Re: [PHP-DB] Refresh

2001-03-27 Thread JJeffman

I don't know Postgresql, but all databases I've dealt with increments
auto-increment fields only on committing insert commands. I think you can
catch the last id number (MySQL do it) and show the number + 1 on the user
screen.

HTH

Jayme.

-Mensagem Original-
De: Julio Cuz, Jr. [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 27 de maro de 2001 16:51
Assunto: [PHP-DB] Refresh


 Hi--

 I don't know if this is something PHP can solve, or if my database engine
 (Postgresql 7.03) needs to do something.

 Every time a user adds a new request, a new ID is generated, but
SOMETIMES,
 when the same user adds several requests, one after another, the browser
 does NOT refresh and it displays the previous ID.

 For example:  User A submits a new request (#1001), then adds another one
 (#1002), it should display #1002, but instead it displays #1001.  Any
ideas?



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Re: [PHP-DB] problem with writing date/time into db

2001-03-25 Thread JJeffman

You've  misplaced a "$date" variable instead of $datum, $date has no value .

HTH

Jayme.

-Mensagem Original-
De: Florian Poppele [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: domingo, 25 de maro de 2001 10:26
Assunto: [PHP-DB] problem with writing date/time into db


 Just started with PHP. I'm trying to write a news post script. Somehow den
 actual date isn't written properly into the db. There's always '-00-00
 00:00:00' saved into the db.

 my code:

 $datum = date("Y-m-d H:m:s");

 $sql = "INSERT INTO news (datum,tag,text,autor) VALUES
 ('$date','$tag','$text', '$autor')";

 If anyone can help, i'd be happy. Thanks.


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Re: [PHP-DB] file name extentions

2001-03-24 Thread JJeffman

Look for "AddType application/x-httpd-php4" on your Apache configuration
file and add the types you want PHP4 be responsible for.

Here are my own :

AddType application/x-httpd-php4 .php
AddType application/x-httpd-php4 .php3
AddType application/x-httpd-php4 .html

HTH

Jayme.

-Mensagem Original-
De: Dan Eskildsen [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sbado, 24 de maro de 2001 08:40
Assunto: [PHP-DB] file name extentions


 Hi there,

 Currently my ISP has PHP 3 installed and to run php scripts I have to save
 the file as name.php3

 I expect to install my own server and php4 in the foreseeable future - how
 can I save the files as .php so that they are upwardly compatible?

 I have tired using the filenmae file.php but the server will not execute
the
 file.

 Any suggestions?

 Regards,
 Dan


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 Please cc your reply to [EMAIL PROTECTED]
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Re: [PHP-DB] comparison table script

2001-03-24 Thread JJeffman

Remember it only works on PHP4.0 !

HTH.

Jayme.

-Mensagem Original-
De: olinux [EMAIL PROTECTED]
Para: PHP-DB [EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de maro de 2001 23:38
Assunto: Re: [PHP-DB] comparison table script


 Cool!
 Just came across this, looks like PHP will make life simple.

 http://www.php.net/manual/en/function.array-flip.php
 Array_flip() returns an array in flip order.

   Example 1. Array_flip() example

 $trans = array_flip ($trans);
 $original = strtr ($str, $trans);




 example:
 $a[0]="abc"; $a[1]="def";
 After an array_flip() you get:
 $a["abc"]=0; $a["def"]=1;

 gotta love it!
 olinux


  De: olinux  [EMAIL PROTECTED]
  Para: [EMAIL PROTECTED]
  Enviada em: sexta-feira, 23 de maro de 2001 12:37
  Assunto: Re: [PHP-DB] comparison table script
 
 
   You can get an idea here of what I would like to do
  
  
 

http://www.bestbuy.com/ComputersPeripherals/DrivesStorage/CDRW.asp?m=488cat
  =511scat=514
  
   So all information is displayed side by side, most of
   the time used to help decide between 2 or 3 products
   [bestbuy limits 10 selections in their comparison]
 


 _
 Do You Yahoo!?
 Get your free @yahoo.com address at http://mail.yahoo.com


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Re: [PHP-DB] connection id

2001-03-24 Thread JJeffman

Use persistent connections it's a matter of performance of your script.
When you use persistent connections the next call to mysql_pconnect will
catch a opened connection if available. The mysql_connect command always
open a new connection which slower than get an opened one. Anyway you can't
use the connection_id in other page. May be using PHP4 Sessions.

HTH.

Jayme.

-Mensagem Original-
De: andrie [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de maro de 2001 20:38
Assunto: [PHP-DB] connection id


 Hello php mania,
   i was connecting into mysql using mysql_connect, and i just saved
   the return value from this funtion. now i want to use this connection
   id in the other page so i dont have to connect into mysql again.
   is it possible for me to do that ?
   anybody could tell me the different between persistence connection
   or not ? and how the implementation ?

   TIA


 --
 Best regards,
  andrie  mailto:[EMAIL PROTECTED]



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Re: [PHP-DB] Going bonkers again ...

2001-03-23 Thread JJeffman

A good advice is put an error checker after every mysql command, this way
you can track errors :

 ?php   file://view jobs script
 include("../includes/connect.inc.php"); file://connect to the
database
 $query = "SELECT m_sender, m_date, m_subject FROM messages WHERE m_id =
 '$m_id'";
 $result = mysql_query($query , $mysql_link) or die (mysql_error());
 $summary = mysql_fetch_row($result) or die (mysql_error());
 $m_sender = $summary[0];
 $m_date = $summary[1];
 $m_subject = $summary[2];
 ?

Let me ask you, is $m_id a character or a integer variable, if integer get
the " ' " off and the query will run ok.

HTH.

Jayme.

-Mensagem Original-
De: Martin Skjldebrand [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de maro de 2001 16:15
Assunto: [PHP-DB] Going bonkers again ...


 Going bonkers again ...
 I have this in a script.

 ?php   file://view jobs script
 include("../includes/connect.inc.php"); file://connect to the
database
 $query = "SELECT m_sender, m_date, m_subject FROM messages WHERE m_id =
 '$m_id'";
 $result = mysql_query($query , $mysql_link);
 $summary = mysql_fetch_row($result);
 $m_sender = $summary[0];
 $m_date = $summary[1];
 $m_subject = $summary[2];
 ?

 Where m_id is passed to the page and connect.inc.php is my database
 connection script which works nicely with all other pages. Still I get:

 Warning: Supplied argument is not a valid MySQL-Link resource in
 /chroot/htdocs/helpdesk/scripts/viewmessage.scp.php on line 7

 Warning: Supplied argument is not a valid MySQL result resource in
 /chroot/htdocs/helpdesk/scripts/viewmessage.scp.php on line 8

 When running this in Mozilla.
 What can produce this and how do I track the error?

 M.

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Re: [PHP-DB] PHP Mail - Webmail ??

2001-03-23 Thread JJeffman

I don't know if you need a special class to send an email, the php mail
function do this in a way you can read it on every browser or email program
.

HTH

Jayme.
-Mensagem Original-
De: Xsarus Internetdiensten [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de maro de 2001 18:55
Assunto: [PHP-DB] PHP Mail - Webmail ??


Huy,

how to build mails in PHP with txt-mails AND HTML-mails AND visible in
Webmail (like Hotmail, USANet)

With the class below I can only make HTML-mails readable in Outlook etc.

Why are the mails not shown in USANet?
Daniel Kieviet
Xsarus Internetservices
Holland
[EMAIL PROTECTED]
http://www.xsarus.nl





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Re: [PHP-DB] RE: [PHP] Printing MySQL into HTML Tables

2001-03-23 Thread JJeffman

Congratulations !! Very good solution ! Simple and efficient !

Cheers,

Jayme.

-Mensagem Original-
De: Michael Rudel [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]; 'PHP-DB mailinglist' [EMAIL PROTECTED];
[EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de maro de 2001 08:29
Assunto: RE: [PHP-DB] RE: [PHP] Printing MySQL into HTML Tables


 Or try this one, its simple but more universal and very usefull for eg.
testing.
 ... and a bit mor structured 8)=)

 ?php
   function result_all( $sql_result )
   {
  echo "TABLE\n";

  $columns = mysql_num_fields( $sql_result );

  for ( $i = 0; $i  $columns; $i++ )
  {
 echo "   TH ".mysql_field_name( $sql_result, $i )."
/TH\n";
  }

  while ( $row = mysql_fetch_row( $sql_result ) )
  {
 echo "   TR\n";

 for ( $count = 0; $count  $columns; ++$count )


echo "  TD ".$row[$count]." /TD\n";
 }

 echo "   /TR\n";
  }

  echo "/TABLE\n";
   }
 ?

 Greetinx,
   Mike

 Michael Rudel
 - Web-Development, Systemadministration -
 ___

 Suchtreffer AG
 Bleicherstrae 20
 D-78467 Konstanz
 Germany
 fon: +49-(0)7531-89207-17
 fax: +49-(0)7531-89207-13
 e-mail: mailto:[EMAIL PROTECTED]
 internet: http://www.suchtreffer.de



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Re: [PHP-DB] comparison table script

2001-03-22 Thread JJeffman

As you can only navigate record by record through the database table I think
the only way, as far as I know, is to store the record values into array
variables and print it to the page after you'd reached the last record.

HTH

Jayme.

-Mensagem Original-
De: olinux [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]; PHP-DB [EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de maro de 2001 00:52
Assunto: [PHP-DB] comparison table script


I would like to make a comparison script that will compare two items. Here
is an example and my "halfway" there solution. [at least i think so

Here is my table [for the sake of this example]

+-+
|  car_ID   |make   |   model   |   color   |
+-+
|  |   |   | |
|  |   |   | |
|  |   |   | |
|  |   |   | |
||_|||


I would like the user to be able to select two or more cars to be compared
[these will be passed from an html form as car_ID
Table will be laid out something like this.

+-+
|  |Car 1   |   Car 2|   Car 3 |
+-+
|  car_ID   |123  |234 |   345 |
+-+
|  make|honda  |   honda   |   ford |
+-+
|  model   |civic |   civic  |  tempo |
+-+
|  color |black   |   blue  |   red |
+-+

basically the table is just displayed with fields and records transversed
[switched]

Now i select the info for the two cars, and $result holds the finished query

OK now to display it.

the first while loop will write the rows.

$table = "TR";

while ($row = mysql_fetch_array($result)) {
   $carID = $row['carID'];
   $make = $row['make'];
   $model = $row['model'];
   $color = $row['color'];

$table .= "TDCar ID/TDTD$car_ID[1]/TD";

2nd while loop - writes TD's which vary based on number of carID's
selected
It will loop until all cars have been included

somehow i need to change $carID[1] to $carID[2]
so I need some help on the best way to do this...
After i am able to do this I will loop thru until it does not exist, in the
case of the table above it would be $car_ID[4]
$next will represent previous number of the array +1

/* start of second while or if/for loop */
if ($car_ID[$next] != "")
  $table .= "TD$car_ID[$next]/TD";

So basically that is as far as i have got. I would appreciate if anyone can
provide some direction

Thanks much,
olinux






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Re: [PHP-DB] class method

2001-03-20 Thread JJeffman

I need a little more information to help you.
Is the $query variable a global one ? Or is it a property of the class ( var
$query; )  ?
Why are you assigning the "mysql_fetch_array" function to a variable if call
it is easier ?

You have misplaced the "if $result" statement, the right position, I think ,
is :

function getdata() {
$this-sql = $query;
$result = mysql_query($query);
if( $result ) { // Check if $result is valid instead of NOT valid
   // $fetch = "mysql_fetch_array";
   while ($row = mysql_fetch_array($result)) {
 $this-field = $row['$this-field'];
}
}
else  $this-error = mysql_error();
return;
}

HTH

Jayme.

www.conex.com.br/jjeffman/antispam.html

-Mensagem Original-
De: bryan [EMAIL PROTECTED]
Para: db [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de maro de 2001 16:21
Assunto: [PHP-DB] class method


I am really new working with classes.  Some of the ideas I am getting, some
I am not.
I wrote this simple little class, with a connection method, and a method to
loop through the
data.  I am not even sure if my code is write (for the loop), but I am
having trouble
displaying the data.  My connection works fine, but my loop is jacked.
Could anyone
suggest or maybe correct a mistake (if you see any)?  Just looking to see if
I am
started in the right direction, or if I have this all bass ackwards.
I have no clue if this is even possible.  I am looking to create a while
loop for whatever
query I run, and make each row equal to whatever field I put in.  I have all
variables
defined within the scope of my class.

Thanks for your help.

Code :

function getdata() {

$this-sql = $query;

$result = mysql_query($query);

$fetch = "mysql_fetch_array";

 while ($row = $fetch($result)) {

 $this-field = $row['$this-field'];

 }

 if(!$result) {

  $this-error = mysql_error();

 return;

}

}

**
End

thanks!!!

[ bryan fitch . programmer . [EMAIL PROTECTED] ]






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Re: [PHP-DB] Dynamically build a form from mySQL table

2001-03-20 Thread JJeffman

If you are using MySQL you can use the "mysql_list_fields" to get the fields
names from a table.

HTH

Jayme.

-Mensagem Original-
De: Martin E. Koss [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de maro de 2001 12:02
Assunto: [PHP-DB] Dynamically build a form from mySQL table


 Hi,
 I've been trying to figure this out by looking through the code in
 phpMyAdmin but I'm not getting very far.

 What I want to do is dynamically generate a form where I get a table row
 containing the field name in one cell and the input field in the next
cell,
 for example:

 $DatabaseName = "FocusDynamics";
 $TableName = "Items";

 // open the table and get all field names, sizes, etc.,

 // for each Field name, print something like:

 PRINT "tr\n";
 PRINT "td$FieldName/td\n";
 PRINT "tdinput type=\"text\" name=\"$FieldName\" value=\"$FieldValue\"
 maxlength=\"FieldSize\"/td\n";
 PRINT "/tr";

 How do I get all this info from the table?

 Thanks for any help.


 Martin E. Koss
 M: 07946-706459
 E: [EMAIL PROTECTED]


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Re: [PHP-DB] No. of Users online right now?

2001-03-20 Thread JJeffman

Have a look on Sessions. You can also write to a database every time a new
visitor runs into your site and check if the other are still connected.

You have to create a script that tracks every movement of the visitor. It is
not a simple script. As far as I know the web server doesn't give you this
information .

HTH.

Jayme.

-Mensagem Original-
De: Dan Eskildsen [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de maro de 2001 07:46
Assunto: [PHP-DB] No. of Users online right now?


 Hi there,

 This is a NewBie Question:
 While out surfing I have often seen a message like:  "There are 17 users
on
 this site at the moment."

 Can I do this with php?  Just to show how many people are on (browsing)
the
 site at that moment?  I run a community website.

 Thanks

 ==
 Regards from Denmark, Europe
 Please cc your reply to [EMAIL PROTECTED]
 ==
 I haven't lost my mind, I've got it backed up on TAPE somewhere...



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Re: [PHP-DB] if () and () - newbie Q

2001-03-17 Thread JJeffman

Try the "empty($variable)" function.

HTH

Jayme.

-Mensagem Original-
De: Michael Gerholdt [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sbado, 17 de maro de 2001 23:12
Assunto: [PHP-DB] if () and () - newbie Q


 Why won't this work for me?

 if (($rectype == 'events') and ($action == '') and ($manage == '')){}

 I've also tried

 if ($rectype == 'events') and ($action == '') and ($manage == ''){}

 I want to have differences between this and something like:

 if (($rectype == 'events') and ($action == 'add') and ($manage == 'some'))

 Also -

 what about something like 'isNull' ? I don't see any documentation in the
 PHP online manual nor is 'null' even mentioned in the index of my Core PHP
 book.

 Regards,
 Michael Gerholdt
 SUNY College at Fredonia


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Re: [PHP-DB] Help w/ displaying return vals

2001-03-14 Thread JJeffman

Use  mysql_function(...) or die( mysql_error())  on every mysql function
or command you're performing, this will tell you what is going wrong .

HTH

Jayme.

-Mensagem Original-
De: [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Enviada em: quarta-feira, 14 de maro de 2001 19:47
Assunto: [PHP-DB] Help w/ displaying return vals


 Here's my php program, I think $result never gets assigned a value,
staying
 null or whatever.

 $link = mysql_connect("host");

 mysql_select_db("dbname");

 $result = mysql_query ("SELECT * FROM table");

 $fields = mysql_num_fields ($result);
 $rows = mysql_num_rows ($result);

 $table = mysql_field_table ($result, $i);

 echo "Your '".$table."' table has ".$fields." fields and ".$rows." records
 BR"

 - - EOP - -

 The problem comes on the lines that reference the variable $result.

 I keep getting this in the browser... leading me to believe that $result
is
 null:

 Warning: Supplied argument is not a valid MySQL result resource


 help!

 Thankx0r

 Ryan




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Re: [PHP-DB] 2 while loops - 2 tables

2001-03-14 Thread JJeffman

If the tables have a one to many relationship you can use nested while
loops:

while(1st loop){
// display header - master table
while(2nd loop){
// display features  - detail table

}
}

HTH

Jayme.


-Mensagem Original-
De: olinux [EMAIL PROTECTED]
Para: PHP-DB [EMAIL PROTECTED]
Enviada em: quinta-feira, 15 de maro de 2001 01:05
Assunto: [PHP-DB] 2 while loops - 2 tables


I am trying to display info from 2 tables in a search result format.
My problem is... how do I get the variables to display together?

for example:
A user selects a city to search apartments in.

$sql = "SELECT * FROM $table_name WHERE apt_city = \"$apt_city\"
  ";
$result = mysql_query($sql, $connection);

while ($row = mysql_fetch_array($result)) {
 $aptID = $row['aptID'];
 $apt_address1 = $row['apt_address1'];
 $apt_address2 = $row['apt_address2'];
 $apt_zip = $row['apt_zip'];
}

while ($row = mysql_fetch_array($result)) {
 $apt_ID = $row['apt_ID'];
 $feature1 = $row['feature1'];
 $feature2 = $row['feature2'];
 $feature3 = $row['feature3'];
}


Now I want to display the approriate data from the apartment next to the
features.
so What I am wondering is how can i "group" the appropriate features with
the correct apartment
 so say a result may look like this [HTML table]
__
Apartment 1  |   feature1
apt_address1  |   feature2
apt_address2  |   feature3
_|_
Apartment 2  |   feature1
apt_address1  |   feature2
apt_address2  |   feature3
_|_
Apartment 3  |   feature1
apt_address1  |   feature2
apt_address2  |   feature3
_|_

Should the 2nd while loop be placed inside the first?

while ($row = mysql_fetch_array($result)) {
  $aptID = $row['aptID'];
  $apt_address1 = $row['apt_address1'];
   $apt_address2 = $row['apt_address2'];
   $apt_zip = $row['apt_zip'];
while ($row = mysql_fetch_array($result)) {
  $apt_ID = $row['apt_ID'];
  $feature1 = $row['feature1'];
  $feature2 = $row['feature2'];
  $feature3 = $row['feature3'];
}
$table_block .= "[ this contains HTML code for table rows to display
data ]";
}

Thanks Much!

olinux




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Re: [PHP-DB] (Newbie) how to evaluate a varying number of db generated checkboxes?

2001-03-07 Thread JJeffman

If you have a way to decide which checkboxes have to be checked, just set
its attribute like the line bellow:
INPUT TYPE="checkbox" NAME="" ?PHP if($condition) echo("CHECKED");? 

HTH

Jayme.

-Mensagem Original-
De: jester [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: quarta-feira, 7 de maro de 2001 14:00
Assunto: [PHP-DB] (Newbie) how to evaluate a varying number of db generated
checkboxes?


 I'm generating a html form with php and a MySQL database.
 My code generates a varying number of checkboxes depending on the number
of
 'options' in my database. The name of the checkbox is set to the -id- of
the
 'option' in my database. When the generated form is posted I want to show
a
 page showing a overview of the 'options' checked. But how do I check if
that
 varying number of checkboxes is 'checked' ??


 db connect and query, result of query is placed in: $result .

 while($row=mysql_fetch_array($result))
 {
 print("form method=\"post\" action=\"formhandler.php\"");
 $optionID=$row["id"];
 $optionDescription=$row["description"];
 print("input type=\"checkbox\" name=\"$optionID\"
 $optionDescriptionbr\n");
 print("/form");
 }


 But how can I get this 'unknown' number of checkboxes in my next page and
 evaluate if they are checked so I can leave out the unchecked ones in my
 overview.




 Who can help me with this problem?!

 Thanx!
 H. de Visser



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Re: [PHP-DB] mail server

2001-03-07 Thread JJeffman

I'm not sure but I think you must have a smtp server program running to
configure as your smtp server.

HTH.

Jayme.


-Mensagem Original-
De: Free Beachler [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: quarta-feira, 7 de maro de 2001 14:48
Assunto: [PHP-DB] mail server


 hi all,
  is there any way i can specify my own smtp server and override the
 php.ini file?  i want to use
 the mail command on my host and i keep getting this error:

 Warning: Unknown error in
 D:\inetpub\nextepmedia\www\nexteplaunch\test_email.php on line 2

 

 i just have a simple php file with a mail command to mail to me, something
 like:

 mail('[EMAIL PROTECTED]', 'test email', 'line1\nline2\line3');

 

 anyway, i'm on this NT host and they're not that good.  instead of having
 them go into their php.ini file and see what's wrong i want to set my own
 server (in the script) to point to our host's SMTP server.

 -f



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Re: [PHP-DB] MySQL - Problem with multiple INSERTs?

2001-03-06 Thread JJeffman

Try this changes:

$con_id = mysql_connect("localhost", "myusername", "mypassword");
if($con_id){
mysql_db_query("DocCountry", "INSERT INTO projects (idCreator, name,
comment) VALUES (0, 'sysmsg9.txt', 'Some file')");
mysql_db_query("DocCountry", "INSERT INTO files (idProject, name,
comment) VALUES (0, 'sysmsg9.txt', 'Some file')");
}
else echo("Connection failed");

-Mensagem Original-
De: Chris [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 6 de maro de 2001 16:13
Assunto: Re: [PHP-DB] MySQL - Problem with multiple INSERTs?


 I did change the id fields from TINYINT to INT (that was just a careless
 error), and fixed something else. But I still have the same problems. The
 new table schemas are below, along with the queries that don't work.

 I'd love for someone to reproduce the error. As a possible workaround,
 everything seems to be fine when I prime the tables by adding a record;
 they only seem to have a problem when the tables are empty.

 Thanks,
 Chris



 mysql_connect("localhost", "myusername", "mypassword");
 mysql_db_query("DocCountry", "INSERT INTO projects (idCreator, name,
 comment) VALUES (1, 'sysmsg9.txt', 'Some file')");
 mysql_db_query("DocCountry", "INSERT INTO files (idProject, name, comment)
 VALUES (1, 'sysmsg9.txt', 'Some file')");

 CREATE TABLE projects ( id int(11) NOT NULL auto_increment, timestamp
 timestamp(14), idCreator int(11) DEFAULT '0' NOT NULL, name varchar(80)
NOT
 NULL, comment text NOT NULL, authLevel varchar(32) NOT NULL, PRIMARY KEY
 (id) );

 CREATE TABLE files ( id int(11) NOT NULL auto_increment, idProject int(11)
 DEFAULT '0' NOT NULL, idCreator int(11) DEFAULT '0' NOT NULL, name
 varchar(80) DEFAULT '0' NOT NULL, comment text NOT NULL, PRIMARY KEY
(id) );



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Re: [PHP-DB] detect cookies

2001-03-06 Thread JJeffman

I've never used but there is a php function "get_browser()" which might do
the work.
I think the best way is set the cookie and try to get it again, if you can
get it the user has cookies enabled.

setcookie("name",value,$cookieLifeTime,$cookiePath);
if($name) echo("Cookie is enabled");

HTH

Jayme.

-Mensagem Original-
De: andrie [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 6 de maro de 2001 18:34
Assunto: [PHP-DB] detect cookies


 Hello php-db,

   can i detect weather user has enable or not their cookies ?
   or is there any function that can read browser setup ?

 --
 Best regards,
  andrie  mailto:[EMAIL PROTECTED]



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Re: [PHP-DB] mysql_fetch_array problem...!

2001-03-05 Thread JJeffman

You must use a loop to show each row of your query.
"mysql_fetch_array($result)" only get the current row.

while($row = mysql_fetch_array($result) ){

// do something

}

The "mysql_fetch_array" function returns an associative array where you can
use the field names  to have access to its value :

$row = mysql_fetch_array($result) ;
$v1 = $row["fieldname1"] ;
$v2 = $row["fieldname2"] ;
$v3 = $row["fieldname3"] ;

You're going to  use the alias names you are creating on the query.

See more details on php manual at mysql functions.

HTH.

Jayme.

-Mensagem Original-
De: Trond Erling Hundal [EMAIL PROTECTED]
Para: PHP-DB-LIST [EMAIL PROTECTED]
Enviada em: segunda-feira, 5 de maro de 2001 09:56
Assunto: [PHP-DB] mysql_fetch_array problem...!


 I want to run a query to my db, fetching different fields from three
 different tables.
 In order to recognise the individual fields I give them names:

 select portal.portal as portal, portal.portalid as id... etc etc


 How can I refer to one specific row in this query..?
 What I mean is, how can i refer to result row number 4...?

 If I only selected rows from one table I could do something like this:

 $i = mysql_fetch_array($sql) ;

 echo "$i[4]" ;




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Re: [PHP-DB] MySQL - Problem with multiple INSERTs?

2001-03-05 Thread JJeffman

Have you put an echo with mysql_error() after performing each query ?

Jayme.


-Mensagem Original-
De: Chris [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: segunda-feira, 5 de maro de 2001 05:04
Assunto: [PHP-DB] MySQL - Problem with multiple INSERTs?


 Howdy,

 I'm getting weird problems trying to INSERT to two different tables, in
 consecutive mysql_queries. Before, I had 3 queries going, and only 2 would
 work at any time. It seemed like it was 'rotating' the bad query - first
 the 1st query would fail (the other two were fine), then I'd empty all my
 tables and refresh, and this time the 2nd query was the problem, and if I
 did it again the 3rd was. All queries worked fine in phpMyAdmin, both
 individually and when executed en masse.

 I've boiled it down to just two queries that don't work. I've included
 everything below (including table schemata), to enable reproduction. It
 seems like a bug to me - the question is, is the bug in PHP, MySQL, or my
 brain?

 This is driving me CRAZY
   - Chris

 mysql_connect("localhost", "myusername", "mypassword");
 mysql_db_query("DocCountry", "INSERT INTO projects (idCreator, name,
 comment) VALUES (1, 'sysmsg9.txt', 'Some file')");
 mysql_db_query("DocCountry", "INSERT INTO files (idProject, name, comment)
 VALUES (1, 'sysmsg9.txt', 'Some file')");

 CREATE TABLE projects ( id int(11) NOT NULL auto_increment, timestamp
 timestamp(14), idCreator int(11) DEFAULT '0' NOT NULL, name varchar(80)
NOT
 NULL, comment text NOT NULL, authLevel varchar(32) NOT NULL, PRIMARY KEY
 (id) );

 CREATE TABLE files ( id tinyint(4) NOT NULL auto_increment, idProject
 tinyint(4) DEFAULT '0' NOT NULL, name tinyint(4) DEFAULT '0' NOT NULL,
 comment text NOT NULL, PRIMARY KEY (id) );

 (P.S. I've tried things like using SET syntax, using mysql_query instead
of
 mysql_db_query, etc. Nothing helps.)


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Re: [PHP-DB] Insert a file in a mysql database!

2001-03-03 Thread JJeffman

Look for "load in file" on MySQL manual.

HTH.

Jayme.

-Mensagem Original-
De: Pedro M. S. Oliveira [EMAIL PROTECTED]
Para: PHP db [EMAIL PROTECTED]
Enviada em: sbado, 3 de maro de 2001 18:03
Assunto: [PHP-DB] Insert a file in a mysql database!


 Hi all...
 Here i am once again asking for advice :)
 well i need to put a file (something lika *.doc or *.rtf) on a mysql
 database.
 The thing is: the user need to upload a computer file to the mysql runing
 over a linux box.

 i would like to know:
 1) what is the best way to do this?
 2) what is the html code i have to generate do do this?
 3) how can i read this back from the database?

 i read something about sending the file over ftp and then on the database
 put just the path to the file.
 but what is your opinion?
 thankx



 ***
 Pedro Miguel Silva Oliveira
 Cell Phone: +351 96 5867227
 SMS: [EMAIL PROTECTED]
 Email: [EMAIL PROTECTED]


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Re: [PHP-DB] How do I keep the selected showing...

2001-03-03 Thread JJeffman

Use the "selected" attribute of the option tag when you load the second
page, marking the place the user had chosen :
option .
option ...
option selected value="g"City G
option...

HTH

Jayme.


-Mensagem Original-
De: Dave Carrera [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sbado, 3 de maro de 2001 04:29
Assunto: [PHP-DB] How do I keep the selected showing...


 Hi All
 I have a fully functional db site which uses 2 sqls and 1 page to give our
 visitors info they need.

 That works fine, but some users have remarked that it would be nice that
the
 selected item from our drop down list stays shown when the page gives the
 info instead of going back to the top of the list.

 http://www.angelettes.co.uk/dates/index.php3 is the url in action and
 choosing different towns will show you what I mean.

 Its not the end of the world, as our visitors have said, but would be
nice.

 Any help is full appreciated.

 Dave C


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Re: [PHP-DB] Selecting number of news items on frontpage

2001-03-01 Thread JJeffman

David Siegel in "Creating Killer Web Sites" 1st edition said frames are good
only for show details of a list of objects like recipes, products or in your
case news!
You can have a frameset with three frames say top, left and main (center).
Put some ad on the top , the headlines of your news on the left and its
bodies on the main frame .
You can limit the number of headlines using the keyword "limit" ( see MySQL
manual ) and put a anchor tag in every headline to a php script passing the
"news_id" and show the selected new on the main frame.

HTH

Jayme.

-Mensagem Original-
De: Matthew Cothier [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: quarta-feira, 28 de fevereiro de 2001 13:13
Assunto: [PHP-DB] Selecting number of news items on frontpage


 I have a homepage which has a news headline system. Bascially via form the
 admin of the site can submit news which appears on the front page, the
only
 problem is the news just keeps coming and I have a front page with too
many
 headlines on.

 How can I make it so that say 7 articles appear on the front page and the
 rest can be accessed through some sort of archive?

 Perhaps a link underneath these articles to the archive?

 And the actual archive a page with the headlines listed that they can
click
 on and view the story, the headlines listed in date order.

 How would I do this?
 _
 Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com.


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Re: [PHP-DB] Drop down box

2001-03-01 Thread JJeffman

The event "OnChange" only happens when the user open the drop down list and
change ( select ) a new value, this is not "just looking" .

I don't like this kind of solution. If I have to put a button on the page I
think the selection list must disappear. Why not give the user a interface
with less "clicks"? May be we can reach another interface approach which
turn it possible.

Jayme.


-Mensagem Original-
De: Ron Brogden [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: quinta-feira, 1 de maro de 2001 18:48
Assunto: Re: [PHP-DB] Drop down box


 At 06:32 PM 3/1/2001 -0300, you wrote:
 The action you want is only available using JavaScript.

 True but the action *you* want is most definitely not what many of your
 *users* are going to want.  If you use Javascript this way your site will
 be un-navigable if Javascript is turned off or the browser does not
support
 it.  What's the big deal about a single button click?  Also, using
 Javascript this way means that if a user is just curious what the choices
 are, you force a refresh without them necessarily wanting one.

 IMHO of course.

 Cheers

 --
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Re: [PHP-DB] onMouseOver onMouseOut

2001-02-24 Thread JJeffman

Are you trying to tell Rudi Ahlers is possible to call php scripts from a
browse event ? The statement "form.submit()" belongs to JavaScript not to
php.

Can you imagine how boring is have to submit forms and reload pages every
time  the user make changes on a drop down menu?

I know you're right about disable JavaScript on the browser but I think
security matters are more applicable to MS Active X which even writes to
your HD, as far as I know JavaScript  is not allowed to do that.

Of course you can't make password validation client side, there is no data
security client side.

I think academic and radical positions aren't good at all. You should deal
with the real world where you have the give the user as much comfort as you
can. Applications don't have proper life, they are created for been used, so
the user is always the king.

-Mensagem Original-
De: Ron Brogden [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de fevereiro de 2001 18:40
Assunto: Re: [PHP-DB] onMouseOver  onMouseOut


 At 06:27 PM 2/23/2001 -0300, you wrote:
 Remember, php is server side while JavaScript is client side. You can't
use
 php client side. You can use some client side events to call php scripts
 which will run on the server and send data to the browser. Events are
client
 side, so try JavaScript you'll enjoy it too.

 Also keep in mind that Javascript should *never* be relied upon for input
 validation.

 It is trivial to disable Javascript on the client side (and there are very
 good reasons for doing so, drop by www.securityfocus.com sometime for
 reasons why) and you cannot trust any data that comes from the end user.
I
 personally would never recommend Javascript "crippling" your site - it
 should run perfectly without it since support varies from browser to
 browser (not everyone uses the latest version of IE) and you have no
 guarantee that it will be enabled client side at all. That's not even
 getting into people building URLs by hand for "kicks". Since you have to
 perform input validation server side anyway, this makes Javascript pretty
 much useless for this purpose.

 Javascript is really only useful for display effects that do not affect
 accessibility which means they should be avoided most of the time just
like
 Macromedia Flash, Quicktime, etc. unless you are 100% sure your audience
 meets your site's requirements exactly.

 All IMHO of course.

 Cheers,

 Ron


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 1412 Quadra  Toll Free:1 800
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Re: [PHP-DB] onMouseOver onMouseOut

2001-02-23 Thread JJeffman

Remember, php is server side while JavaScript is client side. You can't use
php client side. You can use some client side events to call php scripts
which will run on the server and send data to the browser. Events are client
side, so try JavaScript you'll enjoy it too.

HTH

Jayme.
-Mensagem Original-
De: Rudi Ahlers [EMAIL PROTECTED]
Para: PhP List [EMAIL PROTECTED]
Enviada em: sexta-feira, 23 de fevereiro de 2001 14:00
Assunto: [PHP-DB] onMouseOver  onMouseOut


 Is there such a function for PhP ?
 I want to replace some javasctiripts with PhP, but there are quite a few
 onmouseover events.

 Thank you
 Rudi


 "Opinions expressed do not necessarily
 represent the views of my employer."




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Re: [PHP-DB] nl2br()

2001-02-22 Thread JJeffman

Look for "nl2br()" on the php manual. There is more information there.
Any way you can store text fields as the user has typed it in, when you are
about to show them what they wrote you get text from database and apply the
function on the result before put it in a html tag.

select * ...
...

$text_ready = nl2br($row["text"]) ;


HTH.
Jayme.

-Mensagem Original-
De: Matthew Cothier [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: quarta-feira, 21 de fevereiro de 2001 18:11
Assunto: [PHP-DB] nl2br()


 Where exactly do I need to insert this?
 _
 Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com.


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Re: [PHP-DB] next previous record

2001-02-22 Thread JJeffman

I don't know about "Cursors" but I think you can use the same approach we
discussed on navigate record by record, " retrieval of NEXT, PREV records"
was the subject.

If set an order by clause and search for the first record you can use a
where clause like this :
...
$current = $row["field"] ;
// for next row
$query = "select * from table where field_name  '$current' limit 1";
// for previous row
$query = "select * from table where field_name  '$current' limit 1";

HTH

Jayme.
www.conex.com.br/jjeffman/antispam.html

-Mensagem Original-
De: Andrew Hill [EMAIL PROTECTED]
Para: Dreamvale [EMAIL PROTECTED]; [EMAIL PROTECTED]
Enviada em: quinta-feira, 22 de fevereiro de 2001 14:10
Assunto: RE: [PHP-DB] next  previous record


 You want to use Cursors, and I don't believe MySQL supports cursors yet,
 although I could be wrong.

 Best regards,
 Andrew
 --
 Andrew Hill - OpenLink Software
 Director Technology Evangelism
 eBusiness Infrastructure Technology
 http://www.openlinksw.com


  -Original Message-
  From: Dreamvale [mailto:[EMAIL PROTECTED]]
  Sent: Thursday, February 22, 2001 11:42 AM
  To: [EMAIL PROTECTED]
  Subject: Re: [PHP-DB] next  previous record
 
 
  I was not refering pagination.
 
  suppossing there are these 3 records
 
  ABC
  DEF
  GHI
  LJK
 
  now a search is done by entering D, which using like  %, and limit
would
  return the record DEF. The "next" would forward to GHI and
  "previous" would
  backward to ABC.
 
  any idea?
 
  thanks.
 
 
  - Original Message -
  From: "Brunner, Daniel" [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Friday, February 23, 2001 12:12 AM
  Subject: FW: [PHP-DB] next  previous record
 
 
Check this link out...
   
http://www.oreillynet.com/pub/a/php/2000/11/02/next_previous.html?page
=1
   
It's about Next/previous links...
   
It does work, but I've yet to get to get it to work completely with
displaying the records (rows) and the links at the same time...
   
It just takes some time to find how to use the mysql_query variable
to
print out the rows, with every click of the link..
   
If you get any head way let me know...
   
It's great code
   
Dan
   
   
   
--
From: Dreamvale
Sent: Thursday, February 22, 2001 9:55 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] next  previous record
   
hi all,
   
need to implement record scrolling, one at a time -either forward or
backward, on MySQL. The key is a char (32) containing part numbers.
   
anyone has done this before?
   
thanks in advance.
   
dreamvale
   
   
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Re: [PHP-DB] retrieval of NEXT, PREV records

2001-02-21 Thread JJeffman

As far as I know, if you do not set any special order, the table is ordered
by primary key, isn't it ?

Jayme.


-Mensagem Original-
De: Chris Book [EMAIL PROTECTED]
Para: JJeffman [EMAIL PROTECTED]; Adv. Systems Design
[EMAIL PROTECTED]; [EMAIL PROTECTED]
Enviada em: quarta-feira, 21 de fevereiro de 2001 11:16
Assunto: RE: [PHP-DB] retrieval of NEXT, PREV records


 you have to make sure you order by Rec_id all the time too.

 -Original Message-
 From: JJeffman [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, February 20, 2001 4:39 PM
 To: Adv. Systems Design; [EMAIL PROTECTED]
 Subject: Re: [PHP-DB] retrieval of NEXT, PREV records


 "SELECT * FROM Table WHERE Rec_id  $recid LIMIT 1" always bring you the
 next record no matter the Rec_id is.

 HTH

 Jayme.

 -Mensagem Original-
 De: Adv. Systems Design [EMAIL PROTECTED]
 Para: [EMAIL PROTECTED]
 Enviada em: tera-feira, 20 de fevereiro de 2001 11:41
 Assunto: [PHP-DB] retrieval of NEXT, PREV records


  I have set up links to browse records one by one,
  using (ID+1) for NEXT and (ID-1) for PREV...the only
  problem is that if there is a hole in the ID sequence
  (as from DELETION), there is no record returned...How
  can I have it so that the 'holes' are paved over and
  not returned?
 
  TIA
 
  Luis
 
  __
  Do You Yahoo!?
  Get personalized email addresses from Yahoo! Mail - only $35
  a year!  http://personal.mail.yahoo.com/
 
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Re: [PHP-DB] retrieval of NEXT, PREV records

2001-02-21 Thread JJeffman

I'm sorry I haven't noticed that. I couldn't believe, then I tried to create
and make some delete-insert operations and the primary key order has gone
away. Thanks a lot. One more lesson I learned.

Jayme.


-Mensagem Original-
De: Sweep the Net [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: quarta-feira, 21 de fevereiro de 2001 19:06
Assunto: RE: [PHP-DB] retrieval of NEXT, PREV records


 It would only be ordered that way if you had not
 deleted any records and added new ones.  IF there
 are ones deleted, the next ones frill in the space.

 Bob



 At 05:00 PM 2/21/01 -0500, you wrote:
 Perhaps it is ordered that way, perhaps not, but live by the creed
"Expect
 nothing and you will never be disappointed."
 
 Go ahead and specify the order you demand.
 
 
   -Original Message-
   From: JJeffman [mailto:[EMAIL PROTECTED]]
   Sent: Wednesday, February 21, 2001 4:40 PM
   To: [EMAIL PROTECTED]
   Subject: Re: [PHP-DB] retrieval of NEXT, PREV records
  
  
   As far as I know, if you do not set any special order, the table
   is ordered
   by primary key, isn't it ?
  
   Jayme.
  
  


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Re: [PHP-DB] retrieval of NEXT, PREV records

2001-02-20 Thread JJeffman

"SELECT * FROM Table WHERE Rec_id  $recid LIMIT 1" always bring you the
next record no matter the Rec_id is.

HTH

Jayme.

-Mensagem Original-
De: Adv. Systems Design [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de fevereiro de 2001 11:41
Assunto: [PHP-DB] retrieval of NEXT, PREV records


 I have set up links to browse records one by one,
 using (ID+1) for NEXT and (ID-1) for PREV...the only
 problem is that if there is a hole in the ID sequence
 (as from DELETION), there is no record returned...How
 can I have it so that the 'holes' are paved over and
 not returned?

 TIA

 Luis

 __
 Do You Yahoo!?
 Get personalized email addresses from Yahoo! Mail - only $35
 a year!  http://personal.mail.yahoo.com/

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[PHP-DB] Array element as object.

2001-02-20 Thread JJeffman

I've already made an object which had a property that was an array. Now I
need to have an array that can hold objects as its elements is It possible ?
I didn't get it the expression array[$i]-Object gave me syntax error. Any
tips ?

[]'s

Jayme.

http://www.conex.com.br/jjeffman





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Re: [PHP-DB] Drop-down menu selection

2001-02-20 Thread JJeffman

You need mix JavaScript and PHP. Write an "OnChange" event handler for the
"campus" selection list and fill up the "buildings" drop-down menu in two
ways:

1) If the amount of data is not very large you can get all data needed to
run
the "application" client side, load the data into JavaScript arrays and
refresh the select boxes using JavaScript scripts. Otherwise you must reload
the page and process the values posted by the form.

2) Reload the same page (window.location="self.php?campus=value") and run
your php script to fill up the "buildings" drop-down menu.

HTH.

Jayme.


-Mensagem Original-
De: Julio Cuz, Jr. [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 20 de fevereiro de 2001 21:44
Assunto: [PHP-DB] Drop-down menu selection


 Hi--

 I hope all of you are having a great long weekend!

 Let's say I have four (4) tables:

 - "campus" that holds all my campuses' names (only 3),
 - "building_campus1" that holds all buildings for 'campus1',
 - "building_campus2" that holds all buildings for 'campus2',
 - "building_campus3" that holds all buildings for 'campus3'.

 If the user selects "campus 1" from a drop-menu, how can I select
 "buildings for campus 1" on a second drop-down menu?  In other words, how
 do I select the corresponding "building's table" when any "campus" is
selected?

 Thanks!

 P.S.  I have tried the 'onChange' command, but I guess I got the syntax
wrong:

 =
 // $campus:
 ?php
 echo("SELECT onChange='building.value = building.this.value'
NAME='campus'");
 $cmlist = @pg_exec($db, "SELECT * FROM \"Campus\"") or
 die(include("../sqlerror.inc"));
 $i = 0;
 $x = pg_numrows($cmlist);
 while ($i  $x):
  $clist = pg_fetch_array($cmlist,$i);
  echo "OPTION
 VALUE='".$clist["Campus"]."'".$clist["Campus"]."/OPTION";
  $i++;
 endwhile;
 echo("/SELECT");
 ?

 $building:
 ?php
 echo("SELECT NAME='building'");
 $cmlist = @pg_exec($db, "SELECT * FROM building_$campus") or
 die(include("../sqlerror.inc"));
 $i = 0;
 $x = pg_numrows($cmlist);
 while ($i  $x):
  $clist = pg_fetch_array($cmlist,$i);
  echo "OPTION
 VALUE='".$clist["Building"]."'".$clist["Building"]."/OPTION";
  $i++;
 endwhile;
 echo("/SELECT");
 ?
 =

 Julio Cuz, Jr.
 Riverside Community College
 [EMAIL PROTECTED]


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Re: [PHP-DB] composite keys

2001-02-19 Thread JJeffman

MySQL do support composite keys . Have a look on the mysql database
structure the "columns_priv" table has 5 fields in its primary key.
I think you should use an auto_increment as your primary field instead.

HTH.

Jayme.


-Mensagem Original-
De: Russ Michell [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: segunda-feira, 19 de fevereiro de 2001 11:21
Assunto: [PHP-DB] composite keys


 Hi all:
 I am using php4.0.3pl1 with MySQL 3.22.32 on Apache for RH Linux.

 I have a table/relation of sports, where amongst other categories, are
 teams, where there can be many 'teamNames'  'teamInfos' for one sport.

 The problem here is that without the use of a composite key:
 'sportName'  'TeamName', there can be no method of uniquely
 identifiying a row or tuple. A smuch of the info for each sport is
 repeated.

 Does MySQL support the use of composite keys? I am using phpMyAdmin
 2.1.0 to adminster my MySQL system, and this only seems to accept a
 single primary key for a single table.

 Any advice or other methods I could possibley employ, are most welcome.

 Regards:
 Russ

 #---#

  "Believe nothing - consider everything"

   Russ Michell
   Anglia Polytechnic University Webteam
   http://gertrude.sipu.anglia.ac.uk/webteam
   [EMAIL PROTECTED]
   +44 (0)1223 363271 ext 2331

   www.theruss.com

 #---#


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Re: [PHP-DB] Inserting arrays into a database

2001-02-19 Thread JJeffman

Try use a delimited string and split it on retrieve.

HTH.

Jayme.

-Mensagem Original-
De: Kyle Mathews [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: segunda-feira, 19 de fevereiro de 2001 19:35
Assunto: [PHP-DB] Inserting arrays into a database


 Hello:

 I'm wondering what is the best way to insert an array into a database
table.
 As well as the best way to extract and show that information.

 The information that I'd be inserting is a bunch of id numbers for data in
 another table.
 So when getting the information, I'd like to do a table join so that the
 information displayed is the actual data, and not a bunch of numbers.

 Thanks,
 Kyle


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Re: [PHP-DB] Links On The Fly

2001-02-18 Thread JJeffman

You can pass the "href" as an urlencoded to your php script.

HTH.

Jayme.

-Mensagem Original-
De: Sridhar Ranganathan [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sbado, 17 de fevereiro de 2001 21:40
Assunto: [PHP-DB] Links On The Fly


 Hi All

 I have a search engine which generates a page full of links. Depending on
 the link that was clicked, I want to load info on the fly. How do I do
that?

 Regards
 Sridhar Ranganathan
 _
 Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com.


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Re: [PHP-DB] double posts

2001-02-16 Thread JJeffman

Using a JavaScript function instead of the "action" form property I think is
possible .

HTH.

Jayme.

-Mensagem Original-
De: Marc Bragg [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sexta-feira, 16 de fevereiro de 2001 17:53
Assunto: [PHP-DB] double "posts"



 Is it possible to post to two forms with one click, one post command?
 What would statement look like?


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Re: [PHP-DB] primary field

2001-02-16 Thread JJeffman

No it hasn't. The field order in the form doesn't matter, but the order you
use their values in the query yes !

I don't know what kind of operation you're making on the database
 updating, inserting, etc. ).

If you are inserting you must not give any member_id, as long as it is
generated by the database server. As you won't attribute any value to
member_id you must tell which fields you are inserting : "insert into table
(last_name) values('$lastName')" this way you'll get no errors, at least if
last_name is not a unique key .

If you is updating data you can't modify the member_id which is the table
primary key.

HTH.

Jayme.

-Mensagem Original-
De: Marc Bragg [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sexta-feira, 16 de fevereiro de 2001 17:55
Assunto: [PHP-DB] primary field


 Does the first field in a form have special significance?
 Have two fields in table:

 last_name
 member_id

 member_id is key and autoincrement.

 mysql won't accept two last names as same when last_name is first field.

 when member_id is made first field, then can input same last name into
 last_name field.

 why is that?


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Re: [PHP-DB] Related frames

2001-02-15 Thread JJeffman

How about use "A TARGET='main' HREF=\"" ...

HTH

JAYME.

-Mensagem Original-
De: John Halladay [EMAIL PROTECTED]
Para: PHP DB List (E-mail) [EMAIL PROTECTED]
Enviada em: quinta-feira, 15 de fevereiro de 2001 19:46
Assunto: [PHP-DB] Related frames


 I'm trying to have a link in one frame display data in the main frame.
Here
 is an example of what I have set up.  Normally in HTML you would have
 TARGET="main" in the a href="" /a spot, but I tried that and it gives
me
 a parse error.  Any ideas on how to do it, or does anyone have know of any
 websites that I could check.

 Thanks,
 John Halladay

 html

 body

 ?php

 $db = mysql_connect("localhost", "root");

 mysql_select_db("mydb",$db);

 // display individual record

 if (isset($id)) {

 $result = mysql_query("SELECT * FROM employees WHERE id=$id",$db);

 $myrow = mysql_fetch_array($result);

 printf("First name: %s\nbr", $myrow["first"]);

 printf("Last name: %s\nbr", $myrow["last"]);

 printf("Address: %s\nbr", $myrow["address"]);

 printf("Position: %s\nbr", $myrow["position"]);

 } else {

 // show employee list

 $result = mysql_query("SELECT * FROM employees",$db);

 if ($myrow = mysql_fetch_array($result)) {

 // display list if there are records to display

 do {

 printf("a href=\"%s?id=%s\"%s %s/abr\n", $PHP_SELF, $myrow["id"],
 $myrow["first"], $myrow["last"]);

 } while ($myrow = mysql_fetch_array($result));

 } else {

 // no records to display

 echo "Sorry, no records were found!";

 }

 }

 ?

 /body

 /html

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Re: [PHP-DB] MySQL compacting

2001-02-12 Thread JJeffman

I'm afraid there is no articles on this matter. You are facing a database
design matter.

Auto-increment primary keys must haven't any meaning other than just be the
primary key and relate one table to another, if you had a function to
"update" the auto-increment field to eliminate the holes that function
should manage tables relationships as well. As you can see it'll be very
difficult to implement and probably slows down the script, imagine check all
related tables !

Although you have holes in the sequence, the order between the reminiscent
records will be the same .

Auto-increment fields should not be exposed to the user.

HTH.

Jayme.

http://www.conex.com.br/jjeffman





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Re: [PHP-DB] Writing to a file on the user's machine.

2001-02-07 Thread JJeffman

I think write to the user's machine it's up to him, you can't write to it,
you have to "invite" the user to download the file you created for him on
the server. That's the polished application !

HTH.

Jayme.

http://www.conex.com.br/jjeffman



-Mensagem Original-
De: Gary Robinson [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: tera-feira, 6 de fevereiro de 2001 12:20
Assunto: [PHP-DB] Writing to a file on the user's machine.


 How do I write to a file on the user's machine?  I need to drop a small
file
 to the user's machine after a certain transaction.

 Thanks in advance!

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Re: [PHP-DB] using ID

2001-02-07 Thread JJeffman

What for you need a ID if you have already the username which I guess may a
unique key ?

HTH.

Jayme.

http://www.conex.com.br/jjeffman



-Mensagem Original-
De: Brandon Feldhahn [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: segunda-feira, 5 de fevereiro de 2001 22:00
Assunto: [PHP-DB] using ID


 When i make a table with four field (id, name, username, and password)
 what do i do with the i id, how do i make it assign to each password?


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Re: [PHP-DB] refreshing form select boxes with javascript. possible?

2001-02-07 Thread JJeffman

No, JavaScript is "Client" side, while PHP is "Server" side script, so to
call php scripts you have to make a request to the server.

If the amount of data is not very large you can get all data needed to run
the "application" client side, load the data into JavaScript arrays and
refresh the select boxes using JavaScript scripts. Otherwise you must reload
the page and process the values posted by the form.

HTH.

Jayme.

http://www.conex.com.br/jjeffman



-Mensagem Original-
De: Kepa Lyman [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: quarta-feira, 7 de fevereiro de 2001 22:09
Assunto: [PHP-DB] refreshing form select boxes with javascript. possible?



 Hi,

 I have a MySQL database that contains a table of composer names/ID
 numbers, another of symphonies/ID numbers, and another of
 symphonies/composer ID's.  The problem is that under the search form
 now, the search by name does a simple query to the symphonies/ID table
 and gets back a result of all available symphonies.
 This is cumbersome.  What I would like to be able to do, is once the
 composer name select box on the search form is selected, have the
 symphony name form re-update itself to include only those symphonies
 done by the composer.  I imagine this would use a javascript "onSelect,"
 but every time I try to include PHP code in a onselect it gets run
 anyway.  Any way around this?  Can javascript call an exterior PHP
 include or something?  Without refreshing the whole page?  Any ideas?

 the url for the project is symphonynet.datablocks.net.  It's the free
 datablocks php/MySQL deal, sometimes the connection is pretty slow.

 Thanks,

 Kepa Lyman




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Re: [PHP-DB] $result = true or false??

2001-01-26 Thread JJeffman

The "mysql_db_query()" and "mysql_query()" functions only return false (0)
when you have an error in your query or parameter definition, otherwise they
always return a positive result identifier. So, if you must know if is there
any valid record you should ask for the row number returned :
// Check if a valid result has records
if(mysql_num_rows($result)  0){
// stuff
}
else{
// No records procedure
}

HTH

Jayme.

http://www.conex.com.br/jjeffman



-Mensagem Original-
De: Kevin Connolly [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]
Enviada em: sexta-feira, 26 de janeiro de 2001 15:37
Assunto: [PHP-DB] $result = true or false??


Hi,
$db = mysql_connect("localhost", "root");
mysql_select_db("mydb",$db);
$sql = "SELECT * FROM employees where first = '$login'";
$result = mysql_db_query ("mydb", $sql);
echo "$result";

If I run this cose then $result always = Resource id #2 even if $login is
not a member of the database.
Is there anyway I can get it to output true if $login is a member and false
if $login is not a member? or at least get $result to be different if $login
is in the database to that when it is not?

Thanks,

Kevin.



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Re: [PHP-DB] MySQL/PHP Form Addslashes() command

2001-01-26 Thread JJeffman

There is the "nl2br()" function too :
// From php manual :

nl2br -- Converts new lines to HTML line breaks.
Description

string nl2br(string string);

Returns string with 'BR' inserted before all new lines.

HTH

Jayme.

http://www.conex.com.br/jjeffman



-Mensagem Original-
De: Rubanowicz, Lisa [EMAIL PROTECTED]
Para: 'James Smith' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Enviada em: sexta-feira, 26 de janeiro de 2001 07:59
Assunto: RE: [PHP-DB] MySQL/PHP Form  Addslashes() command


 I am a beginner but did it like this, with a little help from my friends!!
 $query = "INSERT INTO guests ";
 $query .= "(guest_id, guest_name, ";
 $query .= "guest_email, guest_time, guest_message) ";
 $query .= "values(, '$name', '$email', NULL, '" .
 str_replace("\n","br", $message) . "')";

 Where $message is the TEXTAREA box submitted
 All the best
 Lisa

 -Original Message-
 From: James Smith [mailto:[EMAIL PROTECTED]]
 Sent: Thursday, January 25, 2001 8:50 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP-DB] MySQL/PHP Form  Addslashes() command


 Alright, you have a textarea in a form, say some one
 right this:

 Today, during the meeting blah blah blah... (now they
 want to start a new paragraph, so they press enter
 twice.)

 After the construction meeting blah blah blah...

 Ok...  Now the question.  The addslashes() command
 won't add the NULL spots to make it a new paragraph
 when you open this row in a page.  How do I get that
 to work...

 Thank You,

 James Smith

 __
 Do You Yahoo!?
 Yahoo! Auctions - Buy the things you want at great prices.
 http://auctions.yahoo.com/

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Re: [PHP-DB] failure notice

2001-01-25 Thread JJeffman

The last time I sent a message to php-list-admin asking for stop this kind
of messages they took the email address off but I was fired of the list too.

Jayme.

http://www.conex.com.br/jjeffman



-Mensagem Original-
De: Jon Niola [EMAIL PROTECTED]
Para: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Enviada em: quinta-feira, 25 de janeiro de 2001 16:17
Assunto: Re: [PHP-DB] failure notice


 Could someone please block this guy's address from the list? I am getting
 sick of this crap

 At 08:00 AM 1/25/01 -0800, Mike wrote:
 Hi. This is the qmail-send program at toye.php.net.
 I'm afraid I wasn't able to deliver your message to the following
addresses.
 This is a permanent error; I've given up. Sorry it didn't work out.
 
 [EMAIL PROTECTED]:
 ezmlm responseezmlm-send: fatal: message already has a Mailing-List
header
 (maybe I should be a sublist) (#5.7.2)
 
 [EMAIL PROTECTED]:
 ezmlm-manage: fatal: message already has a Mailing-List header (maybe I
 should be a sublist) (#5.7.2)
 
 --- Below this line is a copy of the message.
 
 Return-Path: [EMAIL PROTECTED]
 Received: (qmail 10167 invoked from network); 25 Jan 2001 01:00:32 -
 Received: from unknown (HELO gull.prod.itd.earthlink.net)
(207.217.121.85)
by va.php.net with SMTP; 25 Jan 2001 01:00:32 -
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 [63.178.64.241])
  by gull.prod.itd.earthlink.net (EL-8_9_3_3/8.9.3) with SMTP id
  RAA23822;
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 From: "Mike" [EMAIL PROTECTED]
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 Received: from toye.php.net ([198.186.203.51]) by vespasian.mspring.net
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 List-Help: mailto:[EMAIL PROTECTED]
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 Date: Wed, 24 Jan 2001 17:04:11 -0800
 Message-ID: [EMAIL PROTECTED]
 Content-Transfer-Encoding: quoted-printable
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 X-Mailer: Microsoft Outlook Express 5.50.4522.1200
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 (207.217.121.49)  by va.php.net with SMTP; 24 Jan 2001 22:54:52 -
 Received: from michaelbowman (sdn-ar-012orportP142.dialsprint.net
 [63.180.14.206]) by scaup.prod.itd.earthlink.net (EL-8_9_3_3/8.9.3) with
 SMTP id OAA16305 for [EMAIL PROTECTED]; Wed, 24 Jan 2001
 14:57:21 -0800 (PST)
 MIME-Version: 1.0
 Content-Type: text/plain;
  charset="us-ascii"
 X-MimeOLE: Produced By Microsoft MimeOLE V5.50.4522.1200
 Subject: ezmlm response
 
 Hi! This is the ezmlm program. I'm managing the
 [EMAIL PROTECTED] mailing list.
 
 I'm working for my owner, who can be reached
 at [EMAIL PROTECTED]
 
 This is a generic help message. The message I received wasn't sent to
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 In both cases, I'll send a confirmation message to that address. When
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Re: [PHP-DB] Newbie - 2 tables one insert

2001-01-24 Thread JJeffman

Are you trying to get the auto_increment "id" used in the last Insert ? If
so, try this function:
// int mysql_insert_id(int [link_identifier] );
$last_id = mysql_insert_id($result);
$sql2 = "INSERT INTO pages page_id values($last_id );
$result2 = mysql_query($sql2);

HTH

Jayme.

http://www.conex.com.br/jjeffman



-Mensagem Original-
De: Rubanowicz, Lisa [EMAIL PROTECTED]
Para: Rubanowicz, Lisa [EMAIL PROTECTED]; [EMAIL PROTECTED]
Enviada em: tera-feira, 23 de janeiro de 2001 11:54
Assunto: RE: [PHP-DB] Newbie - 2 tables one insert


 I realised I just sent my password out needless to say I am just about to
 change it.
 All the Best
 Lisa

 -Original Message-
 From: Rubanowicz, Lisa [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, January 23, 2001 1:54 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP-DB] Newbie - 2 tables one insert


 Hi all,
 Could you please help me out on this one.
 I want to create a web site using two tables.
 1. page_creation - Stores page_id and page_name to be shown on all
 navigation bars.
 2. pages - Contains pg_id, page_id, etc etc.
 I want to do an insert into page_creation to create a new page and then
pass
 the page_id to pages, so I know the info stored in "pages" relates to a
 certain page (one to many relationship).  In the code below I want this to
 be an "Add a New web Page" where the user types in a Page Name shown in
the
 nav bar and it enters data as above.
 I have been trying for three days now with different methods and it is
 driving me mad.
 Thank you in advance for your assistance


 ?
 if ($page_name) {

 $host="db9.pair.com";
 $user="c3po";
 $password="13Balreask";
 $dbasename="c3po_test";

 mysql_pconnect("$host","$user","$password")
 or die("Unable to connect to SQL server");
 mysql_select_db("$dbasename") or die("Unable to select database");

 $sql1 = "INSERT INTO page_creation pagename";
 $sql1 = "values('$page_name')";
 $result = mysql_query($sql1);
 $sql2 = "INSERT INTO pages page_id values('$result');
 $result2 = mysql_query($sql2);
 }
 else {
 ?
 HTML
 HEAD
 /HEAD
 BODY BGCOLOR="#FF"
 FORM ACTION="test_2_tables.php" METHOD="POST"
 INPUT TYPE=TEXT name="page_name" VALUE="?echo $page_name ?" SIZE=20
 INPUT TYPE=SUBMIT VALUE="Add a New Page"
 /FORM
 /BODY
 /HTML
 ? }
 ?




 Lisa Rubanowicz
 Case ITC,
 Navan, Ireland
 Tel: #353 (0)46 77663

 [EMAIL PROTECTED] mailto:[EMAIL PROTECTED]






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[PHP-DB] Include problem.

2001-01-23 Thread JJeffman

I am running PHP3.017(cgi) + Apache + MySQL on Windows98 SE.
The include() and the getenv() functions are asking for a dial-up
connection. Can somebody give me a hand ?

Jayme.

http://www.conex.com.br/jjeffman






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