the explode() should have worked on that. Something like:
$query = SELECT DCD_Access FROM userdb WHERE ID = $user_ID;
$result4 = mysql_query($query) or die(Error);
$DCD = mysql_fetch_array($result4);
$myarray = explode( ,, $DCD['DCD_Access'] );
foreach ( $myarray as $val )
{
print
$my_arr= array(.);
echo implode(' ',array_keys($my_arr));
Andrey Hristov
IcyGEN Corporation
http://www.icygen.com
BALANCED SOLUTIONS
- Original Message -
From: Rick Emery [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, September 11, 2001 4:23 PM
Subject: RE: [PHP-DB]
, ok, sorry for the disturbance. greets.
Andrey Hristov
IcyGEN Corporation
http://www.icygen.com
BALANCED SOLUTIONS
- Original Message -
From: Rick Emery [EMAIL PROTECTED]
To: 'Andrey Hristov' [EMAIL PROTECTED]; Rick Emery [EMAIL PROTECTED]
Sent: Tuesday, September 11, 2001 4:39
$myarray=explode(,,$DCD['fieldname']);
In the above, substitute fieldname for the name of the field which
contains name1,name2,name3,name4,...
Then, cycle through each $myarray element as you've done below.
-Original Message-
From: Robert Trembath [mailto:[EMAIL PROTECTED]]
Sent:
$myarray=explode(,,$DCD['DCD_Access']);
Then, cycle through each $myarray element as you've done below.
-Original Message-
From: Robert Trembath [mailto:[EMAIL PROTECTED]]
Sent: Monday, September 10, 2001 2:55 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] reading arrays within a field from
what do you mean by it made no difference? Did you examine each element in
$myarray? What were the results?
rick
FYI...I tried to send directly to you and the message was bounced back
-Original Message-
From: Robert Trembath [mailto:[EMAIL PROTECTED]]
Sent: Monday, September 10, 2001
Robert,
Do a manual SELECT DCD_Access FROM userdb WHERE ID = ###
and send the results. I'd like to see exactly what is in that field. The
explode() should have provided an array of values
rick
-Original Message-
From: Robert Trembath [mailto:[EMAIL PROTECTED]]
Sent: Monday,
