on 1/22/03 12:08 AM, Michael Conway at [EMAIL PROTECTED] appended the
following bits to my mbox:
I find myself stuck in coming up with a way to cycle through this
array of db results for porting to a graphing script that I did not
write. My latest attempt to get around this problem is below.
I find myself stuck in coming up with a way to cycle through this
array of db results for porting to a graphing script that I did not
write. My latest attempt to get around this problem is below. Outside
of the $graph-SetDataValues(array( ));, echoing $array[$i] produces the
desired
It looks like you need only one array, $date[begin] = $date[end].
Let's see, I think it'll work. I'll write it in your code then you try:
$i=0;
$result = mysql_query (SELECT DISTINCT date FROM linktracker WHERE name
LIKE '$PHP_AUTH_USER' ORDER BY date);
if ($row = mysql_fetch_array($result)) {
- Original Message -
From: Jim Lucas [EMAIL PROTECTED]
To: Bart Verbeek [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, October 24, 2001 12:42 PM
Subject: Re: [PHP-DB] array-problems
Try this:
BEGIN:PHP-CODE
$result = mysql_query (SELECT DISTINCT date FROM linktracker
Hello,
Can anyone help me with this script I'm using?
I've saved dates in a database and want to make two select-lists of these
dates in a html-form.
I want to select each unique date one time (no doubles).
List 1 is used to set the begin-date of the query for the report, List 2
will
set the
