Jennifer: Did you ever get your If else Question answered?
On Mon, 25 Mar 2002, Jennifer Downey wrote:
Hi all,
I have a table called pets, here is a partial dump:
At this time this is all I am working with.
uid int(10) NOT NULL default '0',
num_pet tinyint(1) NOT NULL default '1',
There are three steps to adding the pet into the db
Step 1 create the record, this is in create.php. And yes believe it or not
this does work.
$query_update = INSERT INTO pets (uid) SELECT uid FROM users WHERE
uid={$session[uid]};
$result = mysql_query($query_update)
or die(Unable to insert into the database);
Step 2 Check to see if there is already a pet record this is in process.php.
$query=SELECT num_pet FROM pets WHERE uid={$session[uid]};
$ret = mysql_query($query);
while(list($num_pet)=
mysql_fetch_row($ret))
// echo the number in the db, it should = 1 until submit button clicked
echo $num_pet
$number_pet = $num_pet;
if($number_pet == 0 ) {
print (Sorry you can't add another pet);
}else{ this does all the updating of the record
?
form action=petdata.php method=post
Click to continueBR
INPUT TYPE=submit VALUE=Submit NAME=submit
/form
?
}
Step three update num_pet after submit is clicked, this is in petdata.php
$db = update pets set num_pet = 0 where uid={$session[uid]};
$ret = mysql_query($db) or die(db_error());
Now here is my question, If the submit button is clicked and num_pets is
updated to 0 and you try to add another record shouldn't this print- Sorry
you can't add another pet?
I am at a loss as to why it will keep adding records. Anyone want to take a
stab at it?
TIA
Jen
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