The following query returns all 8 prayer request categories with the total #
of requests every submitted to each category:
SELECT `prayer_request_category`.`reference` ,
`prayer_request_category`.`category` , COUNT(
`prayer_requests`.`reference` ) AS category_request_count
FROM
Dear Ron
Take your condition to ON cluause. So your on clause (for LEFT JOIN) would
read something like
ON `prayer_request_category`.`
reference` = `prayer_requests`.`prayer_request_category_reference`
AND
`prayer_requests`.`approval_
level` IN ( 1, 3 )
`prayer_requests`.`prayer_request_type` =
thank you for explaining this to me Amit. It works. Ron
The Verse of the Day
“Encouragement from God’s Word”
http://www.TheVerseOfTheDay.info
From: Amit Tandon
Sent: Friday, May 06, 2011 5:49 AM
To: Ron Piggott
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] COUNT and OUTER JOIN results
I am making a Bible concordance. I need help with the query that figures
out how many times each word is in the Bible.
The COUNT() in the query below is giving me the total number of words for
the letter of the alphabet, not the specific word, and is causing there to
be only 1 search result.
I
On 13 August 2010 13:43, Ron Piggott ron.pigg...@actsministries.org wrote:
SELECT `bible_concordance_words`.`reference`,
`bible_concordance_words`.`word`,
COUNT(`bible_concordance_word_reference`.`bible_concordance_words_reference`)
AS occurrences FROM `bible_concordance_words` INNER JOIN
Hi all
I am 99.9% sure it is my lack of understanding something, but it sure
seems like my PHP/MySQL code is returning something other than what i
expect from reading the docs.
to explain:
this code is serving me (almost perfectly) well:
Thanks for your help, Chris. You certainly got me going in the right
direction. In case anyone is interested, below is the completed
solution, with design elements, turned into a function so I can
easily call it several times.
function counter_maker ($database,$name,$link)
{
Thanks in advance for your help, and forgive me if this is me being
bone-headed. :-)
The following code works and accomplishes what I need it to do, but I
am wondering if there is a better way to accomplish the same task. I
have several tables of records and I need to count and then
Kevin Murphy asks:
The following code works and accomplishes what I need it to do, but I
am wondering if there is a better way to accomplish the same task. I
have several tables of records and I need to count and then display.
Even if I could just combine the first three queries (below) into
Actually the design is in the code below I need to display the
counts from all of those queries in a grid. Basically, its just a
summary of a bunch of information. Another way to look at it would be
a several lines that say something like this:
You have $data1_count NEW records in
I am making a PHP/MySQL traffic report page from a table that records some user
activity using PHP referrer information.
I have a table with three rows: IP, page_name, and timestamp. The IP row records the
user's IP address, page_name records the name of the page that the user loaded, and
the
)
) AS unik_visits
FROM T
LEFT JOIN U
ONU.ip = T.ip
AND U.rank = T.rank + 1
GROUP BY ip
HTH
Ignatius
_
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, June 08, 2004 5:03 PM
Subject: [PHP-DB] Count unique
Hi all,
I'm baffled by this. I've put together a rather simple newsletter +
greeting card app for a company to send their clients personalized
corporate e-mails each containing the URL link to the greeting card page.
When the user successfully visits the view card page, my code writes the
visit
On Mon, Dec 22, 2003 at 11:43:35AM +0900, Lew Mark-Andrews wrote:
Table structure for cardlist:
`visitdate` datetime default NULL,
$sql = SELECT COUNT(visitdate) FROM cardlist GROUP BY visitdate;
$visitcount = mysql_num_rows($query);
echo pTotal number of visits: $visitcount/pbr; // ---
Lew Mark-Andrews wrote:
I get a count of 1 for the number of visits
($visitcount) using my following code. It should be 0.
---
snipped code in check_visits.php
$sql = SELECT COUNT(visitdate) FROM cardlist GROUP BY visitdate;
$query = mysql_query($sql) or die(brbrdiv
John,
That's because you're displaying how many rows were returned from the
query, not the value that COUNT() returns. A query with COUNT() is
always going to return at least one row.
$visitcount = mysql_result($query,0);
Yes, that was it! Thank you so much.
Lew
--
PHP Database Mailing List
Hi all. I was wanting to make a page that takes a set date and
counts down to zero displaying days, minutes, and seconds. Basically, I
want it to count down from the current date and time until a future date
and time is reached (ie. Sept. 30th is x days, y minutes, and z seconds
away
On Mon, 22 Sep 2003, Frank McIsaac wrote:
Hi all. I was wanting to make a page that takes a set date and
counts down to zero displaying days, minutes, and seconds. Basically, I
want it to count down from the current date and time until a future date
and time is reached (ie. Sept.
On Mon, 22 Sep 2003, Peter Beckman wrote:
On Mon, 22 Sep 2003, Frank McIsaac wrote:
Hi all. I was wanting to make a page that takes a set date and
counts down to zero displaying days, minutes, and seconds. Basically, I
want it to count down from the current date and time until a
Hi,
Is it possible to combine the COUNT AVG functions using MySQL? I have a
table called Bookings and I need to find out the average number of bookings.
So I need to count the number of bookings in the table and then get the
Average, is this possible?
Thanks for your help
--
PHP Database
Hi everybody,
I've got a little problem, which I can't solve. It is as follow:
In my database I made a table with different fields.
One of the fields is named 'bedrag' and contains a numeric value like 15.47 or 78.16
and so on.
If I want a value of the table I use in most cases the following
out of your result set. It's a common
mistake. :)
Edward Dudlik
Becoming Digital
www.becomingdigital.com
- Original Message -
From: Robert Wanadoo [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, 09 June, 2003 11:40
Subject: [PHP-DB] Count database-values
Hi everybody,
I've got
- Original Message -
From: Becoming Digital [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, 10 June, 2003 06:43
Subject: Re: [PHP-DB] Count database-values
So far no problems, but I want to count all these values.
I tried with SUM but with the following code it doesn't work
-
From: Becoming Digital [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, 10 June, 2003 06:43
Subject: Re: [PHP-DB] Count database-values
So far no problems, but I want to count all these values.
I tried with SUM but with the following code it doesn't work:
$squery
Digital' [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Tuesday, 10 June, 2003 11:54
Subject: RE: [PHP-DB] Count database-values
-Original Message-
From: Becoming Digital [mailto:[EMAIL PROTECTED]
Sent: 10 June 2003 12:15
I screwed up my own code. Silly me. It should read:
Surely your
instead
of the column name as the documentation recommends, the performance should
be just fine.
Hope this helps.
Rich
-Original Message-
From: Becoming Digital [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 10, 2003 12:50 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Count database
]; [EMAIL PROTECTED]
Sent: Tuesday, 10 June, 2003 13:14
Subject: RE: [PHP-DB] Count database-values
Edward,
Have you considered trying mysql_result()?
It appears that your query is going to always return a single piece of data:
Total. So you essentially have an array with only a single element. If you
Hi all,
I have this table which stores products and quantities ordered by
customers, and for billing purposes, I need to fetch not only how many
products but also how many where ordered for each one but not detailed,
but as one big result, so later I can charge for individual gift
packages and
hello, um using this SQL string :
SELECT computer, date, closedate,UNIX_TIMESTAMP(closedate),
UNIX_TIMESTAMP(date), (UNIX_TIMESTAMP(closedate) -
UNIX_TIMESTAMP(date)) / POW(60,2) FROM tracking (18 Records)
computer date closedate UNIX_TIMESTAMP(closedate)
Hi All
I have added a row to my table which inputs which admin user has amended
a record in a table on my db.
I have this working but what I would like to do is count how many
instances of the admin id I have stored.
So if my list looks like this..
Admin_id
1
2
2
2
3
3
3
3
.
248.474.7200 x 183
248.474.8500 (fax)
www.strtrade.com
-Original Message-
From: Dave Carrera [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, May 01, 2002 8:03 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Count and group ?
Hi All
I have added a row to my table which inputs which admin user
Carrera [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 01, 2002 1:02 PM
Subject: [PHP-DB] Count and group ?
Hi All
I have added a row to my table which inputs which admin user has amended
a record in a table on my db.
I have this working but what I would like to do is count how
Subject: RE: [PHP-DB] count
Something like this
Select sum(ID) name from $table;
Where name is some name that I come up with?
Ronald L. Allen (MCSE NT, MCP, CCNA)
SR. LAN/WAN Administrator
SFOR - Hungary, Croatia
[EMAIL PROTECTED]
[EMAIL PROTECTED]
+36-82-50 ext. 22580
DSN: 760
On Sunday 10 February 2002 00:55, Barry Rumsey wrote:
I have the following code:
$query = SELECT * FROM artist WHERE artist LIKE 'b%' ORDER BY artist
ASC;
[snip]
What I would like to know is how do I do a count on each result
returned.e.g. Benny(4) , Bill(10)
Try:
$query = SELECT artist,
How do you add a count feature to a link. I can get stuff from the db but want to know
how many times it's been read or click on?
Afterthought -- you could make this self-maintaining by doing a select for
$PHP_SELF and inserting the record if mysql_num_rows() returned 0. Downside
is that it would add greatly to the overhead.
Miles
At 04:42 PM 1/16/2002 -0400, Miles Thompson wrote:
Barry,
Before leaping to the wrong
I'm trying to do the following query:
$db_connect = mysql_connect($sqlhostname,$login,$password);
$base_selection = mysql_select_db($base,$db_connect);
$query = SELECT DISTINCT * FROM xp_topics WHERE artist_count='artist' AND topictext
LIKE
'A%' ORDER BY artist_count ASC limit 0,5;
Barry,
I can't see where you've created $topictest.
Maybe, just before you define $queyr2, you should have the line
$topictest = $row[ topcitext];
I also think xp_stories_topicid should be xp_stories.topicid
Try echo 'ing $query2 and see what is printed.
Hope this helps, and that I've not
Is it posible to do a count(*) on a tabe where id=2 and count just those that id = 2
Barry,
Is it posible to do a count(*) on a tabe where id=2 and count just those that id = 2
=why don't you try it?
The answer is yes, because count(*) means count the entire number of non-null rows
selected.
See manual: 3.3.4.8 Counting Rows
=dn
--
PHP Database Mailing List
Hi,
SELECT SUM(IF(id = '2',1,0)) AS field_name FROM table
Versatile command - you can use it for quite a lot of things.
Barry Rumsey wrote:
Is it posible to do a count(*) on a tabe where id=2 and count just those that id =
2
--
--
Dan Barton
Terrestrial Program Biologist
Asst.
Ok i think i need to expand my help request... my fault
I have a db that uses ids for topics in a message board ie each topic has
messages of various numbers in them.
From my select a topic page i hope to put the number of messages in the
topic, so it visually looks like this sort of...
Message-
From: DC [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 30, 2001 9:53 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] count function?
Ok i think i need to expand my help request... my fault
I have a db that uses ids for topics in a message board ie each topic has
messages of various
30, 2001 9:53 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] count function?
Ok i think i need to expand my help request... my fault
I have a db that uses ids for topics in a message board ie each topic has
messages of various numbers in them.
From my select a topic page i hope t
At 10:06 AM 3/30/01 -0800, Larry Rivera wrote:
I think you have to run multiple queries, ie run some loop after finding out
what topics you wil count from e==
run a select distinct to get the topics
run a while or for loop then run queries again like count(*) where
topic='$topic'
Better yet
Cheers Brian
Thats sounds more like i am looking for
Although i have put the other code examples offered for this prob in my code
folder for later cause you never now when you'll need them.
Cheers
Dave C
""Brian S. Dunworth"" [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL
What is retrieved if you do a Select Count(*) from myDb where
condition = parameters?
Seems your result set should contain this value...
Phil J.
DC wrote:
Hi All
I cant quite work out how to count the number of rows in my mysql db that
match a certain critieria and the show that number
if you just need the number
SELECT COUNT(*) FROM table where
At 06:34 PM 3/30/2001 +0100, DC wrote:
Hi All
I cant quite work out how to count the number of rows in my mysql db that
match a certain critieria and the show that number numericaly in my pages.
Checked books,
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