Okay, when I try to change the gregorian date to julian, I get
error: call to undefined function: gregoriantojd() in line...
Here's the code I used to replace $datetoget=($datetoget-1);
//from what I understand ,must be in month, day, year format
//so passed today's date
$greg_date=GregorianToJD(1,2,2002);
//subtracted a day
$greg_date=($greg_date-1);
//converted it back to gregorian format
$datetoget=JDToGregorian($greg_date);
--
Faye Keesic
Computer Programmer Analyst/Web Page Design
From: [EMAIL PROTECTED]
Date: Wed, 2 Jan 2002 07:55:02 -0800 (PST)
To: Faye Keesic [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Date problem with new year
Ah... the $datetoget = ($datetoget-1) is the problem.
Convert the Gregorian Ymd date to Julian, subtract 1, then convert the
Julian date back to Gregorian (or Hebrew ;-). I've not had much success
with MySQL's date functions.
On Wed, 2 Jan 2002, Faye Keesic wrote:
I had no problems with retrieving news stories from previous days before
2002, and haven't changed any of my code. This site has been up for a year,
and I can't recall anything like this happening when 2001 rolled around.
Please excuse the messy code, as this was the first php/db web site I
designed. I took out the formatting stuff... :)
From my php page, I call a function:
get_most_recent_stories(date(Ymd));
- which passes today's date, formatted for for the db
In my code:
- this is the function I call - which in turn calls the function below
(no_yesterdays_stories($datetoget) to subtract a day if there is no news
items for the current date, which then calls the same
get_most_recent_stories() function, but passes a lower date. Ideally,
these will loop until there are stories found for a certain day.
function get_most_recent_stories($datetoget)
{
//Get the headlines, summaries and links to the story
db_connect();
$sql = SELECT * FROM tblStory WHERE (StoryDate=$datetoget);
$results = mysql_query($sql);
if ($results) {
if ($row = mysql_fetch_array($results)) {
echo $row[StorySum];}
while ($row = mysql_fetch_array($results));
}
else {
no_yesterdays_stories($datetoget); } }
}
function no_yesterdays_stories($datetoget)
{
//query has returned no stories from yesterday (holiday, etc.)
//keep subtracting on day from yesterday's date until there are stories
found
$datetoget=($datetoget-1);
get_most_recent_stories($datetoget);
}
--
Faye Keesic
Computer Programmer Analyst/Web Page Design
From: Rick Emery [EMAIL PROTECTED]
Date: Wed, 2 Jan 2002 09:05:42 -0600
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Date problem with new year
No bug, mate.
Post your code so that we can help ya...
-Original Message-
From: Faye Keesic [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, January 02, 2002 8:56 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Date problem with new year
I have a db site that always displays the most recent occurrence of news
stories
The last occurrence of stories was last year (2001-12-31) and up to the new
year rolling over, I had no difficulty subtracting days, etc.
Is there a bug in Mysql? PHP that I don't know of..
Please help.
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