Hi,
this is a way to find dupes with sql
SELECT id, year, COUNT(*) AS cnt FROM table
GROUP BY id, year
HAVING cnt1
Lutz
[EMAIL PROTECTED] (J. Wharton) writes:
Does anyone know of any built-in functions (either in PHP or MySQL) that can
search for duplicates in a table according to 2
Hi Volker,
after studying your code (not so easy to find without formating and
lots of html), I think what you want to do is somthing like this:
$abfrage = 'SELECT A.id AS aid, A.autor AS aauthor, A.zeit,AS azeit'
.' A.betreff AS abetreff, A.inhalt AS ainhalt,'
Hi Andy,
it is difficult to give you an advice without the knowing about
how you are searching the database. But if you have to search
through all entries, it was a bad decision to split them up into
250 tables.
Some other hints:
You are lost without an index, because mysql have to do a full
Hi Jon-David,
not sure that this is the only problem, but rewrite your query like this
(single quotes araound the values):
$query=insert into BUGS (APP, APP_VERSION, BUILD, OS, SEVERITY,
BUG_PRIORITY, BUG_STATE, SB_USER, STEPS, EXPECTED,
if APP_VERSION is defined as decimal you can not insert a string.
So leaving away the quotes around $numVersion should bring you
closer.
Lutz
[EMAIL PROTECTED] (Jon-David Schlough) writes:
you're right Lutz, that is not my only problem- turns out this statement is
wrought with errors :|
i
Hi Jeff,
the most important rule you should follow: don't query the database
in a loop to avoid a join! The following lines (maybe some changes
are necesary) will do the same job as your code, but considerable faster.
Especially if 'id' is an index in both tables.
Lutz
$sql = 'SELECT u.id,
[EMAIL PROTECTED] (Adv. Systems Design) writes:
I was simply going by the docs themselves:
http://www.mysql.com/doc/A/N/ANSI_diff_Sub-selects.html
(see bottom of page)
yes, using REPLACE may be a solution. But you have to make a copy of
the original table, because REPLACE cannot access the
[EMAIL PROTECTED] (Adv. Systems Design) writes:
Question is how to properly form a LEFT JOIN using
UPDATE... I tried:
UPDATE product_price LEFT JOIN temp
SET product_price.product_price_vdate = 1 (del flag)
ON product_price.product_id = temp.product_id
WHERE temp.product_id IS NOT NULL
