--- Jason Wong [EMAIL PROTECTED] wrote:
What happens when you do this:
$to = $rsVendorJobs-fields('Conmail');
echo $to;
echo $rsVendorJobs-fields('Conmail');
$to = $rsVendorJobs-fields('Conmail');
echo $to;
Same thing: Call to a member function on a non-object
in..
Stuart
--
PHP
On Tuesday 07 December 2004 19:15, Stuart Felenstein wrote:
--- Jason Wong [EMAIL PROTECTED] wrote:
Please be explicit, do you mean this what you get?:
What happens when you do this:
$to = $rsVendorJobs-fields('Conmail');
Call to a member function on a non-object
echo $to;
Nothing, as
--- Jason Wong [EMAIL PROTECTED] wrote:
Also just to be certain that you *are* running those
lines of code change the
echo $to, to echo Before $to echo After $to or
something.
Well now I feel like a damn jackass. I just
discovered something that doesnt fix the issue, yet
reveals the
I have Windows 2000 on my system. I have installed Apache 2 and it seems to
work fine, when I test it, it goes to the 'localhost' dir.
PHP is the problem, I have tried about 5 different websites's installation
manuals to no avail. I have tried to do a manual installation
I have downloaded
I'm not using the browsers 'view source' at all... Only the 'view source'
function from PHP.
But when none of the source is checked, and even right after a restart of
MySQL and Apache, the dual insert resists...
Funny thing is, I've had this problem in another section of the site, and it
Well for one thing, you're telling it to use the module, and then you're also
telling it to use php.exe to parse the files, which is CGI. So that won't
work. Pick one or the other. Here's the instructions:
http://www.php.net/manual/en/install.windows.apache2.php
Pick install as a module, or
