Re: [PHP-DB] Help with If else if
On Tue, 13 Mar 2012 17:33:43 +0530, Gu®u nagendra802...@gmail.com sent:
Hi,
Please help me with this code. I have 2 different fields in mysql table.
What I want is if the field is empty don't show the image. Please look at
the code below.
?php
if($search-plugin-ListViewValue()==)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($search-facebook-ListViewValue()==)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
else if($search-plugin-ListViewValue()==
$search-facebook-ListViewValue()==)
{
echo ;
}
else
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a'.'a
href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
--
*Best,
*
*Gu®u*
I think we really need to see a lot more than this before we can help.
What is the output that is generated? What is $search and how is it
set prior to entering this bit of code? As it stands, I can see no
reference to MySQL tables in this, nor any idea what values you're
expecting and not seeing. If you don't already, please set
error_reporting to the most detailed, and turn on display_errors in
your output. Before each of the if's echo a var_dump of the values
you're testing so we can see their exact values.
--
Tamara Temple
aka tamouse__
May you never see a stranger's face in the mirror
--
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Re: [PHP-DB] Help with If else if
On Tue, 13 Mar 2012 21:23:57 +0530, Gu®u nagendra802...@gmail.com sent:
No Michael, your code is also not working. What you have understood is
correct. let me explain it to others too.
If variable twitter and facebook are empty don't echo anything,
if variable twitter has a value and facebook is empty echo out only twitter,
if variable twitter has no value and facebook has a value echo out facebook
only,
and finally if both has values echo out both.
Basically I want to echo out only if there is some value in the database.
But in my case both the images are echoing out.
For probably the bazillionth time, PUT REPLIES ON THE BOTTOM
On Tue, Mar 13, 2012 at 8:54 PM, Michael Stowe m...@mikestowe.com wrote:
From looking at your code, the issue is that your if statements are
checking for the same criteria as your else statements, meaning that if the
string is empty () the if statements will be triggered, and since the if
statements are true, the elseif statement will not be. Or if the string
isn't empty, neither the if or the elseif statements will be triggered,
causing the else statement to be activated. Either way, the images would
be printed out. *
*
*
*
*Did you mean to do this?*
?php
if($search-plugin-ListViewValue() ==
$search-facebook-ListViewValue() == ) {
// Neither one has a value
} elseif ($search-plugin-ListViewValue() !=
$search-facebook-ListViewValue() != ) {
// Both have a Value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a' . 'a
href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
} elseif ($search-plugin-ListViewValue() != ) {
// Twitter has a value
} else {
// Facebook has a value (only possible option left)
echo 'a href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
Hope that helps,
Mike
On Tue, Mar 13, 2012 at 9:44 AM, Matijn Woudt tijn...@gmail.com wrote:
On Tue, Mar 13, 2012 at 3:06 PM, Gu®u nagendra802...@gmail.com wrote:
The issue is both the images are echoing and no if else statement is
working.
First of all, please bottom post on this (and probably any) mailing list.
You should perhaps provide what the contents of
$search-plugin-ListViewValue()== and
$search-facebook-ListViewValue()== is.
Though, if I understood you correctly, it would be as simple as:
$facebookEnabled = $search-facebook-ListViewValue()!=;
$twitterEnabled = $search-plugin-ListViewValue()!=;
if($facebookEnabled)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($twitterEnabled)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
- Matijn
--
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--
---
My command is this: Love each other as I
have loved you. John 15:12
---
--
*Best,
*
*Gu®u*
Recapitulating your pseudocode above, you don't need anything so complex:
if twitter is set:
emit twitter image
if facebook is set:
emit facebook image
The two seem completely independent of each other. Thus:
?php
$twitter = $search-plugin-ListViewValue();
if (!empty($twitter)) {
echo 'a href='.$twitter.'img src=images/twitter.gif
width=22 height=23//a';
}
$fb = $search-facebook-ListViewValue();
if (!empty($fb)) {
echo 'a href='.$fb.'img src=images/facebook.gif width=22
height=23//a';
}
?
The above will give a twitter image+link if the twitter link is set,
and a facebook image+link if facebook is set. You don't need to do
anything special if both are set, or if neither is set, as they are
completely independent of each other.
--
Tamara Temple
aka tamouse__
May you never see a stranger's face in the mirror
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Help with If else if
Hi,
Please help me with this code. I have 2 different fields in mysql table.
What I want is if the field is empty don't show the image. Please look at
the code below.
?php
if($search-plugin-ListViewValue()==)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($search-facebook-ListViewValue()==)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
else if($search-plugin-ListViewValue()==
$search-facebook-ListViewValue()==)
{
echo ;
}
else
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a'.'a
href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
--
*Best,
*
*Gu®u*
Re: [PHP-DB] Help with If else if
On Tue, Mar 13, 2012 at 1:03 PM, Gu®u nagendra802...@gmail.com wrote: Hi, Please help me with this code. I have 2 different fields in mysql table. What I want is if the field is empty don't show the image. Please look at the code below. I have looked at it. Maybe you should tell what is wrong, what it outputs currently, and what it should output. Or perhaps, which errors you get if any? - Matijn -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Help with If else if
The issue is both the images are echoing and no if else statement is working. On Tue, Mar 13, 2012 at 7:22 PM, Matijn Woudt tijn...@gmail.com wrote: On Tue, Mar 13, 2012 at 1:03 PM, Gu®u nagendra802...@gmail.com wrote: Hi, Please help me with this code. I have 2 different fields in mysql table. What I want is if the field is empty don't show the image. Please look at the code below. I have looked at it. Maybe you should tell what is wrong, what it outputs currently, and what it should output. Or perhaps, which errors you get if any? - Matijn -- *Best, * *Gu®u*
Re: [PHP-DB] Help with If else if
On Tue, Mar 13, 2012 at 3:06 PM, Gu®u nagendra802...@gmail.com wrote:
The issue is both the images are echoing and no if else statement is
working.
First of all, please bottom post on this (and probably any) mailing list.
You should perhaps provide what the contents of
$search-plugin-ListViewValue()== and
$search-facebook-ListViewValue()== is.
Though, if I understood you correctly, it would be as simple as:
$facebookEnabled = $search-facebook-ListViewValue()!=;
$twitterEnabled = $search-plugin-ListViewValue()!=;
if($facebookEnabled)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($twitterEnabled)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
- Matijn
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Help with If else if
From looking at your code, the issue is that your if statements are
checking for the same criteria as your else statements, meaning that if the
string is empty () the if statements will be triggered, and since the if
statements are true, the elseif statement will not be. Or if the string
isn't empty, neither the if or the elseif statements will be triggered,
causing the else statement to be activated. Either way, the images would
be printed out. *
*
*
*
*Did you mean to do this?*
?php
if($search-plugin-ListViewValue() ==
$search-facebook-ListViewValue() == ) {
// Neither one has a value
} elseif ($search-plugin-ListViewValue() !=
$search-facebook-ListViewValue() != ) {
// Both have a Value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a' . 'a
href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
} elseif ($search-plugin-ListViewValue() != ) {
// Twitter has a value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a';
} else {
// Facebook has a value (only possible option left)
echo 'a href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
Hope that helps,
Mike
On Tue, Mar 13, 2012 at 9:44 AM, Matijn Woudt tijn...@gmail.com wrote:
On Tue, Mar 13, 2012 at 3:06 PM, Gu®u nagendra802...@gmail.com wrote:
The issue is both the images are echoing and no if else statement is
working.
First of all, please bottom post on this (and probably any) mailing list.
You should perhaps provide what the contents of
$search-plugin-ListViewValue()== and
$search-facebook-ListViewValue()== is.
Though, if I understood you correctly, it would be as simple as:
$facebookEnabled = $search-facebook-ListViewValue()!=;
$twitterEnabled = $search-plugin-ListViewValue()!=;
if($facebookEnabled)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($twitterEnabled)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
- Matijn
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
---
My command is this: Love each other as I
have loved you. John 15:12
---
Re: [PHP-DB] Help with If else if
No Michael, your code is also not working. What you have understood is
correct. let me explain it to others too.
If variable twitter and facebook are empty don't echo anything,
if variable twitter has a value and facebook is empty echo out only twitter,
if variable twitter has no value and facebook has a value echo out facebook
only,
and finally if both has values echo out both.
Basically I want to echo out only if there is some value in the database.
But in my case both the images are echoing out.
On Tue, Mar 13, 2012 at 8:54 PM, Michael Stowe m...@mikestowe.com wrote:
From looking at your code, the issue is that your if statements are
checking for the same criteria as your else statements, meaning that if the
string is empty () the if statements will be triggered, and since the if
statements are true, the elseif statement will not be. Or if the string
isn't empty, neither the if or the elseif statements will be triggered,
causing the else statement to be activated. Either way, the images would
be printed out. *
*
*
*
*Did you mean to do this?*
?php
if($search-plugin-ListViewValue() ==
$search-facebook-ListViewValue() == ) {
// Neither one has a value
} elseif ($search-plugin-ListViewValue() !=
$search-facebook-ListViewValue() != ) {
// Both have a Value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a' . 'a
href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
} elseif ($search-plugin-ListViewValue() != ) {
// Twitter has a value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a';
} else {
// Facebook has a value (only possible option left)
echo 'a href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
Hope that helps,
Mike
On Tue, Mar 13, 2012 at 9:44 AM, Matijn Woudt tijn...@gmail.com wrote:
On Tue, Mar 13, 2012 at 3:06 PM, Gu®u nagendra802...@gmail.com wrote:
The issue is both the images are echoing and no if else statement is
working.
First of all, please bottom post on this (and probably any) mailing list.
You should perhaps provide what the contents of
$search-plugin-ListViewValue()== and
$search-facebook-ListViewValue()== is.
Though, if I understood you correctly, it would be as simple as:
$facebookEnabled = $search-facebook-ListViewValue()!=;
$twitterEnabled = $search-plugin-ListViewValue()!=;
if($facebookEnabled)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($twitterEnabled)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
- Matijn
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
---
My command is this: Love each other as I
have loved you. John 15:12
---
--
*Best,
*
*Gu®u*
Re: [PHP-DB] Help with If else if
Hmm, what happens with the code I sent you? Just tested it on my end and
worked exactly as expected.
Try doing a
var_dump($search-plugin-ListViewValue(), $search-facebook-ListViewValue());
to make sure the data being returned is what's expected... you should be
getting string(0) returned for both.
Thanks,
Mike
On Tue, Mar 13, 2012 at 10:53 AM, Gu®u nagendra802...@gmail.com wrote:
No Michael, your code is also not working. What you have understood is
correct. let me explain it to others too.
If variable twitter and facebook are empty don't echo anything,
if variable twitter has a value and facebook is empty echo out only
twitter,
if variable twitter has no value and facebook has a value echo out
facebook only,
and finally if both has values echo out both.
Basically I want to echo out only if there is some value in the database.
But in my case both the images are echoing out.
On Tue, Mar 13, 2012 at 8:54 PM, Michael Stowe m...@mikestowe.com wrote:
From looking at your code, the issue is that your if statements are
checking for the same criteria as your else statements, meaning that if the
string is empty () the if statements will be triggered, and since the if
statements are true, the elseif statement will not be. Or if the string
isn't empty, neither the if or the elseif statements will be triggered,
causing the else statement to be activated. Either way, the images would
be printed out. *
*
*
*
*Did you mean to do this?*
?php
if($search-plugin-ListViewValue() ==
$search-facebook-ListViewValue() == ) {
// Neither one has a value
} elseif ($search-plugin-ListViewValue() !=
$search-facebook-ListViewValue() != ) {
// Both have a Value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a' . 'a
href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
} elseif ($search-plugin-ListViewValue() != ) {
// Twitter has a value
echo 'a href=' . $search-plugin-ListViewValue() . 'img
src=images/twitter.gif width=22 height=23//a/a';
} else {
// Facebook has a value (only possible option left)
echo 'a href=' . $search-facebook-ListViewValue() . 'img
src=images/facebook.gif width=22 height=23//a/a';
}
?
Hope that helps,
Mike
On Tue, Mar 13, 2012 at 9:44 AM, Matijn Woudt tijn...@gmail.com wrote:
On Tue, Mar 13, 2012 at 3:06 PM, Gu®u nagendra802...@gmail.com wrote:
The issue is both the images are echoing and no if else statement is
working.
First of all, please bottom post on this (and probably any) mailing list.
You should perhaps provide what the contents of
$search-plugin-ListViewValue()== and
$search-facebook-ListViewValue()== is.
Though, if I understood you correctly, it would be as simple as:
$facebookEnabled = $search-facebook-ListViewValue()!=;
$twitterEnabled = $search-plugin-ListViewValue()!=;
if($facebookEnabled)
{
echo 'a href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
if($twitterEnabled)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
- Matijn
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
---
My command is this: Love each other as I
have loved you. John 15:12
---
--
*Best,
*
*Gu®u*
--
---
My command is this: Love each other as I
have loved you. John 15:12
---
Re: [PHP-DB] Help with If else if
On Tue, Mar 13, 2012 at 4:53 PM, Gu®u nagendra802...@gmail.com wrote: No Michael, your code is also not working. What you have understood is correct. let me explain it to others too. If variable twitter and facebook are empty don't echo anything, if variable twitter has a value and facebook is empty echo out only twitter, if variable twitter has no value and facebook has a value echo out facebook only, and finally if both has values echo out both. Basically I want to echo out only if there is some value in the database. But in my case both the images are echoing out. That's exactly what my code does too, except it's a bit simpler. If mine isn't working too, then your input is probably different, try a var_dump on the ListViewValue() items. - Matijn -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Help with If else if
I tried the below code too considering may be the localhost is really dumb
and we need to tell each and every condition. But still its not working :(
$tweet = $search-plugin-ListViewValue();
$fb = $search-facebook-ListViewValue();
if($tweet== $fb==)
{
echo ;
}
elseif($fb== $tweet!=)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a';
}
elseif($tweet== $fb!=)
{
echo 'a
href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
elseif($fb!= $tweet!=)
{
echo 'a href='.$search-plugin-ListViewValue().'img
src=images/twitter.gif width=22 height=23//a/a'.'a
href='.$search-facebook-ListViewValue().'img
src=images/facebook.gif width=22 height=23//a/a';
}
On Tue, Mar 13, 2012 at 9:44 PM, Matijn Woudt tijn...@gmail.com wrote:
On Tue, Mar 13, 2012 at 4:53 PM, Gu®u nagendra802...@gmail.com wrote:
No Michael, your code is also not working. What you have understood is
correct. let me explain it to others too.
If variable twitter and facebook are empty don't echo anything,
if variable twitter has a value and facebook is empty echo out only
twitter,
if variable twitter has no value and facebook has a value echo out
facebook
only,
and finally if both has values echo out both.
Basically I want to echo out only if there is some value in the database.
But in my case both the images are echoing out.
That's exactly what my code does too, except it's a bit simpler. If
mine isn't working too, then your input is probably different, try a
var_dump on the ListViewValue() items.
- Matijn
--
*Best,
*
*Gu®u*
