You seem to be mixing OO and procedural coding styles...try
?
mysql_connect(localhost,user,password);
$result=mysql_db_query(salzert,SELECT * FROM Benutzer WHERE ID=$id);
$row = mysql_fetch_array($result); //get the data into an array
echo 'input type=text name=id value=';
echo $id;
echo '';
Hi,
Actually you have an undefined variable called $row which is in this
context ($row-Vorname) is an object...but $row has nor content
neither type.
I think you'd better use arrays...in this way:
(according to the PHP manual mysql_db_query() is decrepated)
?php
$link = mysql_connect(_host_,
