[PHP-DB] Re: Help with array

2003-02-16 Thread Fredrik de Vibe
[EMAIL PROTECTED] (John Thorne) writes: $data[$cpt]= $row[0].,.$row[1].,.$row[2].,.$row[3].,.$row[4]; What you need is a two dimensional array. The code above concatenates the $row elements into a string and puts this string into a one dimensional array. the 2D array $foo[3][5] can be seen as:

[PHP-DB] Re: Help with array

2003-02-16 Thread John Thorne
Thanks for the reply I do not under stand how to apply your example $foo[$i][$j] = bar; Graph example array trying to create thru sql: $data = array( array(0,Concept,2002-9-1,2002-9-15,blue), array(1,Creative,2002-9-15,2002-9-30,red), array(2,Produce,2002-9-31,2002-10-10,green)): Output $data

[PHP-DB] Re: Help with array

2003-02-16 Thread Fredrik de Vibe
[EMAIL PROTECTED] (John Thorne) writes: [ snip ] $data[$cpt]= $rownu.,.\.$row[0].\.,\.$row[1].\,.\.$row[2].\; This is a string, not an array. Could you go a step farther in the $foo[$i][$j] please $data[$cpt][0] = $rownu; $data[$cpt][1] = $row[0]; $data[$cpt][2] = $row[1]; $data[$cpt][3]

[PHP-DB] Re: Help with array

2003-02-16 Thread John Thorne
$cpt=0; $rownu =1; while($row = mysql_fetch_row($result)) { $data[$cpt][0] = $rownu; $data[$cpt][1] = $row[0]; $data[$cpt][2] = $row[1]; $data[$cpt][3] = $row[2]; $rownu++; $cpt++; This worked perfectly Fredrik.. thank you jrt Fredrik De Vibe [EMAIL