Re: [PHP-DB] MySQL/PHP Left Join Question

2006-05-25 Thread tg-php
One thing I've done in situations like this is just load your returned DB data into an array. Something like this would do: $dvdarr[$result['call_number']]['Title'] = $result['title']; $dvdarr[$result['call_number']]['Publisher'] = $result['publisher'];

RE: [PHP-DB] MySQL/PHP Left Join Question

2006-05-25 Thread Bastien Koert
I approach this by assigning a value to a variable and then comparing to see if i need to write out a new title $oldDVD = ; while ($rows=mysql_fetch_array($result)) { //decide whether to show the DVD title if ($oldDVD != $rows['title']) { echo trtd.$rows['title']./td/tr; $oldDVD =

Re: [PHP-DB] MySQL/PHP Left Join Question

2006-05-25 Thread Brad Bonkoski
Some good examples of how to deal with this in PHP have already been given, especially the associative array solution. The question I have is with something like this, how do you weight out the pros/cons of code development versus speed? i.e. for code development breaking the logic up into 2

Re: [PHP-DB] MySQL/PHP Left Join Question

2006-05-25 Thread Andrew Darby
Thanks to Bastien and TG for their suggestions. I'd been looking at it Bastien's way, but TG's is probably better suited to what I want to do. I'd forgotten about that possibility, cramming it all into an array . . . . Again, thanks for the help, Andrew p.s. I'd be curious about the relative

Re: [PHP-DB] MySQL/PHP Left Join Question

2006-05-25 Thread Bastien Koert
test both and let us know bastien From: Andrew Darby [EMAIL PROTECTED] To: php-db@lists.php.net Subject: Re: [PHP-DB] MySQL/PHP Left Join Question Date: Thu, 25 May 2006 12:33:15 -0400 Thanks to Bastien and TG for their suggestions. I'd been looking at it Bastien's way, but TG's is probably