RE: [PHP-DB] How-to pass informational mysql messages to the browser

2005-02-25 Thread Tyler Replogle
try
if($mysql stuff her){
worked
}else{
doestn't work
}
I don't know how to get the other info you wanted besides just finding it 
out before hand and see what he info is afterr you do the mydql stuff.

From: Mike Millner [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] How-to pass informational mysql messages to the browser
Date: Thu, 24 Feb 2005 15:07:00 -0700
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Hello everyone,
My PHP/mysql pages are working perfectly, the problem is users don't know 
if what they are doing is working.

I have a system that adds and deletes tape id's from mysql via a PHP front 
end.

I would like to pass the same success/failure messages that I would get if 
I performed the add/delete directly within mysql.

For example, If I delete a tape from the db within mysql, after I hit enter 
I get the following message:

mysql delete from tape_tracking_test where media_id like 'TR44';
Query OK, 1 row affected (0.01 sec)
I would like to display this message to the browser:
Query OK, 1 row affected (0.01 sec)
Any help would be appreciated,
Thanks,
Mike
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RE: [PHP-DB] php problem

2005-01-06 Thread Tyler Replogle
whats the php info?
From: Serenity Schindler [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] php problem
Date: Thu, 6 Jan 2005 05:00:32 -0800 (PST)
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I am new to php and have no idea what I'm doing wrong. I have a file named 
test.php containing:

html
head
title PHP Test /title
/head
body
pThis is an HTML line
p
?php
   echo This is a PHP line;
   phpinfo();
?
/body
/html
The html lines show up just fine but none of the php info is displayed. Any 
ideas?

~Serenity~

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RE: [PHP-DB] Cookies with databases

2004-10-20 Thread Tyler Replogle
Yes you need to set the string domain
http://us2.php.net/manual/en/function.setcookie.php
that url should help you
From: Jason T. Davidson [EMAIL PROTECTED]
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Subject: [PHP-DB] Cookies with databases
Date: Wed, 20 Oct 2004 19:54:54 -0500
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I am trying to set a cookie with a value from a database.  Here is my 
script:

? //Setting Cookies
setcookie ('CIDcookie', $cid);
setcookie ('USERcookie', $user);
?
?
//Database connection
require (../../db_connect.php);
//Table Name
$main_tbl = MAIN
?
?
//Check the Password against the CID
$query=SELECT * FROM $main_tbl WHERE CID='$cid';
$result=mysql_query($query) or die(mysql_error());
$check=mysql_fetch_array($result);
if	($Message == NoAccess){
	echo(BCENTERFONT COLOR=REDYou do not have access to that 
page!/FONT/CENTER/B\n);
	include (staff_code/admin_links.php);
	}
if	($check[PASSWORD] != $_REQUEST[password]){
	header(Location:staff_login.php?Message=Invalid);
	}
if	(($check[PASSWORD] == $_REQUEST[password]) AND ($check[USER] == A)) {
	include (staff_code/admin_links.php);
	$user = $check[USER];
	}
else{
	include (staff_code/controller_links.php);
	}
?

Then on the second page it is reading the cookies, but it will display the 
CIDcookie, but not the USERcookie.  Here is the script on the second page:

? //Retrieve Cookies
$cid = $_COOKIE['CIDcookie'];
$user = $_COOKIE['USERcookie'];
?
html
head
titleZMP ARTCC:  Staff To Do List/title
meta http-equiv=Content-Type content=text/html; charset=iso-8859-1
/head
?
echo (My CID is $cid);
echo ($user);
?
body text=#66 link=#66 vlink=#66 alink=#66
table width=600
tr
tddiv align=centerfont size=4strongZMPs Staff TO Do 
List/strong/font/div/td
/tr
/table
br

table width=600
	tr
		td colspan=3 bgcolor=#99div align=centerstrongfont 
size=3Completed Tasks/font/strong/div/td
	/tr
	tr bgcolor=#CC
		td width=100div align=centerDate Finished/div/td
	td width=250div align=centerTask/div/td
	td width=250div align=centerStatus/div/td
	/tr
	tr
	  tddiv align=center10-13-04/div/td
	  tddiv align=centerDLH SOP (new)/div/td
	  tddiv align=centerAwaiting finish of other projects/div/td
  /tr
	tr
	  tddiv align=center10-18-04/div/td
	  tddiv align=centerZMP Policies/div/td
	  tddiv align=centerquot;/div/td
  /tr
/table
br

table width=600
	tr
		td colspan=3 bgcolor=#99div align=centerstrongfont 
size=3
		Tasks Awaiting VATUSA Approval/font/strong/div/td
	/tr
	tr bgcolor=#CC
	  td width=100div align=centerDate Sent/div/td
  td width=250div align=centerTask/div/td
  td width=250div align=centerStatus/div/td
	/tr
	tr
	  tddiv align=center10-09-04/div/td
	  tddiv align=centerLNK SOP (new)/div/td
	  tddiv align=centerAwaiting approval/div/td
  /tr
	tr
	  tddiv align=center10-19-04/div/td
	  tddiv align=centerM98 SOP/div/td
	  tddiv align=centerAwaiting Approval/div/td
  /tr
	tr
	  tddiv align=center10-19-04/div/td
	  tddiv align=centerGeneral SOP/div/td
	  tddiv align=centerAwaiting Approval/div/td
  /tr
/table

/body
/html
So I am assuming that somewhere in my first page that my cookie isn't 
actually gettting set properly.  I have tried many varitites and can't find 
any help sections on cookies from a database.  Any help would be 
appreciated!

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Re: [PHP-DB] DISTINCT and multiple results...

2004-06-07 Thread Tyler Replogle
hey,
you could do something like this
?php  $query = SELECT * FROM `table` Group by email;
  $query_count++;
  $result = mysql_query ($query);
  while ($row = mysql_fetch_assoc ($result)) {
$title = $row[title];
$first_name= $row[first name];
$company = $row[company];
echotitle: $title br first_name: $first_name br company: $company;
}
?


From: [EMAIL PROTECTED]
To: Jonathan Haddad [EMAIL PROTECTED]
CC: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] DISTINCT and multiple results...
Date: Mon, 7 Jun 2004 14:05:41 +0100
Ah, but then how can I select other info from the same table (title, first
name, company etc...)


Jonathan Haddad [EMAIL PROTECTED]
07/06/2004 13:39
To
[EMAIL PROTECTED]
cc
[EMAIL PROTECTED]
Subject
Re: [PHP-DB] DISTINCT and multiple results...


select distinct email, username from table
On Jun 7, 2004, at 8:19 AM, [EMAIL PROTECTED] wrote:
 Hi there...
 I'm trying to create a MYSQL query that does the following...

 I've a table that lists ALL downloads from our site.
 so I may have the same user many times, but different files, or infact,
 same user, same file.
 What my boss wants to see is:
 If a user downloaded a file 3 times, she doesn't care, she just wants
 to
 see that it was downloaded.
 So I tried using DISTINCT(email), but then I loose the data about the
 other files that they've downloaded
 How can I create a query, where I can list only one instance of email,
 per
 multiple instatnces of a file name.

 Does that make sence?
 I'm reallyu stumped...

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RE: [PHP-DB] Macs and sessions

2004-04-20 Thread Tyler Replogle
All Macintosh users can't or is it just a type of one because that happened 
to me before i change my sites to work with it. So if it is just one type of 
Macintosh computer i might be able to help you.




From: matthew perry [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Macs and sessions
Date: Tue, 20 Apr 2004 12:31:33 -0500
Macintosh users can't log in on my web site.
I don't require anything unusual for log ins - simply a form with a user id 
and password that queries a MySQL database.
The form is not encripted and I don't even use any security precautions for 
the data transfer (users can't do much anyway).
After the log in I store all information in session data.
The rest of my site's pages work fine including my PHP pages.
Anyone know why macs might have problems with PHP/MySQL data transfers?

Matt

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RE: [PHP-DB] Displaying Date from Value in MySQL DB

2004-04-20 Thread Tyler Replogle
You could always make your own function. If you need help with that i would 
be glad to help there too.



From: Justin @ Dreaming in TO [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Displaying Date from Value in MySQL DB
Date: Tue, 20 Apr 2004 14:27:30 -0400
Hey All,

Looking to try to figure at small problem.

This is the SQL query I am using to show the next event on a page:

SELECT ditoevents.eventstatus, ditoevents.eventdate, 
DATE_FORMAT(ditoevents.eventdate, '%a, %b %d %Y'), ditoevents.eventtime, 
ditoevents.eventlocation, ditoevents.topic, ditoevents.presenter
FROM ditoevents
WHERE ditoevents.eventstatus = 'next'

This is the structure of the table in the MySQL db:

CREATE TABLE ditoevents (
  ID char(3) NOT NULL default '',
  eventID char(2) NOT NULL default '',
  eventstatus varchar(4) NOT NULL default '',
  eventdate date NOT NULL default '-00-00',
  eventtime time NOT NULL default '00:00:00',
  eventlocation text NOT NULL,
  topic text NOT NULL,
  presenter text NOT NULL
) TYPE=MyISAM;
The problem is, the date value that's being pulled from the DB is being 
displayed as 2004-05-12. I would like the date to be displayed as, 
Wednesday, May 12th, 2004.

How do I do this with PHP. I looked at some of the date functions, and I'm 
a bit confused.

Thanks,

Justin

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RE: [PHP-DB] password input type

2004-04-06 Thread Tyler Replogle
the onlooker



From: matthew perry [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] password input type
Date: Mon, 05 Apr 2004 13:14:17 -0500
Does using a pasword input type input name=password type=password 
make the transfer more secure from someone sniffing my connection or does 
it only shield an onlooker from seeing what the user enters?
- Matt

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