use the loop with while and make sure that you create arrays. you're
currently filling the same variables with different results each time. the last
one always overwrites the ones bevor.
so add those brackets: []:
$dbRow['ev_id'][]= $row[id];
$dbRow['ev_uid'][] = $row[user_id];
HTH,
Bastian
George Pitcher schrieb:
Hi all,
I want to grab the resul from a db query and store it in an array so that I
can selectively grab the data later.
This is what I'm doing:
$dbRowCount = mysql_num_rows( $result );
for ($i = 1; $i = $dbRowCount; ++$i) {
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$dbRow['ev_id']= $row[id];
$dbRow['ev_uid'] = $row[user_id];
$dbRow['ev_title'] = $row[name];
$dbRow['ev_cat'] = $row[category];
$dbRow['ev_sd']= $row[start_day];
$dbRow['ev_ed']= $row[end_day];
}
}
In my sample database, I have two records which are both found with the
query (tested in MySQLFront) but the array ends up with 3 rows each with the
last record in it.
Any suggestions?
George
===
George Pitcher
HERON Technical Manager
Ingenta plc
23-38 Hythe Bridge Street, Oxford, OX1 2ET
T +44 (0)1865 799137 direct
T +44 (0)1865 799000 switchboard
F +44 (0)1865 799134
E [EMAIL PROTECTED]
www.ingenta.com
Ingenta: Empowering the exchange of academic and professional content
online.
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[PHP-DB] Re: Final question of the week :-)
Hi,
you could use IN in your query:
$sql = select * from. where id in (0// start your query
if (count($selection) = 1) {
for ($i=0;$icount($selection);$i++) {
echo $selection[$i];
$sql .= ,.$selection[$i];// add each ID to your query
}};
$sql .= ); // finish the query, then execute it
$res = mysql_query($sql);
HTH,
Bastian
Chris Payne schrieb:
Hi there everyone,
I use the following code to collect date from multiple tickboxes on my form:
if (count($selection) = 1) {
for ($i=0;$icount($selection);$i++) {
echo $selection[$i];
}};
$selection is the ID number and passes fine, but what I need it to do is
query my DB via the above query displaying the results from the multiple
ID's, how can I do this from this array? I know from a single ID / string
but not this way.
Please help, i'm almost totally bald from frustration :-)
Chris
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[PHP-DB] Re: adding in array
Hi, I'ld suggest this: // inside your loop $array[$year] += $value; HTH, Bastian Martin Allan Jensen schrieb: Hi all, I have a problem i know you can help me with. I have this flushet out from a loop command: Year: 2000 ID: 14 Value: 300 Year: 2002 ID: 11 Value: 640 Year: 2002 ID: 10 Value: 100 Year: 2003 ID: 11 Value: 200 Year: 2004 ID: 11 Value: 150 Year: 2005 ID: 11 Value: 250 I need PHP to put it into an array, but if it's the same YEAR the it's supposed to add the two values, so if i made a flush of the arrayt it would say somthing like: Array( [0] = Array ( [2000] = 300) [1] = Array( [2002] = 740 ) [2] = Array( [2003] = 200) [4] = Array( [2004] = 150) [5] = Array( [2005] = 250)) So here is the little plan, I only got the values in a variable in a loop, so i guess firstly putting it into an array could be a good idea, then add it and put it into an array again so i can flush the output, but i'm really bad at array (and english) so i really hope that you will help me. I hope you get it, Thanks A lot for your help !! BEST Regards, Martin Allan Jensen -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: adding in array
Lets say $year is 2000 There is not defined index 2000 at $array. It is going to be undefined offset. Hm... I think it's gonna work, but if it's one of the don'ts in progamming style, could you tell me why you shouldn't do this and how to make it better (and nice)? Regards, Bastian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Fw: Insert strtoupper
Hi,
in your query strtoupper is treated as a string and not as a function.
You have to write this:
mysql_query (INSERT INTO anagrafe (codice,nome, cognome, codicefiscale)
VALUES
('.strtoupper($codicefiscale).','$NOME','.strtoupper($cognome).','.strtoupper($codicefiscale).',
...
Regards,
Bastian
Antonio Bernabei schrieb:
Hi,
I want to insert the upper case of the strings written in the forn, so I
put
on the php file called these lines
$NOME=strtoupper($nome);
mysql_query (INSERT INTO anagrafe (codice,nome, cognome, codicefiscale)
VALUES
('strtoupper($codicefiscale)','$NOME','strtoupper($cognome)','strtoupper($co
dicefiscale)', ...
but if $codice if for example abc in field codice I don't get ABC but
uppercase(abc)
while if $nome is mario in the filed nome I get MARIO
Can I avoid to write extra lines for the conversion?
Thanks
Antonio
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[PHP-DB] Re: displaying duplicate records...
Hi, there's an elegant way to stop people from uploading the infos more than one time. And it's easy to do. You just have to figure out which fields are not allowed to have the same values and put those fields into an unique key. ALTER TABLE projekt ADD UNIQUE(voornaam, achternaam, email) would just allow one entry with the same names and email. The query you're searching may be like this: $query=SELECT COUNT(email) as cnt, voornaam,achternaam,leeftijd,ID,email FROM modellen GROUP BY email HAVING cnt 1; HTH, Bastian Marco Alting schrieb: I have a database which allows people to upload info and foto's. There's a unique ID field, but some people tend to upload their info more than once (its a contest site). What I'm able to do is to see how may duplicates there are using the following statement: $query=SELECT COUNT(*) as cnt, voornaam,achternaam,leeftijd,ID,email FROM modellen GROUP BY email HAVING cnt 1; But this only gives me numbers. Does anyone know how to display every record that has multiple duplicate ? Or is there an elegant way to stop people from entering their info more than once? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: displaying duplicate records...
Marco Alting schrieb: Ok I see, and how would you catch the error people get, when they send it again ? Well, there will be no error-message... if you use mysql (do you?) ;-) If you want a message you will have to select all rows from your table where the values the user wants to insert are already inserted. If you find some - error, if not - put them in. Ignatius is right: I forgot to mention that there mustn't be any duplicates in the fields you want to add to the unique key. HTH, Bastian Bastian Vogt [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, there's an elegant way to stop people from uploading the infos more than one time. And it's easy to do. You just have to figure out which fields are not allowed to have the same values and put those fields into an unique key. ALTER TABLE projekt ADD UNIQUE(voornaam, achternaam, email) would just allow one entry with the same names and email. The query you're searching may be like this: $query=SELECT COUNT(email) as cnt, voornaam,achternaam,leeftijd,ID,email FROM modellen GROUP BY email HAVING cnt 1; HTH, Bastian Marco Alting schrieb: I have a database which allows people to upload info and foto's. There's a unique ID field, but some people tend to upload their info more than once (its a contest site). What I'm able to do is to see how may duplicates there are using the following statement: $query=SELECT COUNT(*) as cnt, voornaam,achternaam,leeftijd,ID,email FROM modellen GROUP BY email HAVING cnt 1; But this only gives me numbers. Does anyone know how to display every record that has multiple duplicate ? Or is there an elegant way to stop people from entering their info more than once? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] mysql - enum
Hi, is it possible to get all possible values of an enum-field from a mysql-table in php? The values might be changed in the database. Now I've got an select-field in my php-app where the user can select each value of the enum-field for a new record befor saving... Thanks for any reply, Bastian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Connecting to remote db securely
Hi, why don't you write a script which simply gets all the data you need out of their database and puts it into some arrays. then include the page on your website and then you can work with the arrays as if they were on your server HTH, Bastian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: help w/Multiple Joins
hi, you have to create aliases for every column you want to fetch results from. you have to change your query like this: SELECT i1.img_path AS i1_path, i2.img_path AS i2_path, i3. you can leave out the AS if you want to.. hth, bastian $result = mysql_query(SELECT * FROM photo_album as p INNER JOIN images AS i1 ON p.img_1=i1.img_id INNER JOIN images AS i2 ON p.img_2=i2.img_id INNER JOIN images AS i3 ON p.img_3=i3.img_id INNER JOIN images AS i4 ON p.img_4=i4.img_id,$db)or die(mysql_error()); -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: right join
hi, did you try ...FROM labor RIGHT JOIN works_orders ON labor_ord_no = works_orders_ord_no WHERE labor_qty='' ORDER BY labor_qty,$link); ? i think that should do it regards, bastian How do I get the following select to exclude records where labor_qty from labor does not have a record? $result = mysql_query(SELECT labor_ord_no,works_orders_ord_no,works_orders_part_no,works_orders_qty,labor _qty FROM labor RIGHT JOIN works_orders ON labor_ord_no = works_orders_ord_no ORDER BY labor_qty,$link); -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
