Building off of one of John Holmes's posts from yesterday:
$f_date = date('n/d/Y',strtotime($yourDBdate));
should do the trick.
Hope this helps.
Rich
> -----Original Message-----
> From: Steve B. [mailto:[EMAIL PROTECTED]
> Sent: Wednesday, June 11, 2003 2:53 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] simple date formatting?
>
>
> Hi I'm looking to format a date but all I find is this date()
> function and it appears to be for
> current date?
>
> My variable $dbrec["ListDate"] is printing:
> 4/30/2003 0:00:00
>
> It needs to print
> 4/30/2003
>
> Am I on the right track to try to do a (with right parameters)
>
> $formatted_date = date("M D Y",$dbrec["ListDate"]);
> or
> $formatted_date = date_format("M D Y",$dbrec["ListDate"]);
>
> Thanks
> Current code just chops it off:
> print "<td><font
> color='white'><b>".substr($dbrec["ListDate"],0,9)."</td>";
>
>
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