Balwantsingh wrote:
I am developing a page using PHP for entering the data into tables made in
mysql. I want that when user click on Reports button the data (which will
retrieve from mysql) should be shown in Spreadsheet (Calc) of Open Office.
Pls. tell how it can be done.
Does MySQL have a JDBC
function RemoveWhiteSpaces($str = '')
{
$search = array ('([\r\n])');
$replace = array (\n);
$str = preg_replace ($search, $replace, $str);
return $str;
}
Just a thought:
1. Read contents of the file (file() and implode() in php) so that the
contents are contained in an array
2.
use mysql_escape_string.
http://us3.php.net/manual/en/function.mysql-escape-string.php
Jon
Ron Piggott wrote:
I have begun to create a Christian Ministry Directory. It is on the
ministry web site I am building at
http://www.actsministries.org/ministrydirectory/ .
One of the problems I am now
Hi there,
I'm writing a script that'll enable me to ban certain IP-addresses from
a site, and i have a qouple of questions:
1. When inserting the IP into the database (probably MySQL), should
i use the dotted- or the long-type?
2. What is the best way to ban IP ranges?
--
On Mon, 2004-08-23 at 11:24, Daniel Schierbeck wrote:
Hi there,
I'm writing a script that'll enable me to ban certain IP-addresses from
a site, and i have a qouple of questions:
1.When inserting the IP into the database (probably MySQL), should
i use the dotted- or the
Hello,
Regarding this code:
[PHP code]
// This works
$name=name;
$table=mytable;
$mysql_connect(localhost,,) or die(Error: .mysql_error());
$mysql_select_db(mydb) or die(Error: .mysql_error());
$mysql_query(INSERT INTO $table (`id`,`name`) VALUES ('','$name'));
[/PHP code]
I want to
On Mon, 23 Aug 2004 17:06:40 -0700, Ben Galin [EMAIL PROTECTED] wrote:
Hello,
Regarding this code:
[PHP code]
// This works
$name=name;
$table=mytable;
$mysql_connect(localhost,,) or die(Error: .mysql_error());
$mysql_select_db(mydb) or die(Error: .mysql_error());
Ben Galin wrote:
I want to define() TABLE as a constant instead of using the variable $table
[PHP code]
// This runs without an error but does *not* insert a new row
$name=name;
define(TABLE, mytable);
$mysql_connect(localhost,,) or die(Error: .mysql_error());
$mysql_select_db(mydb) or
On Aug 23, 2004, at 8:12 PM, John Holmes wrote:
You can't have a constant in a string. You'd do it like this:
mysql_query(INSERT INTO . TABLE . (`id`,`name`) VALUES
('','$name'));
Thanks, John and Justin. Wasn't thinking about that.
The other error you have, and I don't know how you think this
Hi everyone.
I'm new to PHP. And so I'm so keen on finding people who are willing to share their
knowledge with me.
I've generated forms containing text boxes, check boxes, text areas, drop boxes, radio
buttons hidden fields as an HTML table with two columns, the first for the
desciption,
On Tuesday 24 August 2004 08:18, Ben Galin wrote:
You're right. It doesn't run. I retyped instead of copy-and-paste'd;
that's a typo.
Please, when you post code make sure they're verbatim by using copy paste.
That way people can focus on your actual problem rather than on your typos.
--
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