The code looks correct so my guess is that you are parsing it inorrectly in
actionscript...
Bastien
From: Juan Stiller <[EMAIL PROTECTED]>
To: php-db@lists.php.net
Subject: [PHP-DB] MySQL query result with some errors!
Date: Tue, 11 Oct 2005 18:14:42 -0300 (ART)
Hi,
Im trying to get a query result from mysql database to
show it on a flash animation, so far i have this code
that its supposed to connect to mysql server , make
the query and get the results, store them on variables
so that flash can read them. Basically i have these
main fileds like : lastname, firstname and so on... a
guy here told me correctly that i should in case to
have more than one entry on the database, use the
output like lastname1, lastname2, etc. I gues this
code is doing that, but when i want to show that info
on flash i get eg:
lastname: smithn=0
lastname: jacksonn=1
when it should be
lastname: smith
lastname: jackson
...
...
So i guess im doing something wrong, can someone point
me in the right direcction??
Here is the php code:
<?php
$conn = @mysql_connect("localhost", "mysql",
"ullneverguessit");
if (!$conn) {
echo( "<P>No se pudo conectar " .
"al servidor MySQL.</P>" );
exit();
}
if (! @mysql_select_db("llamadas") ) {
echo( "<P>No se puede encontrar " .
"la base de datos clientes!</P>" );
exit();
}
////////////////////////////////////////////////////////////////////////////////
$qr = mysql_query("select * from datos");
$nrows =
mysql_num_rows($qr);
$rString = "n=".$nrows;
for ($i=0; $i < $nrows; $i++) {
$row = mysql_fetch_array($qr);
$rstring .= "&Id".$i."=".$row['id'];
$rString .=
"&Dia".$i."=".$row['dia']."&Mes".$i."=".$row['mes']."&Ano".$i."=".$row['ano'];
$rString .=
"&Hora".$i."=".$row['hora']."&Minutos".$i."=".$row['minutos'];
$rString .= "&Receptor".$i."=".$row['receptor'].
$rString .=
"&Destinatario".$i."=".$row['destinatario'].
$rString .= "&Apellido".$i."=".$row['apellido'].
$rstring .= "&Nombre".$i."=".$row['nombre'];
$rstring .= "&Telefono".$i."=".$row['telefono'];
$rstring .= "&Asunto".$i."=".$row['asunto'];
}
echo $rString;
mysql_free_result($qr);
?>
Thanks.
Juan
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