[PHP-DB] Control Structure Error

[Brad Lipovsky]

Here is the code that I am trying to use:

//code start
function search_terms($title) {
 $array = explode ( , $title);
  for($i=0,$n=count($array); $i$n; $i++) {
   $returned_string = $returned_string . $array[$i] .  OR ;
}
 return $returned_string
}
//code end

I want it to turn the string of words stored in $title into an array
($array), then use the for structure to insert the string  OR  in between
each word, and then finally return the string ($returned_string) for DB
purposes.



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RE: [PHP-DB] Control Structure Error

[Ben Bleything]

It works for me... except that you need a semi-colon after 'return
$returned_string' and it sticks the word OR at the end of the whole
string, which you may not want.

Does that help, or did I miss the point?

Ben

-Original Message-
From: Brad Lipovsky [mailto:[EMAIL PROTECTED]] 
Sent: Sunday, July 08, 2001 5:52 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Control Structure Error

Here is the code that I am trying to use:

//code start
function search_terms($title) {
 $array = explode ( , $title);
  for($i=0,$n=count($array); $i$n; $i++) {
   $returned_string = $returned_string . $array[$i] .  OR ;
}
 return $returned_string
}
//code end

I want it to turn the string of words stored in $title into an array
($array), then use the for structure to insert the string  OR  in
between
each word, and then finally return the string ($returned_string) for DB
purposes.



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To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]



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