On Fri, Feb 29, 2008 at 12:22 AM, Ron Piggott
<[EMAIL PROTECTED]> wrote:
> $reference_number = mysql_result($search_result,$i,"reference_number");
> $description = mysql_result($search_result,$i,"description");
Just mind the line-wrapping in this message. ;-P
--
Daniel P. Brown
Senior
Ron Piggott wrote:
This line of code
while ($row = mysql_fetch_assoc($result)) {
Gave me this error message:
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL
result resource
I ran
select reference, description from table
in mySQL and it worked --- Any idea what caused
Ron Piggott wrote:
I need help populating an array based on the output of a mysql query.
$reference_number is a value assigned by auto_increment
$description is what I want the value of the array to be --- a few words
in length
$reference_number = mysql_result($search_result,$i,"reference_numb
I need help populating an array based on the output of a mysql query.
$reference_number is a value assigned by auto_increment
$description is what I want the value of the array to be --- a few words
in length
$reference_number = mysql_result($search_result,$i,"reference_number");
$description =
