Hi ya'll,
I am lost as to why I am getting this error in my script. Can anyone kindly
explain why this is so.
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
resource in /home/cm/public_html/cell/login.php
Hey thanks guys, the email was the problem
I had emial instead of email
Thanks for the assistance.
-Original Message-
From: Peter Lovatt [mailto:[EMAIL PROTECTED]
Sent: Tuesday, January 18, 2005 1:45 AM
To: Earl Clare; php-db@lists.php.net
Subject: RE: [PHP-DB] i am lost (php warning
hi everyone,
I am new to all php and mySQL.
What i am trying to do is to obtain information from the db using 3 conditions.
this is what i've got
$sql_num = mysql_query("SELECT * FROM siteinfo WHERE dive_operator = '1' AND status =
'1'",$db) or die (mysql_error());
the 3 conditions i need is
hey guys,
I need some assistance here...
I am toying with a search form that will allow the user to select 3 options from a set
of checkboxes to search by (eg.)
[[ Select any 3 type ]]
[ ] option1 [ ] option2 [ ] option3
[ ] option4 [ ] option5 [ ] option6
[ ] option7 [ ] option8 [