Argh, i don't like the plaintext :)
..btw, 05473 is a password for archive
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hi, if the column type of id is varchar or char, u need to put '' around
id.
ur query should look like
mysql_query(DELETE FROM open_trades WHERE id= '.$id.');
Note that your can leave any space between and '
if u do have a space between them, ur query will look like
mysql_query(DELETE FROM
hi, if the column type of id is varchar or char, u need to put '' around
id.
ur query should look like
mysql_query(DELETE FROM open_trades WHERE id= '.$id.');
Note that your can leave any space between and '
if u do have a space between them, ur query will look like
mysql_query(DELETE FROM
Hello sam,
Did you try:
while($row1=mysql_fetch_row($result1) AND $row2=mysql_fetch_row($result2)) ?
or this:
while(($row1=mysql_fetch_row($result1)) ($row2=mysql_fetch_row($result2)))
?
good luck!
P.S. These two actually work... i'm
I have to find a way to extract the text from a word doc. I came across
antiword, which is what most people seem to suggest, but i cant get it
to run on the documents correctly.
I have $path and $file variables, i just don't know how to get antiword
to run on the document.
shell_exec?
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PHP
How would you create a drop down menu from a database query? I have
figured how to do it with one field, but how could it be done with a
system where the value is different than the displayed value (ie.
numerical code as the value, name displayed)?
Thanks,
Cole
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hmm... what about something like this??
echo select name=\dropdown\;
$query = select code, name from table;
$result = mysql_query($query);
while($array = mysql_fetch_array($result))
{
echo option value=\.$array[code].\.$array[name]./option;
}
echo /select;
hth
- Original Message
Thanks. I think I can work from this. Just to let you know, it generates
a parse error ( I think its because of the quotes).
Cole
On Thu, 2004-06-17 at 18:09, Ng Hwee Hwee wrote:
hmm... what about something like this??
echo select name=\dropdown\;
$query = select code, name from table;
sorry, these codes are not tested... yes, i missed a quotation mark on the
first echo statement.
it should read:
echo select name=\dropdown\;
but i guess you can figure it out from these.. good luck! :o)
- Original Message -
From: Cole Ashcraft [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
I think this is the line which is the cause of your coding woes...
The quote () doesn't have any matching pair. There's one quote in
front, but there's none at the back.
echo select name=\dropdown\;
* *
- Original Message -
From: Cole Ashcraft [EMAIL
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