, SCOTT V (SBCSI)
Subject: RE: [PHP-DB] Easy array question...
It's actually putting the whole of the array $other as the first element of
the array $other2. You're going to have to step through the array to copy
it.
foreach($other as $element) {
$other2[] = $element;
} //e
tly, from this code the output I am
actually
getting is:
Array
Thanks again.
-Original Message-
From: Jonathan Villa [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 10:58 AM
To: [EMAIL PROTECTED]; NIPP, SCOTT V (SBCSI); 'Hutchins, Richard';
[EMAIL PROTECTED]
Subj
ually
getting is:
Array
Thanks again.
-Original Message-
From: Jonathan Villa [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 10:58 AM
To: [EMAIL PROTECTED]; NIPP, SCOTT V (SBCSI); 'Hutchins, Richard';
[EMAIL PROTECTED]
Subject: RE: [PHP-DB] Easy array questio
SCOTT V (SBCSI)'; 'Hutchins, Richard'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Easy array question...
$array_copy = array();
array_push($array_copy, $_SESSION['original_array']);
echo $array_copy[0];//or whatever to test
---> Jonathan
-Original Mes
Richard'; '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Easy array question...
I don't think that is the case because I am able to access the
original array in this same page without having to use the session
variable
reference. Won't hurt to give it a try thoug
PROTECTED]
Sent: Wednesday, March 12, 2003 10:40 AM
To: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Easy array question...
Are you using:
$array2 = $_SESSION["array1"];
Not sure that will do the trick, but it was my first inclination.
Rich
> -Original Message-
>
TECTED]'
> Subject: [PHP-DB] Easy array question...
>
>
> I create an array on one page and then process it on
> the next page
> as I have registered the array as a session variable. I need
> to basically
> process one of these arrays twice, so I want to make a
I create an array on one page and then process it on the next page
as I have registered the array as a session variable. I need to basically
process one of these arrays twice, so I want to make a copy of the array.
The question is how do I do this? I have tried the following:
$array2 = $
