Hi,
how can I put the content of a databasefield into a array.
I need this to put out a securetyimage for validation.
Regards,
Ruprecht
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Hi,
2006/2/7, Ruprecht Helms [EMAIL PROTECTED]:
Hi,
how can I put the content of a databasefield into a array.
It depends on what kind of database server you are using. If you are
using MySQL you will need http://www.php.net/mysql . It is a good
starting point.
BTW you may want to take a look
Hi all,
I have an elusive problem with PHP and ODBC.
I want to use ODBC to contact a MSSQL server on an NT box, from a linux
machine.
FreeTDS driver, no problem
unixODBC, no problem
I can contact the correct database on the NT box through isql and tsql, no
problem
I can make a command-line
$newdata = $contents[0];
for ( $i = 1; $i count($array); $i++ ) {
$current = $array[$i];
$structure[$i]['name'] = substr($current, 55, strlen($current) - 0);
}
Should the array loop thru start at 0 (below)? Not 1 as you have the
starting value for $i (above)
$newdata =
I didn't read all your code, but this jumped out to me also as to Bastien
for ( $i = 1; $i count($array); $i++ ) {
If you have 1 file, then you probably have 1 1 which does not execute
even once. I definitely suggest also $i = 0;
-Dwight
-Original Message-
From: Chris Payne
