--- Jason Wong [EMAIL PROTECTED] wrote:
I'm not sure what you mean exactly by intended use
checkboxes.
Intended use - I generate a list (via a repeat region)
of records. Each item on the list has an associated
checkbox. If I put a check in the box, do a $_POST I
expect on the next page
On Monday 06 December 2004 20:39, Stuart Felenstein wrote:
--- Jason Wong [EMAIL PROTECTED] wrote:
I'm not sure what you mean exactly by intended use
checkboxes.
Intended use - I generate a list (via a repeat region)
of records. Each item on the list has an associated
checkbox. If I put
Hi guys,
I'm trying to get two columns of td/td to display side by side and
then go to a new row. I am using this code but nothing I seem to do is
working this far.
?php
for ($r=0;$products = db_fetch($productsQuery);$r++)
{
?
td align=centera href=?php echo $base_url; ?products/?php
echo
Thank you everyone who replied to my problem. I have decided now to go with
Anna's solution and so far it's working great!
So thank you very much for your help Anna.
Thanks again,
Andy.
-Original Message-
From: anna w [mailto:[EMAIL PROTECTED]
Sent: Wednesday, 01 December 2004 11:17
To:
Post your relevant code and lets have a look.
bastien
From: Steven \[Offstage\] [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Mozilla inserts twice, IE does OK... ?
Date: Sun, 5 Dec 2004 23:41:43 +0100 (CET)
Hi there,
First post to this mailing list, and I have a very strange problem:
Are you using view source a lot? (some of) Mozillas view source
commands send the query again, minus the POST vars. This could be the
behaviour you're seeing.
I say some of because there are multiple ways of viewing the source -
web developer toolbar's (extension) doesn't seem to suffer from
On Monday 06 December 2004 22:46, Norland, Martin wrote:
No, PHP5 does indeed have some new (and different) functions for mysql,
but it supports (properly, nothing old about it) the normal mysql
functions as well. The change for PHP5 is that it no longer enables
mysql functions by default
anyway mysql_connect() won't work in php5 - although I do believe it's
possible to compile in the 'old' mysql lib yourself.
No, PHP5 does indeed have some new (and different) functions for mysql,
but it supports (properly, nothing old about it) the normal mysql
functions as well. The change
try this
?php
for ($r=0;$products = db_fetch($productsQuery);$r++)
{
if (($r % 2) == 0)
{
echo /tr
tr valign=\top\;
}
echo td
Newer versions of php user $_POST and $_GET to access form variables...try
this
if([EMAIL PROTECTED]'start']) $start = 0;
bastien
From: Valerie [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] pagination
Date: Sun, 5 Dec 2004 10:19:03 -0500
It shows next and the first 10 records but
AFAIK no version of PHP ever did compile with mysql by default. You
*had* to
use --with-mysql if you wanted mysql support. The choice was whether
to use
the bundled library (the default if you didn't specify a directory
with
--with-mysql) or some other library.
snip
If this is where you
On Monday 06 December 2004 23:54, Norland, Martin wrote:
Sorry this got a little toasty, but it sure felt like a blind attack,
since the most cursory of checks revealed my statements true.
I'm sorry if you felt that that was an attack. Your honour, in my defence, I
confess that I haven't
I'm trying to send mail out based partially on a
recordset/binding.
The fields are available but I'm not sure if they need
to be turned into a variable first or if I can just
reference them in the body of the email.
Here is what I tried:
$to = $rsVendorJobs-Fields('Conmail');
$subject =
I prefer to assign the db values to loca variables to ensure that I am
sending out exactly what I need to.
Bastien
From: Stuart Felenstein [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] stumped-mail and database
Date: Mon, 6 Dec 2004 10:05:57 -0800 (PST)
I'm trying to send mail out
-Original Message-
From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
Here is what I tried:
$to = $rsVendorJobs-Fields('Conmail');
$subject = $rsVendorJobs-Fields('RefEm');
$body = '$cl';
$headers = From: [EMAIL PROTECTED];
mail($to,$subject,$body,$headers);
echo Mail sent to $to;
er, I don't know if it would interest you but here is a class I have
been using for ages now (not that I have trouble using mail() for simple
jobs) because its simple, packed with functionality and works well:
http://phpmailer.sourceforge.net/
the following page hopefully demonstrates how
--- Bastien Koert [EMAIL PROTECTED] wrote:
I prefer to assign the db values to loca variables
to ensure that I am
sending out exactly what I need to.
Well the binding is one where clause that pulls the
correct record for the transaction. Following what
you are saying, how does that
--- Norland, Martin [EMAIL PROTECTED]
wrote:
1) change
$to = $rsVendorJobs-Fields('Conmail');
To
$to = {$rsVendorJobs-Fields('Conmail')};
Or just
$to = $rsVendorJobs-Fields('Conmail');
2) change
$body = '$cl';
To
$body = $cl;
Well I'm sure this is not the
What is $rsVendorJobs, where is it populated? I assumed, from the way
you were using it - that it was a class object with a 'fields' function
that returns the value of a column when passed the column name. Which,
looking back, seems pretty excessively abstracted :)
Is $rsVendorJobs just the
--- Norland, Martin [EMAIL PROTECTED]
wrote:
What is $rsVendorJobs
It's a recordset which for lack of a better
definition is a sql query.
Is $rsVendorJobs just the result of a mysql_query()?
If so, you probably
just want to be using:
$to = $rsVendorJobs['Conmail'];
Nope, though it
All I can recommend from here is heavy use of printr() or var_dump() on
your variables.
$totalRows_rsVendorJobs = $rsVendorJobs-RecordCount(); // end
Recordset
This clearly means $rsVendorJobs is an object of some sort, probably
some custom recordset object as you've said - so your best bet is
--- Norland, Martin [EMAIL PROTECTED]
wrote:
All I can recommend from here is heavy use of
printr() or var_dump() on
your variables.
They are NULL. That is the problem. I can't for the
life of me , figure out a way to initialize these
variables.
Obviously, also, you'll want to print
-Original Message-
From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
They are NULL. That is the problem. I can't for the life of me ,
figure out a way to
initialize these variables.
(Bear with me on this, because I've got nothing remaining to go on...)
What do you get from:
Stuart Felenstein wrote:
--- Norland, Martin [EMAIL PROTECTED]
wrote:
All I can recommend from here is heavy use of
printr() or var_dump() on
your variables.
They are NULL. That is the problem. I can't for the
life of me , figure out a way to initialize these
variables.
be more specific - its
--- Norland, Martin [EMAIL PROTECTED]
wrote:
(Bear with me on this, because I've got nothing
remaining to go on...)
What do you get from:
var_dump($query_rsVendorJobs);
var_dump($totalRows_rsVendorJobs);
var_dump($-SelectLimit($query_rsVendorJobs));
var_dump($rsVendorJobs);
object(kt_adorecordset_mysql)(33) { [dataProvider]=
Looks like you're using the ADODB library (
http://www.certicamara.com/consulta/lib/adodb/docs-adodb.htm ) or
similar. ( That may not be the official site, I just bounced around a
bit. )
All your previous code
I just thought, if your query object ($) is returning a
resultset object then maybe you have to 'loop' the resultset object
in order to retrieve the 'row' object(s) from which you can retrieve the
data.
your resultset object doesn't have a GetRowAssoc() method?
[ defined as
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